3.97/1.71 YES 3.97/1.73 proof of /export/starexec/sandbox/benchmark/theBenchmark.pl 3.97/1.73 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.97/1.73 3.97/1.73 3.97/1.73 Left Termination of the query pattern 3.97/1.73 3.97/1.73 max(g,a,a) 3.97/1.73 3.97/1.73 w.r.t. the given Prolog program could successfully be proven: 3.97/1.73 3.97/1.73 (0) Prolog 3.97/1.73 (1) PrologToPiTRSProof [SOUND, 0 ms] 3.97/1.73 (2) PiTRS 3.97/1.73 (3) DependencyPairsProof [EQUIVALENT, 11 ms] 3.97/1.73 (4) PiDP 3.97/1.73 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 3.97/1.73 (6) AND 3.97/1.73 (7) PiDP 3.97/1.73 (8) UsableRulesProof [EQUIVALENT, 0 ms] 3.97/1.73 (9) PiDP 3.97/1.73 (10) PiDPToQDPProof [SOUND, 0 ms] 3.97/1.73 (11) QDP 3.97/1.73 (12) QDPSizeChangeProof [EQUIVALENT, 0 ms] 3.97/1.73 (13) YES 3.97/1.73 (14) PiDP 3.97/1.73 (15) UsableRulesProof [EQUIVALENT, 0 ms] 3.97/1.73 (16) PiDP 3.97/1.73 (17) PiDPToQDPProof [SOUND, 0 ms] 3.97/1.73 (18) QDP 3.97/1.73 (19) QDPSizeChangeProof [EQUIVALENT, 0 ms] 3.97/1.73 (20) YES 3.97/1.73 3.97/1.73 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (0) 3.97/1.73 Obligation: 3.97/1.73 Clauses: 3.97/1.73 3.97/1.73 max(X, Y, X) :- less(Y, X). 3.97/1.73 max(X, Y, Y) :- less(X, s(Y)). 3.97/1.73 less(0, s(X1)). 3.97/1.73 less(s(X), s(Y)) :- less(X, Y). 3.97/1.73 3.97/1.73 3.97/1.73 Query: max(g,a,a) 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (1) PrologToPiTRSProof (SOUND) 3.97/1.73 We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes: 3.97/1.73 3.97/1.73 max_in_3: (b,f,f) 3.97/1.73 3.97/1.73 less_in_2: (f,b) (b,f) 3.97/1.73 3.97/1.73 Transforming Prolog into the following Term Rewriting System: 3.97/1.73 3.97/1.73 Pi-finite rewrite system: 3.97/1.73 The TRS R consists of the following rules: 3.97/1.73 3.97/1.73 max_in_gaa(X, Y, X) -> U1_gaa(X, Y, less_in_ag(Y, X)) 3.97/1.73 less_in_ag(0, s(X1)) -> less_out_ag(0, s(X1)) 3.97/1.73 less_in_ag(s(X), s(Y)) -> U3_ag(X, Y, less_in_ag(X, Y)) 3.97/1.73 U3_ag(X, Y, less_out_ag(X, Y)) -> less_out_ag(s(X), s(Y)) 3.97/1.73 U1_gaa(X, Y, less_out_ag(Y, X)) -> max_out_gaa(X, Y, X) 3.97/1.73 max_in_gaa(X, Y, Y) -> U2_gaa(X, Y, less_in_ga(X, s(Y))) 3.97/1.73 less_in_ga(0, s(X1)) -> less_out_ga(0, s(X1)) 3.97/1.73 less_in_ga(s(X), s(Y)) -> U3_ga(X, Y, less_in_ga(X, Y)) 3.97/1.73 U3_ga(X, Y, less_out_ga(X, Y)) -> less_out_ga(s(X), s(Y)) 3.97/1.73 U2_gaa(X, Y, less_out_ga(X, s(Y))) -> max_out_gaa(X, Y, Y) 3.97/1.73 3.97/1.73 The argument filtering Pi contains the following mapping: 3.97/1.73 max_in_gaa(x1, x2, x3) = max_in_gaa(x1) 3.97/1.73 3.97/1.73 U1_gaa(x1, x2, x3) = U1_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ag(x1, x2) = less_in_ag(x2) 3.97/1.73 3.97/1.73 s(x1) = s(x1) 3.97/1.73 3.97/1.73 less_out_ag(x1, x2) = less_out_ag(x1) 3.97/1.73 3.97/1.73 U3_ag(x1, x2, x3) = U3_ag(x3) 