YES

Solver Timeout: 4
Global Timeout: 60
No parsing errors!
Init Location: 0
Transitions:
<l0, l7, true>
<l1, l2, (undef2 = undef2), par{oldX0^0 -> (0 + x0^0), oldX1^0 -> undef2, x0^0 -> (0 + undef2)}>
<l3, l4, (undef4 = (0 + x0^0)), par{oldX0^0 -> undef4, x0^0 -> (1 + undef4)}>
<l4, l1, (undef7 = (0 + x0^0)) /\ (20 <= (0 + undef7)), par{oldX0^0 -> undef7, x0^0 -> (0 + undef7)}>
<l4, l3, (undef10 = (0 + x0^0)) /\ ((0 + undef10) <= 19), par{oldX0^0 -> undef10, x0^0 -> (0 + undef10)}>
<l5, l4, true, par{oldX0^0 -> (0 + x0^0), x0^0 -> 0}>
<l6, l5, (undef17 = undef17), par{oldX0^0 -> (0 + x0^0), oldX1^0 -> undef17, x0^0 -> (0 + undef17)}>
<l6, l2, true>
<l6, l1, true>
<l6, l3, true>
<l6, l4, true>
<l6, l5, true>
<l7, l6, true>

Fresh variables:
undef2, undef4, undef7, undef10, undef17, 

Undef variables:
undef2, undef4, undef7, undef10, undef17, 

Abstraction variables:

Exit nodes:

Accepting locations:

Asserts:

Preprocessed LLVMGraph
Init Location: 0
Transitions:
<l0, l3, (undef17 = undef17) /\ (undef10 = (0 + 0)) /\ ((0 + undef10) <= 19), par{x0^0 -> (0 + undef10)}>
<l0, l2, true>
<l0, l2, (undef2 = undef2), par{x0^0 -> (0 + undef2)}>
<l0, l3, true>
<l0, l2, (undef7 = (0 + x0^0)) /\ (20 <= (0 + undef7)) /\ (undef2 = undef2), par{x0^0 -> (0 + undef2)}>
<l0, l3, (undef10 = (0 + x0^0)) /\ ((0 + undef10) <= 19), par{x0^0 -> (0 + undef10)}>
<l0, l3, (undef10 = (0 + 0)) /\ ((0 + undef10) <= 19), par{x0^0 -> (0 + undef10)}>
<l3, l2, (undef4 = (0 + x0^0)) /\ (undef7 = (0 + (1 + undef4))) /\ (20 <= (0 + undef7)) /\ (undef2 = undef2), par{x0^0 -> (0 + undef2)}>
<l3, l3, (undef4 = (0 + x0^0)) /\ (undef10 = (0 + (1 + undef4))) /\ ((0 + undef10) <= 19), par{x0^0 -> (0 + undef10)}>

Fresh variables:
undef2, undef4, undef7, undef10, undef17, 

Undef variables:
undef2, undef4, undef7, undef10, undef17, 

Abstraction variables:

Exit nodes:

Accepting locations:

Asserts:

*************************************************************
*******************************************************************************************
***********************       WORKING TRANSITION SYSTEM (DAG)       ***********************
*******************************************************************************************

Init Location: 0
Graph 0:
Transitions:
Variables:

Graph 1:
Transitions:
<l3, l3, undef10 <= 19 /\ x0^0 = undef4 /\ 1 + undef4 = undef10, {x0^0 -> undef10, rest remain the same}>
Variables:
x0^0

Graph 2:
Transitions:
Variables:

Precedence: 
Graph 0

Graph 1
<l0, l3, undef10 = 0, {x0^0 -> undef10, rest remain the same}>
<l0, l3, true, {all remain the same}>
<l0, l3, undef10 <= 19 /\ x0^0 = undef10, {x0^0 -> undef10, rest remain the same}>
<l0, l3, undef10 = 0, {x0^0 -> undef10, rest remain the same}>

Graph 2
<l0, l2, true, {all remain the same}>
<l0, l2, true, {x0^0 -> undef2, rest remain the same}>
<l0, l2, 20 <= undef7 /\ x0^0 = undef7, {x0^0 -> undef2, rest remain the same}>
<l3, l2, 20 <= undef7 /\ x0^0 = undef4 /\ 1 + undef4 = undef7, {x0^0 -> undef2, rest remain the same}>

Map Locations to Subgraph:
( 0 , 0 )
( 2 , 2 )
( 3 , 1 )

*******************************************************************************************
********************************    CHECKING ASSERTIONS    ********************************
*******************************************************************************************

Proving termination of subgraph 0
Proving termination of subgraph 1
Checking unfeasibility...
Time used: 0.00191

Checking conditional termination of SCC {l3}...

LOG: CALL solveLinear

LOG: RETURN solveLinear - Elapsed time: 0.000743s
Ranking function: 18 - x0^0
New Graphs: 
Proving termination of subgraph 2
Analyzing SCC {l2}...
No cycles found.

Program Terminates