3.69/1.67 WORST_CASE(NON_POLY, ?) 3.69/1.68 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 3.69/1.68 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.69/1.68 3.69/1.68 3.69/1.68 The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.69/1.68 3.69/1.68 (0) CpxTRS 3.69/1.68 (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] 3.69/1.68 (2) TRS for Loop Detection 3.69/1.68 (3) DecreasingLoopProof [LOWER BOUND(ID), 25 ms] 3.69/1.68 (4) BEST 3.69/1.68 (5) proven lower bound 3.69/1.68 (6) LowerBoundPropagationProof [FINISHED, 0 ms] 3.69/1.68 (7) BOUNDS(n^1, INF) 3.69/1.68 (8) TRS for Loop Detection 3.69/1.68 (9) InfiniteLowerBoundProof [FINISHED, 0 ms] 3.69/1.68 (10) BOUNDS(INF, INF) 3.69/1.68 3.69/1.68 3.69/1.68 ---------------------------------------- 3.69/1.68 3.69/1.68 (0) 3.69/1.68 Obligation: 3.69/1.68 The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.69/1.68 3.69/1.68 3.69/1.68 The TRS R consists of the following rules: 3.69/1.68 3.69/1.68 zeros -> cons(0, n__zeros) 3.69/1.68 and(tt, X) -> activate(X) 3.69/1.68 length(nil) -> 0 3.69/1.68 length(cons(N, L)) -> s(length(activate(L))) 3.69/1.68 take(0, IL) -> nil 3.69/1.68 take(s(M), cons(N, IL)) -> cons(N, n__take(M, activate(IL))) 3.69/1.68 zeros -> n__zeros 3.69/1.68 take(X1, X2) -> n__take(X1, X2) 3.69/1.68 activate(n__zeros) -> zeros 3.69/1.68 activate(n__take(X1, X2)) -> take(X1, X2) 3.69/1.68 activate(X) -> X 3.69/1.68 3.69/1.68 S is empty. 3.69/1.68 Rewrite Strategy: INNERMOST 3.69/1.68 ---------------------------------------- 3.69/1.68 3.69/1.68 (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) 3.69/1.68 Transformed a relative TRS into a decreasing-loop problem. 3.69/1.68 ---------------------------------------- 3.69/1.68 3.69/1.68 (2) 3.69/1.68 Obligation: 3.69/1.68 Analyzing the following TRS for decreasing loops: 3.69/1.68 3.69/1.68 The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.69/1.68 3.69/1.68 3.69/1.68 The TRS R consists of the following rules: 3.69/1.68 3.69/1.68 zeros -> cons(0, n__zeros) 3.69/1.68 and(tt, X) -> activate(X) 3.69/1.68 length(nil) -> 0 3.69/1.68 length(cons(N, L)) -> s(length(activate(L))) 3.69/1.68 take(0, IL) -> nil 3.69/1.68 take(s(M), cons(N, IL)) -> cons(N, n__take(M, activate(IL))) 3.69/1.68 zeros -> n__zeros 3.69/1.68 take(X1, X2) -> n__take(X1, X2) 3.69/1.68 activate(n__zeros) -> zeros 3.69/1.68 activate(n__take(X1, X2)) -> take(X1, X2) 3.69/1.68 activate(X) -> X 3.69/1.68 3.69/1.68 S is empty. 3.69/1.68 Rewrite Strategy: INNERMOST 3.69/1.68 ---------------------------------------- 3.69/1.68 3.69/1.68 (3) DecreasingLoopProof (LOWER BOUND(ID)) 3.69/1.68 The following loop(s) give(s) rise to the lower bound Omega(n^1): 3.69/1.68 3.69/1.68 The rewrite sequence 3.69/1.68 3.69/1.68 length(cons(N, L)) ->^+ s(length(L)) 3.69/1.68 3.69/1.68 gives rise to a decreasing loop by considering the right hand sides subterm at position [0]. 