YES Solver Timeout: 4 Global Timeout: 60 No parsing errors! Init Location: 0 Transitions: (0 + undef2), j_15^0 -> undef2}> (0 + st_14^0)}> (1 + i_13^0)}> (0 + st_14^0)}> (1 + i_13^0)}> Fresh variables: undef2, undef7, Undef variables: undef2, undef7, Abstraction variables: Exit nodes: Accepting locations: Asserts: Preprocessed LLVMGraph Init Location: 0 Transitions: (0 + undef2)}> (1 + (0 + undef2))}> (1 + i_13^0)}> Fresh variables: undef2, undef7, Undef variables: undef2, undef7, Abstraction variables: Exit nodes: Accepting locations: Asserts: ************************************************************* ******************************************************************************************* *********************** WORKING TRANSITION SYSTEM (DAG) *********************** ******************************************************************************************* Init Location: 0 Graph 0: Transitions: Variables: Graph 1: Transitions: 1 + i_13^0, rest remain the same}> Variables: i_13^0 Graph 2: Transitions: Variables: Precedence: Graph 0 Graph 1 1 + undef2, rest remain the same}> Graph 2 undef2, rest remain the same}> Map Locations to Subgraph: ( 0 , 0 ) ( 3 , 1 ) ( 4 , 2 ) ******************************************************************************************* ******************************** CHECKING ASSERTIONS ******************************** ******************************************************************************************* Proving termination of subgraph 0 Proving termination of subgraph 1 Checking unfeasibility... Time used: 0.001537 Checking conditional termination of SCC {l3}... LOG: CALL solveLinear LOG: RETURN solveLinear - Elapsed time: 0.000534s Ranking function: 499 - i_13^0 New Graphs: Proving termination of subgraph 2 Analyzing SCC {l4}... No cycles found. Program Terminates