3.97/1.73 3.97/1.73 max_out_gaa(x1, x2, x3) = max_out_gaa 3.97/1.73 3.97/1.73 U2_gaa(x1, x2, x3) = U2_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ga(x1, x2) = less_in_ga(x1) 3.97/1.73 3.97/1.73 0 = 0 3.97/1.73 3.97/1.73 less_out_ga(x1, x2) = less_out_ga 3.97/1.73 3.97/1.73 U3_ga(x1, x2, x3) = U3_ga(x3) 3.97/1.73 3.97/1.73 3.97/1.73 3.97/1.73 3.97/1.73 3.97/1.73 Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog 3.97/1.73 3.97/1.73 3.97/1.73 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (2) 3.97/1.73 Obligation: 3.97/1.73 Pi-finite rewrite system: 3.97/1.73 The TRS R consists of the following rules: 3.97/1.73 3.97/1.73 max_in_gaa(X, Y, X) -> U1_gaa(X, Y, less_in_ag(Y, X)) 3.97/1.73 less_in_ag(0, s(X1)) -> less_out_ag(0, s(X1)) 3.97/1.73 less_in_ag(s(X), s(Y)) -> U3_ag(X, Y, less_in_ag(X, Y)) 3.97/1.73 U3_ag(X, Y, less_out_ag(X, Y)) -> less_out_ag(s(X), s(Y)) 3.97/1.73 U1_gaa(X, Y, less_out_ag(Y, X)) -> max_out_gaa(X, Y, X) 3.97/1.73 max_in_gaa(X, Y, Y) -> U2_gaa(X, Y, less_in_ga(X, s(Y))) 3.97/1.73 less_in_ga(0, s(X1)) -> less_out_ga(0, s(X1)) 3.97/1.73 less_in_ga(s(X), s(Y)) -> U3_ga(X, Y, less_in_ga(X, Y)) 3.97/1.73 U3_ga(X, Y, less_out_ga(X, Y)) -> less_out_ga(s(X), s(Y)) 3.97/1.73 U2_gaa(X, Y, less_out_ga(X, s(Y))) -> max_out_gaa(X, Y, Y) 3.97/1.73 3.97/1.73 The argument filtering Pi contains the following mapping: 3.97/1.73 max_in_gaa(x1, x2, x3) = max_in_gaa(x1) 3.97/1.73 3.97/1.73 U1_gaa(x1, x2, x3) = U1_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ag(x1, x2) = less_in_ag(x2) 3.97/1.73 3.97/1.73 s(x1) = s(x1) 3.97/1.73 3.97/1.73 less_out_ag(x1, x2) = less_out_ag(x1) 3.97/1.73 3.97/1.73 U3_ag(x1, x2, x3) = U3_ag(x3) 3.97/1.73 3.97/1.73 max_out_gaa(x1, x2, x3) = max_out_gaa 3.97/1.73 3.97/1.73 U2_gaa(x1, x2, x3) = U2_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ga(x1, x2) = less_in_ga(x1) 3.97/1.73 3.97/1.73 0 = 0 3.97/1.73 3.97/1.73 less_out_ga(x1, x2) = less_out_ga 3.97/1.73 3.97/1.73 U3_ga(x1, x2, x3) = U3_ga(x3) 3.97/1.73 3.97/1.73 3.97/1.73 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (3) DependencyPairsProof (EQUIVALENT) 3.97/1.73 Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem: 3.97/1.73 Pi DP problem: 3.97/1.73 The TRS P consists of the following rules: 3.97/1.73 3.97/1.73 MAX_IN_GAA(X, Y, X) -> U1_GAA(X, Y, less_in_ag(Y, X)) 3.97/1.73 MAX_IN_GAA(X, Y, X) -> LESS_IN_AG(Y, X) 3.97/1.73 LESS_IN_AG(s(X), s(Y)) -> U3_AG(X, Y, less_in_ag(X, Y)) 3.97/1.73 LESS_IN_AG(s(X), s(Y)) -> LESS_IN_AG(X, Y) 3.97/1.73 MAX_IN_GAA(X, Y, Y) -> U2_GAA(X, Y, less_in_ga(X, s(Y))) 3.97/1.73 MAX_IN_GAA(X, Y, Y) -> LESS_IN_GA(X, s(Y)) 3.97/1.73 LESS_IN_GA(s(X), s(Y)) -> U3_GA(X, Y, less_in_ga(X, Y)) 3.97/1.73 LESS_IN_GA(s(X), s(Y)) -> LESS_IN_GA(X, Y) 3.97/1.73 3.97/1.73 The TRS R consists of the following