3.69/1.68 3.69/1.68 The pumping substitution is [L / cons(N, L)]. 3.69/1.68 3.69/1.68 The result substitution is [ ]. 3.69/1.68 3.69/1.68 3.69/1.68 3.69/1.68 3.69/1.68 ---------------------------------------- 3.69/1.68 3.69/1.68 (4) 3.69/1.68 Complex Obligation (BEST) 3.69/1.68 3.69/1.68 ---------------------------------------- 3.69/1.68 3.69/1.68 (5) 3.69/1.68 Obligation: 3.69/1.68 Proved the lower bound n^1 for the following obligation: 3.69/1.68 3.69/1.68 The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.69/1.68 3.69/1.68 3.69/1.68 The TRS R consists of the following rules: 3.69/1.68 3.69/1.68 zeros -> cons(0, n__zeros) 3.69/1.68 and(tt, X) -> activate(X) 3.69/1.68 length(nil) -> 0 3.69/1.68 length(cons(N, L)) -> s(length(activate(L))) 3.69/1.68 take(0, IL) -> nil 3.69/1.68 take(s(M), cons(N, IL)) -> cons(N, n__take(M, activate(IL))) 3.69/1.68 zeros -> n__zeros 3.69/1.68 take(X1, X2) -> n__take(X1, X2) 3.69/1.68 activate(n__zeros) -> zeros 3.69/1.68 activate(n__take(X1, X2)) -> take(X1, X2) 3.69/1.68 activate(X) -> X 3.69/1.68 3.69/1.68 S is empty. 3.69/1.68 Rewrite Strategy: INNERMOST 3.69/1.68 ---------------------------------------- 3.69/1.68 3.69/1.68 (6) LowerBoundPropagationProof (FINISHED) 3.69/1.68 Propagated lower bound. 3.69/1.68 ---------------------------------------- 3.69/1.68 3.69/1.68 (7) 3.69/1.68 BOUNDS(n^1, INF) 3.69/1.68 3.69/1.68 ---------------------------------------- 3.69/1.68 3.69/1.68 (8) 3.69/1.68 Obligation: 3.69/1.68 Analyzing the following TRS for decreasing loops: 3.69/1.68 3.69/1.68 The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.69/1.68 3.69/1.68 3.69/1.68 The TRS R consists of the following rules: 3.69/1.68 3.69/1.68 zeros -> cons(0, n__zeros) 3.69/1.68 and(tt, X) -> activate(X) 3.69/1.68 length(nil) -> 0 3.69/1.68 length(cons(N, L)) -> s(length(activate(L))) 3.69/1.68 take(0, IL) -> nil 3.69/1.68 take(s(M), cons(N, IL)) -> cons(N, n__take(M, activate(IL))) 3.69/1.68 zeros -> n__zeros 3.69/1.68 take(X1, X2) -> n__take(X1, X2) 3.69/1.68 activate(n__zeros) -> zeros 3.69/1.68 activate(n__take(X1, X2)) -> take(X1, X2) 3.69/1.68 activate(X) -> X 3.69/1.68 3.69/1.68 S is empty. 3.69/1.68 Rewrite Strategy: INNERMOST 3.69/1.68 ---------------------------------------- 3.69/1.68 3.69/1.68 (9) InfiniteLowerBoundProof (FINISHED) 3.69/1.68 The following loop proves infinite runtime complexity: 3.69/1.68 3.69/1.68 The rewrite sequence 3.69/1.68 3.69/1.68 length(cons(N, n__zeros)) ->^+ s(length(cons(0, n__zeros))) 3.69/1.68 3.69/1.68 gives rise to a decreasing loop by considering the right hand sides subterm at position [0]. 3.69/1.68 3.69/1.68 The pumping substitution is [ ]. 3.69/1.68 3.69/1.68 The result substitution is [N / 0]. 3.69/1.68 3.69/1.68 3.69/1.68 3.69/1.68 3.69/1.68 ---------------------------------------- 3.69/1.68 3.69/1.68 (10) 3.69/1.68 BOUNDS(INF, INF) 3.69/1.71 EOF