YES Solver Timeout: 4 Global Timeout: 60 No parsing errors! Init Location: 0 Transitions: (1 + i^0)}> (1 + i^0)}> 0}> undef41, y^0 -> undef42}> (1 + j^0)}> (1 + i^0)}> undef62, y^0 -> undef63}> 0}> 0}> (1 + i^0)}> 0}> 13, i^0 -> 0, nodecount^0 -> 5, source^0 -> 0}> Fresh variables: undef41, undef42, undef62, undef63, Undef variables: undef41, undef42, undef62, undef63, Abstraction variables: Exit nodes: Accepting locations: Asserts: Preprocessed LLVMGraph Init Location: 0 Transitions: (1 + i^0)}> 0}> (1 + i^0)}> 0}> (1 + i^0), j^0 -> 0}> (1 + j^0)}> 0, j^0 -> 0}> (1 + i^0)}> (1 + i^0)}> (1 + i^0)}> Fresh variables: undef41, undef42, undef62, undef63, Undef variables: undef41, undef42, undef62, undef63, Abstraction variables: Exit nodes: Accepting locations: Asserts: ************************************************************* ******************************************************************************************* *********************** WORKING TRANSITION SYSTEM (DAG) *********************** ******************************************************************************************* Init Location: 0 Graph 0: Transitions: Variables: Graph 1: Transitions: 1 + i^0, rest remain the same}> 1 + i^0, rest remain the same}> 1 + i^0, rest remain the same}> Variables: i^0 Graph 2: Transitions: 1 + i^0, j^0 -> 0, rest remain the same}> 1 + j^0, rest remain the same}> Variables: i^0, j^0 Graph 3: Transitions: 1 + i^0, rest remain the same}> Variables: i^0 Graph 4: Transitions: 1 + i^0, rest remain the same}> Variables: i^0 Graph 5: Transitions: Variables: Precedence: Graph 0 Graph 1 Graph 2 0, j^0 -> 0, rest remain the same}> Graph 3 0, rest remain the same}> Graph 4 0, rest remain the same}> Graph 5 Map Locations to Subgraph: ( 0 , 0 ) ( 2 , 5 ) ( 3 , 4 ) ( 5 , 3 ) ( 8 , 2 ) ( 11 , 1 ) ******************************************************************************************* ******************************** CHECKING ASSERTIONS ******************************** ******************************************************************************************* Proving termination of subgraph 0 Proving termination of subgraph 1 Checking unfeasibility... Time used: 0.004614 Some transition disabled by a set of invariant(s): Invariant at l11: 0 <= i^0 Strengthening and disabling transitions... > It's unfeasible. Removing transition: 1 + i^0, rest remain the same}> LOG: CALL solverLinear in Graph for feasibility LOG: RETURN solveLinear in Graph for feasibility Strengthening transition (result): 1 + i^0, rest remain the same}> LOG: CALL solverLinear in Graph for feasibility LOG: RETURN solveLinear in Graph for feasibility Strengthening transition (result): 1 + i^0, rest remain the same}> Checking unfeasibility... Time used: 0.002402 Checking conditional termination of SCC {l11}... LOG: CALL solveLinear LOG: RETURN solveLinear - Elapsed time: 0.000928s Ranking function: 4 - i^0 New Graphs: Proving termination of subgraph 2 Checking unfeasibility... Time used: 0.011814 Checking conditional termination of SCC {l8}... LOG: CALL solveLinear LOG: RETURN solveLinear - Elapsed time: 0.001468s Ranking function: 3 - i^0 New Graphs: Transitions: 1 + j^0, rest remain the same}> Variables: j^0 Checking conditional termination of SCC {l8}... LOG: CALL solveLinear LOG: RETURN solveLinear - Elapsed time: 0.000557s Ranking function: 12 - j^0 New Graphs: Proving termination of subgraph 3 Checking unfeasibility... Time used: 0.001242 Checking conditional termination of SCC {l5}... LOG: CALL solveLinear LOG: RETURN solveLinear - Elapsed time: 0.000618s Ranking function: 12 - i^0 New Graphs: Proving termination of subgraph 4 Checking unfeasibility... Time used: 0.001215 Checking conditional termination of SCC {l3}... LOG: CALL solveLinear LOG: RETURN solveLinear - Elapsed time: 0.000625s Ranking function: 4 - i^0 New Graphs: Proving termination of subgraph 5 Analyzing SCC {l2}... No cycles found. Program Terminates