rules: 3.97/1.73 3.97/1.73 max_in_gaa(X, Y, X) -> U1_gaa(X, Y, less_in_ag(Y, X)) 3.97/1.73 less_in_ag(0, s(X1)) -> less_out_ag(0, s(X1)) 3.97/1.73 less_in_ag(s(X), s(Y)) -> U3_ag(X, Y, less_in_ag(X, Y)) 3.97/1.73 U3_ag(X, Y, less_out_ag(X, Y)) -> less_out_ag(s(X), s(Y)) 3.97/1.73 U1_gaa(X, Y, less_out_ag(Y, X)) -> max_out_gaa(X, Y, X) 3.97/1.73 max_in_gaa(X, Y, Y) -> U2_gaa(X, Y, less_in_ga(X, s(Y))) 3.97/1.73 less_in_ga(0, s(X1)) -> less_out_ga(0, s(X1)) 3.97/1.73 less_in_ga(s(X), s(Y)) -> U3_ga(X, Y, less_in_ga(X, Y)) 3.97/1.73 U3_ga(X, Y, less_out_ga(X, Y)) -> less_out_ga(s(X), s(Y)) 3.97/1.73 U2_gaa(X, Y, less_out_ga(X, s(Y))) -> max_out_gaa(X, Y, Y) 3.97/1.73 3.97/1.73 The argument filtering Pi contains the following mapping: 3.97/1.73 max_in_gaa(x1, x2, x3) = max_in_gaa(x1) 3.97/1.73 3.97/1.73 U1_gaa(x1, x2, x3) = U1_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ag(x1, x2) = less_in_ag(x2) 3.97/1.73 3.97/1.73 s(x1) = s(x1) 3.97/1.73 3.97/1.73 less_out_ag(x1, x2) = less_out_ag(x1) 3.97/1.73 3.97/1.73 U3_ag(x1, x2, x3) = U3_ag(x3) 3.97/1.73 3.97/1.73 max_out_gaa(x1, x2, x3) = max_out_gaa 3.97/1.73 3.97/1.73 U2_gaa(x1, x2, x3) = U2_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ga(x1, x2) = less_in_ga(x1) 3.97/1.73 3.97/1.73 0 = 0 3.97/1.73 3.97/1.73 less_out_ga(x1, x2) = less_out_ga 3.97/1.73 3.97/1.73 U3_ga(x1, x2, x3) = U3_ga(x3) 3.97/1.73 3.97/1.73 MAX_IN_GAA(x1, x2, x3) = MAX_IN_GAA(x1) 3.97/1.73 3.97/1.73 U1_GAA(x1, x2, x3) = U1_GAA(x3) 3.97/1.73 3.97/1.73 LESS_IN_AG(x1, x2) = LESS_IN_AG(x2) 3.97/1.73 3.97/1.73 U3_AG(x1, x2, x3) = U3_AG(x3) 3.97/1.73 3.97/1.73 U2_GAA(x1, x2, x3) = U2_GAA(x3) 3.97/1.73 3.97/1.73 LESS_IN_GA(x1, x2) = LESS_IN_GA(x1) 3.97/1.73 3.97/1.73 U3_GA(x1, x2, x3) = U3_GA(x3) 3.97/1.73 3.97/1.73 3.97/1.73 We have to consider all (P,R,Pi)-chains 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (4) 3.97/1.73 Obligation: 3.97/1.73 Pi DP problem: 3.97/1.73 The TRS P consists of the following rules: 3.97/1.73 3.97/1.73 MAX_IN_GAA(X, Y, X) -> U1_GAA(X, Y, less_in_ag(Y, X)) 3.97/1.73 MAX_IN_GAA(X, Y, X) -> LESS_IN_AG(Y, X) 3.97/1.73 LESS_IN_AG(s(X), s(Y)) -> U3_AG(X, Y, less_in_ag(X, Y)) 3.97/1.73 LESS_IN_AG(s(X), s(Y)) -> LESS_IN_AG(X, Y) 3.97/1.73 MAX_IN_GAA(X, Y, Y) -> U2_GAA(X, Y, less_in_ga(X, s(Y))) 3.97/1.73 MAX_IN_GAA(X, Y, Y) -> LESS_IN_GA(X, s(Y)) 3.97/1.73 LESS_IN_GA(s(X), s(Y)) -> U3_GA(X, Y, less_in_ga(X, Y)) 3.97/1.73 LESS_IN_GA(s(X), s(Y)) -> LESS_IN_GA(X, Y) 3.97/1.73 3.97/1.73 The TRS R consists of the following rules: 3.97/1.73 3.97/1.73 max_in_gaa(X, Y, X) -> U1_gaa(X, Y, less_in_ag(Y, X)) 3.97/1.73 less_in_ag(0, s(X1)) -> less_out_ag(0, s(X1)) 3.97/1.73 less_in_ag(s(X), s(Y)) -> U3_ag(X, Y, less_in_ag(X, Y)) 3.97/1.73 U3_ag(X, Y, less_out_ag(X, Y)) -> less_out_ag(s(X), s(Y)) 3.97/1.73 