4.49/2.16 WORST_CASE(NON_POLY, ?) 4.49/2.16 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 4.49/2.16 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.49/2.16 4.49/2.16 4.49/2.16 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 4.49/2.16 4.49/2.16 (0) CpxTRS 4.49/2.16 (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] 4.49/2.16 (2) TRS for Loop Detection 4.49/2.16 (3) DecreasingLoopProof [LOWER BOUND(ID), 0 ms] 4.49/2.16 (4) BEST 4.49/2.16 (5) proven lower bound 4.49/2.16 (6) LowerBoundPropagationProof [FINISHED, 0 ms] 4.49/2.16 (7) BOUNDS(n^1, INF) 4.49/2.16 (8) TRS for Loop Detection 4.49/2.16 (9) InfiniteLowerBoundProof [FINISHED, 156 ms] 4.49/2.16 (10) BOUNDS(INF, INF) 4.49/2.16 4.49/2.16 4.49/2.16 ---------------------------------------- 4.49/2.16 4.49/2.16 (0) 4.49/2.16 Obligation: 4.49/2.16 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 4.49/2.16 4.49/2.16 4.49/2.16 The TRS R consists of the following rules: 4.49/2.16 4.49/2.16 f(h(x), y) -> h(f(y, f(x, h(f(a, a))))) 4.49/2.16 4.49/2.16 S is empty. 4.49/2.16 Rewrite Strategy: FULL 4.49/2.16 ---------------------------------------- 4.49/2.16 4.49/2.16 (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) 4.49/2.16 Transformed a relative TRS into a decreasing-loop problem. 4.49/2.16 ---------------------------------------- 4.49/2.16 4.49/2.16 (2) 4.49/2.16 Obligation: 4.49/2.16 Analyzing the following TRS for decreasing loops: 4.49/2.16 4.49/2.16 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 4.49/2.16 4.49/2.16 4.49/2.16 The TRS R consists of the following rules: 4.49/2.16 4.49/2.16 f(h(x), y) -> h(f(y, f(x, h(f(a, a))))) 4.49/2.16 4.49/2.16 S is empty. 4.49/2.16 Rewrite Strategy: FULL 4.49/2.16 ---------------------------------------- 4.49/2.16 4.49/2.16 (3) DecreasingLoopProof (LOWER BOUND(ID)) 4.49/2.16 The following loop(s) give(s) rise to the lower bound Omega(n^1): 4.49/2.16 4.49/2.16 The rewrite sequence 4.49/2.16 4.49/2.16 f(h(x), y) ->^+ h(f(y, f(x, h(f(a, a))))) 4.49/2.16 4.49/2.16 gives rise to a decreasing loop by considering the right hand sides subterm at position [0,1]. 4.49/2.16 4.49/2.16 The pumping substitution is [x / h(x)]. 4.49/2.16 4.49/2.16 The result substitution is [y / h(f(a, a))]. 4.49/2.16 4.49/2.16 4.49/2.16 4.49/2.16 4.49/2.16 ---------------------------------------- 4.49/2.16 4.49/2.16 (4) 4.49/2.16 Complex Obligation (BEST) 4.49/2.16 4.49/2.16 ---------------------------------------- 4.49/2.16 4.49/2.16 (5) 4.49/2.16 Obligation: 4.49/2.16 Proved the lower bound n^1 for the following obligation: 4.49/2.16 4.49/2.16 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 4.49/2.16 4.49/2.16 4.49/2.16 The TRS R consists of the following rules: 4.49/2.16 4.49/2.16 f(h(x), y) -> h(f(y, f(x, h(f(a, a))))) 4.49/2.16 4.49/2.16 S is empty. 4.49/2.16 Rewrite Strategy: FULL 4.49/2.16 ---------------------------------------- 4.49/2.16 4.49/2.16 (6) LowerBoundPropagationProof (FINISHED) 4.49/2.16 Propagated lower bound. 4.49/2.16 ---------------------------------------- 4.49/2.16 4.49/2.16 (7) 4.49/2.16 BOUNDS(n^1, INF) 4.49/2.16 4.49/2.16 ---------------------------------------- 4.49/2.16 4.49/2.16 (8) 4.49/2.16 Obligation: 4.49/2.16 Analyzing the following TRS for decreasing loops: 4.49/2.16 4.49/2.16 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 4.49/2.16 4.49/2.16 4.49/2.16 The TRS R consists of the following rules: 4.49/2.16 4.49/2.16 f(h(x), y) -> h(f(y, f(x, h(f(a, a))))) 4.49/2.16 4.49/2.16 S is empty. 4.49/2.16 Rewrite Strategy: FULL 4.49/2.16 ---------------------------------------- 4.49/2.16 4.49/2.16 (9) InfiniteLowerBoundProof (FINISHED) 4.49/2.16 The following loop proves infinite runtime complexity: 4.49/2.16 4.49/2.16 The rewrite sequence 4.49/2.16 4.49/2.16 f(h(h(x1_0)), h(h(x1_2))) ->^+ h(h(f(h(h(f(f(x1_0, h(f(a, a))), f(f(a, a), h(f(a, a)))))), h(h(f(f(x1_2, h(f(a, a))), f(f(a, a), h(f(a, a))))))))) 4.49/2.16 4.49/2.16 gives rise to a decreasing loop by considering the right hand sides subterm at position [0,0]. 4.49/2.16 4.49/2.16 The pumping substitution is [ ]. 4.49/2.16 4.49/2.16 The result substitution is [x1_0 / f(f(x1_0, h(f(a, a))), f(f(a, a), h(f(a, a)))), x1_2 / f(f(x1_2, h(f(a, a))), f(f(a, a), h(f(a, a))))]. 4.49/2.16 4.49/2.16 4.49/2.16 4.49/2.16 4.49/2.16 ---------------------------------------- 4.49/2.16 4.49/2.16 (10) 4.49/2.16 BOUNDS(INF, INF) 4.49/2.20 EOF