3.28/1.62 WORST_CASE(NON_POLY, ?) 3.28/1.62 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 3.28/1.62 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.28/1.62 3.28/1.62 3.28/1.62 The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.28/1.62 3.28/1.62 (0) CpxTRS 3.28/1.62 (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] 3.28/1.62 (2) TRS for Loop Detection 3.28/1.62 (3) DecreasingLoopProof [LOWER BOUND(ID), 0 ms] 3.28/1.62 (4) BEST 3.28/1.62 (5) proven lower bound 3.28/1.62 (6) LowerBoundPropagationProof [FINISHED, 0 ms] 3.28/1.62 (7) BOUNDS(n^1, INF) 3.28/1.62 (8) TRS for Loop Detection 3.28/1.62 (9) InfiniteLowerBoundProof [FINISHED, 0 ms] 3.28/1.62 (10) BOUNDS(INF, INF) 3.28/1.62 3.28/1.62 3.28/1.62 ---------------------------------------- 3.28/1.62 3.28/1.62 (0) 3.28/1.62 Obligation: 3.28/1.62 The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.28/1.62 3.28/1.62 3.28/1.62 The TRS R consists of the following rules: 3.28/1.62 3.28/1.62 zeros -> cons(0, n__zeros) 3.28/1.62 and(tt, X) -> activate(X) 3.28/1.62 length(nil) -> 0 3.28/1.62 length(cons(N, L)) -> s(length(activate(L))) 3.28/1.62 zeros -> n__zeros 3.28/1.62 activate(n__zeros) -> zeros 3.28/1.62 activate(X) -> X 3.28/1.62 3.28/1.62 S is empty. 3.28/1.62 Rewrite Strategy: INNERMOST 3.28/1.62 ---------------------------------------- 3.28/1.62 3.28/1.62 (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) 3.28/1.62 Transformed a relative TRS into a decreasing-loop problem. 3.28/1.62 ---------------------------------------- 3.28/1.62 3.28/1.62 (2) 3.28/1.62 Obligation: 3.28/1.62 Analyzing the following TRS for decreasing loops: 3.28/1.62 3.28/1.62 The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.28/1.62 3.28/1.62 3.28/1.62 The TRS R consists of the following rules: 3.28/1.62 3.28/1.62 zeros -> cons(0, n__zeros) 3.28/1.62 and(tt, X) -> activate(X) 3.28/1.62 length(nil) -> 0 3.28/1.62 length(cons(N, L)) -> s(length(activate(L))) 3.28/1.62 zeros -> n__zeros 3.28/1.62 activate(n__zeros) -> zeros 3.28/1.62 activate(X) -> X 3.28/1.62 3.28/1.62 S is empty. 3.28/1.62 Rewrite Strategy: INNERMOST 3.28/1.62 ---------------------------------------- 3.28/1.62 3.28/1.62 (3) DecreasingLoopProof (LOWER BOUND(ID)) 3.28/1.62 The following loop(s) give(s) rise to the lower bound Omega(n^1): 3.28/1.62 3.28/1.62 The rewrite sequence 3.28/1.62 3.28/1.62 length(cons(N, L)) ->^+ s(length(L)) 3.28/1.62 3.28/1.62 gives rise to a decreasing loop by considering the right hand sides subterm at position [0]. 3.28/1.62 3.28/1.62 The pumping substitution is [L / cons(N, L)]. 3.28/1.62 3.28/1.62 The result substitution is [ ]. 3.28/1.62 3.28/1.62 3.28/1.62 3.28/1.62 3.28/1.62 ---------------------------------------- 3.28/1.62 3.28/1.62 (4) 3.28/1.62 Complex Obligation (BEST) 3.28/1.62 3.28/1.62 ---------------------------------------- 3.28/1.62 3.28/1.62 (5) 3.28/1.62 Obligation: 3.28/1.62 Proved the lower bound n^1 for the following obligation: 3.28/1.62 3.28/1.62 The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.28/1.62 3.28/1.62 3.28/1.62 The TRS R consists of the following rules: 3.28/1.62 3.28/1.62 zeros -> cons(0, n__zeros) 3.28/1.62 and(tt, X) -> activate(X) 3.28/1.62 length(nil) -> 0 3.28/1.62 length(cons(N, L)) -> s(length(activate(L))) 3.28/1.62 zeros -> n__zeros 3.28/1.62 activate(n__zeros) -> zeros 3.28/1.62 activate(X) -> X 3.28/1.62 3.28/1.62 S is empty. 3.28/1.62 Rewrite Strategy: INNERMOST 3.28/1.62 ---------------------------------------- 3.28/1.62 3.28/1.62 (6) LowerBoundPropagationProof (FINISHED) 3.28/1.62 Propagated lower bound. 3.28/1.62 ---------------------------------------- 3.28/1.62 3.28/1.62 (7) 3.28/1.62 BOUNDS(n^1, INF) 3.28/1.62 3.28/1.62 ---------------------------------------- 3.28/1.62 3.28/1.62 (8) 3.28/1.62 Obligation: 3.28/1.62 Analyzing the following TRS for decreasing loops: 3.28/1.62 3.28/1.62 The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.28/1.62 3.28/1.62 3.28/1.62 The TRS R consists of the following rules: 3.28/1.62 3.28/1.62 zeros -> cons(0, n__zeros) 3.28/1.62 and(tt, X) -> activate(X) 3.28/1.62 length(nil) -> 0 3.28/1.62 length(cons(N, L)) -> s(length(activate(L))) 3.28/1.62 zeros -> n__zeros 3.28/1.62 activate(n__zeros) -> zeros 3.28/1.62 activate(X) -> X 3.28/1.62 3.28/1.62 S is empty. 3.28/1.62 Rewrite Strategy: INNERMOST 3.28/1.62 ---------------------------------------- 3.28/1.62 3.28/1.62 (9) InfiniteLowerBoundProof (FINISHED) 3.28/1.62 The following loop proves infinite runtime complexity: 3.28/1.62 3.28/1.62 The rewrite sequence 3.28/1.62 3.28/1.62 length(cons(N, n__zeros)) ->^+ s(length(cons(0, n__zeros))) 3.28/1.62 3.28/1.62 gives rise to a decreasing loop by considering the right hand sides subterm at position [0]. 3.28/1.62 3.28/1.62 The pumping substitution is [ ]. 3.28/1.62 3.28/1.62 The result substitution is [N / 0]. 3.28/1.62 3.28/1.62 3.28/1.62 3.28/1.62 3.28/1.62 ---------------------------------------- 3.28/1.62 3.28/1.62 (10) 3.28/1.62 BOUNDS(INF, INF) 3.28/1.65 EOF