U1_gaa(X, Y, less_out_ag(Y, X)) -> max_out_gaa(X, Y, X) 3.97/1.73 max_in_gaa(X, Y, Y) -> U2_gaa(X, Y, less_in_ga(X, s(Y))) 3.97/1.73 less_in_ga(0, s(X1)) -> less_out_ga(0, s(X1)) 3.97/1.73 less_in_ga(s(X), s(Y)) -> U3_ga(X, Y, less_in_ga(X, Y)) 3.97/1.73 U3_ga(X, Y, less_out_ga(X, Y)) -> less_out_ga(s(X), s(Y)) 3.97/1.73 U2_gaa(X, Y, less_out_ga(X, s(Y))) -> max_out_gaa(X, Y, Y) 3.97/1.73 3.97/1.73 The argument filtering Pi contains the following mapping: 3.97/1.73 max_in_gaa(x1, x2, x3) = max_in_gaa(x1) 3.97/1.73 3.97/1.73 U1_gaa(x1, x2, x3) = U1_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ag(x1, x2) = less_in_ag(x2) 3.97/1.73 3.97/1.73 s(x1) = s(x1) 3.97/1.73 3.97/1.73 less_out_ag(x1, x2) = less_out_ag(x1) 3.97/1.73 3.97/1.73 U3_ag(x1, x2, x3) = U3_ag(x3) 3.97/1.73 3.97/1.73 max_out_gaa(x1, x2, x3) = max_out_gaa 3.97/1.73 3.97/1.73 U2_gaa(x1, x2, x3) = U2_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ga(x1, x2) = less_in_ga(x1) 3.97/1.73 3.97/1.73 0 = 0 3.97/1.73 3.97/1.73 less_out_ga(x1, x2) = less_out_ga 3.97/1.73 3.97/1.73 U3_ga(x1, x2, x3) = U3_ga(x3) 3.97/1.73 3.97/1.73 MAX_IN_GAA(x1, x2, x3) = MAX_IN_GAA(x1) 3.97/1.73 3.97/1.73 U1_GAA(x1, x2, x3) = U1_GAA(x3) 3.97/1.73 3.97/1.73 LESS_IN_AG(x1, x2) = LESS_IN_AG(x2) 3.97/1.73 3.97/1.73 U3_AG(x1, x2, x3) = U3_AG(x3) 3.97/1.73 3.97/1.73 U2_GAA(x1, x2, x3) = U2_GAA(x3) 3.97/1.73 3.97/1.73 LESS_IN_GA(x1, x2) = LESS_IN_GA(x1) 3.97/1.73 3.97/1.73 U3_GA(x1, x2, x3) = U3_GA(x3) 3.97/1.73 3.97/1.73 3.97/1.73 We have to consider all (P,R,Pi)-chains 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (5) DependencyGraphProof (EQUIVALENT) 3.97/1.73 The approximation of the Dependency Graph [LOPSTR] contains 2 SCCs with 6 less nodes. 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (6) 3.97/1.73 Complex Obligation (AND) 3.97/1.73 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (7) 3.97/1.73 Obligation: 3.97/1.73 Pi DP problem: 3.97/1.73 The TRS P consists of the following rules: 3.97/1.73 3.97/1.73 LESS_IN_GA(s(X), s(Y)) -> LESS_IN_GA(X, Y) 3.97/1.73 3.97/1.73 The TRS R consists of the following rules: 3.97/1.73 3.97/1.73 max_in_gaa(X, Y, X) -> U1_gaa(X, Y, less_in_ag(Y, X)) 3.97/1.73 less_in_ag(0, s(X1)) -> less_out_ag(0, s(X1)) 3.97/1.73 less_in_ag(s(X), s(Y)) -> U3_ag(X, Y, less_in_ag(X, Y)) 3.97/1.73 U3_ag(X, Y, less_out_ag(X, Y)) -> less_out_ag(s(X), s(Y)) 3.97/1.73 U1_gaa(X, Y, less_out_ag(Y, X)) -> max_out_gaa(X, Y, X) 3.97/1.73 max_in_gaa(X, Y, Y) -> U2_gaa(X, Y, less_in_ga(X, s(Y))) 3.97/1.73 less_in_ga(0, s(X1)) -> less_out_ga(0, s(X1)) 3.97/1.73 less_in_ga(s(X), s(Y)) -> U3_ga(X, Y, less_in_ga(X, Y)) 3.97/1.73 U3_ga(X, Y, less_out_ga(X, Y)) -> less_out_ga(s(X), s(Y)) 3.97/1.73 U2_gaa(X, Y, less_out_ga(X, s(Y))) -> max_out_gaa(X, Y, Y) 3.97/1.73 3.97/1.73 The argument filtering Pi contains the following mapping: 3.97/1.73 max_in_gaa(x1, x2, x3) = max_in_gaa(x1) 3.97/1.73 3.97/1.73 U1_gaa(x1, x2, x3) = U1_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ag(x1, x2) = less_in_ag(x2) 3.97/1.73 3.97/1.73 s(x1) = s(x1) 3.97/1.73 3.97/1.73 less_out_ag(x1, x2) = less_out_ag(x1) 3.97/1.73 3.97/1.73 U3_ag(x1, x2, x3) = U3_ag(x3) 3.97/1.73 3.97/1.73 max_out_gaa(x1, x2, x3) = max_out_gaa 3.97/1.73 3.97/1.73 U2_gaa(x1, x2, x3) = U2_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ga(x1, x2) = less_in_ga(x1) 3.97/1.73 3.97/1.73 0 = 0 3.97/1.73 3.97/1.73 less_out_ga(x1, x2) = less_out_ga 3.97/1.73 3.97/1.73 U3_ga(x1, x2, x3) = U3_ga(x3) 3.97/1.73 3.97/1.73 LESS_IN_GA(x1, x2) = LESS_IN_GA(x1) 3.97/1.73 3.97/1.73 3.97/1.73 We have to consider all (P,R,Pi)-chains 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (8) UsableRulesProof (EQUIVALENT) 3.97/1.73 For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R. 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (9) 3.97/1.73 Obligation: 3.97/1.73 Pi DP problem: 3.97/1.73 The TRS P consists of the following rules: 3.97/1.73 3.97/1.73 LESS_IN_GA(s(X), s(Y)) -> LESS_IN_GA(X, Y) 3.97/1.73 3.97/1.73 R is empty. 3.97/1.73 The argument filtering Pi contains the following mapping: 3.97/1.73 s(x1) = s(x1) 3.97/1.73 3.97/1.73 LESS_IN_GA(x1, x2) = LESS_IN_GA(x1) 3.97/1.73 3.97/1.73 3.97/1.73 We have to consider all (P,R,Pi)-chains 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (10) PiDPToQDPProof (SOUND) 3.97/1.73 Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi. 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (11) 3.97/1.73 Obligation: 3.97/1.73 Q DP problem: 3.97/1.73 The TRS P consists of the following rules: 3.97/1.73 3.97/1.73 LESS_IN_GA(s(X)) -> LESS_IN_GA(X) 3.97/1.73 3.97/1.73 R is empty. 3.97/1.73 Q is empty. 3.97/1.73 We have to consider all (P,Q,R)-chains. 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (12) QDPSizeChangeProof (EQUIVALENT) 3.97/1.73 By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. 3.97/1.73 3.97/1.73 From the DPs we obtained the following set of size-change graphs: 3.97/1.73 *LESS_IN_GA(s(X)) -> LESS_IN_GA(X) 3.97/1.73 The graph contains the following edges 1 > 1 3.97/1.73 3.97/1.73 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (13) 3.97/1.73 YES 3.97/1.73 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (14) 3.97/1.73 Obligation: 3.97/1.73 Pi DP problem: 3.97/1.73 The TRS P consists of the following rules: 3.97/1.73 3.97/1.73 LESS_IN_AG(s(X), s(Y)) -> LESS_IN_AG(X, Y) 3.97/1.73 3.97/1.73 The TRS R consists of the following rules: 3.97/1.73 3.97/1.73 max_in_gaa(X, Y, X) -> U1_gaa(X, Y, less_in_ag(Y, X)) 3.97/1.73 less_in_ag(0, s(X1)) -> less_out_ag(0, s(X1)) 3.97/1.73 less_in_ag(s(X), s(Y)) -> U3_ag(X, Y, less_in_ag(X, Y)) 3.97/1.73 U3_ag(X, Y, less_out_ag(X, Y)) -> less_out_ag(s(X), s(Y)) 3.97/1.73 U1_gaa(X, Y, less_out_ag(Y, X)) -> max_out_gaa(X, Y, X) 3.97/1.73 max_in_gaa(X, Y, Y) -> U2_gaa(X, Y, less_in_ga(X, s(Y))) 3.97/1.73 less_in_ga(0, s(X1)) -> less_out_ga(0, s(X1)) 3.97/1.73 less_in_ga(s(X), s(Y)) -> U3_ga(X, Y, less_in_ga(X, Y)) 3.97/1.73 U3_ga(X, Y, less_out_ga(X, Y)) -> less_out_ga(s(X), s(Y)) 3.97/1.73 U2_gaa(X, Y, less_out_ga(X, s(Y))) -> max_out_gaa(X, Y, Y) 3.97/1.73 3.97/1.73 The argument filtering Pi contains the following mapping: 3.97/1.73 max_in_gaa(x1, x2, x3) = max_in_gaa(x1) 3.97/1.73 3.97/1.73 U1_gaa(x1, x2, x3) = U1_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ag(x1, x2) = less_in_ag(x2) 3.97/1.73 3.97/1.73 s(x1) = s(x1) 3.97/1.73 3.97/1.73 less_out_ag(x1, x2) = less_out_ag(x1) 3.97/1.73 3.97/1.73 U3_ag(x1, x2, x3) = U3_ag(x3) 3.97/1.73 3.97/1.73 max_out_gaa(x1, x2, x3) = max_out_gaa 3.97/1.73 3.97/1.73 U2_gaa(x1, x2, x3) = U2_gaa(x3) 3.97/1.73 3.97/1.73 less_in_ga(x1, x2) = less_in_ga(x1) 3.97/1.73 3.97/1.73 0 = 0 3.97/1.73 3.97/1.73 less_out_ga(x1, x2) = less_out_ga 3.97/1.73 3.97/1.73 U3_ga(x1, x2, x3) = U3_ga(x3) 3.97/1.73 3.97/1.73 LESS_IN_AG(x1, x2) = LESS_IN_AG(x2) 3.97/1.73 3.97/1.73 3.97/1.73 We have to consider all (P,R,Pi)-chains 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (15) UsableRulesProof (EQUIVALENT) 3.97/1.73 For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R. 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (16) 3.97/1.73 Obligation: 3.97/1.73 Pi DP problem: 3.97/1.73 The TRS P consists of the following rules: 3.97/1.73 3.97/1.73 LESS_IN_AG(s(X), s(Y)) -> LESS_IN_AG(X, Y) 3.97/1.73 3.97/1.73 R is empty. 3.97/1.73 The argument filtering Pi contains the following mapping: 3.97/1.73 s(x1) = s(x1) 3.97/1.73 3.97/1.73 LESS_IN_AG(x1, x2) = LESS_IN_AG(x2) 3.97/1.73 3.97/1.73 3.97/1.73 We have to consider all (P,R,Pi)-chains 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (17) PiDPToQDPProof (SOUND) 3.97/1.73 Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi. 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (18) 3.97/1.73 Obligation: 3.97/1.73 Q DP problem: 3.97/1.73 The TRS P consists of the following rules: 3.97/1.73 3.97/1.73 LESS_IN_AG(s(Y)) -> LESS_IN_AG(Y) 3.97/1.73 3.97/1.73 R is empty. 3.97/1.73 Q is empty. 3.97/1.73 We have to consider all (P,Q,R)-chains. 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (19) QDPSizeChangeProof (EQUIVALENT) 3.97/1.73 By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. 3.97/1.73 3.97/1.73 From the DPs we obtained the following set of size-change graphs: 3.97/1.73 *LESS_IN_AG(s(Y)) -> LESS_IN_AG(Y) 3.97/1.73 The graph contains the following edges 1 > 1 3.97/1.73 3.97/1.73 3.97/1.73 ---------------------------------------- 3.97/1.73 3.97/1.73 (20) 3.97/1.73 YES 3.97/1.78 EOF