WORST_CASE(INF,?)

### Pre-processing the ITS problem ###

Initial linear ITS problem
   Start location: __init
      0: f1_0_main_Load -> f135_0_f_LE : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg1>0 && arg2>-1 && arg2==arg1P_1 && arg2==arg2P_1 ], cost: 1
      1: f135_0_f_LE -> f182_0_f_LE : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, [ arg1>0 && arg1==arg1P_2 && 2==arg2P_2 && arg2==arg3P_2 ], cost: 1
      2: f182_0_f_LE -> f135_0_f_LE : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [ arg2>0 && arg1>0 && arg1-arg2==arg1P_3 && -1+arg3==arg2P_3 ], cost: 1
      3: f182_0_f_LE -> f182_0_f_LE : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, [ arg2>0 && arg1>0 && arg1==arg1P_4 && -1+arg2==arg2P_4 && -1+arg3==arg3P_4 ], cost: 1
      4: f182_0_f_LE -> f182_0_f_LE : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, [ arg2>0 && arg1>0 && arg1==arg1P_5 && -1+arg2==arg2P_5 ], cost: 1
      5: __init -> f1_0_main_Load : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, [], cost: 1

Checking for constant complexity:
   The following rule is satisfiable with cost >= 1, yielding constant complexity:
      5: __init -> f1_0_main_Load : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, [], cost: 1

Simplified all rules, resulting in:
   Start location: __init
      0: f1_0_main_Load -> f135_0_f_LE : arg1'=arg2, arg3'=arg3P_1, [ arg1>0 && arg2>-1 ], cost: 1
      1: f135_0_f_LE -> f182_0_f_LE : arg2'=2, arg3'=arg2, [ arg1>0 ], cost: 1
      2: f182_0_f_LE -> f135_0_f_LE : arg1'=arg1-arg2, arg2'=-1+arg3, arg3'=arg3P_3, [ arg2>0 && arg1>0 ], cost: 1
      3: f182_0_f_LE -> f182_0_f_LE : arg2'=-1+arg2, arg3'=-1+arg3, [ arg2>0 && arg1>0 ], cost: 1
      4: f182_0_f_LE -> f182_0_f_LE : arg2'=-1+arg2, arg3'=arg3P_5, [ arg2>0 && arg1>0 ], cost: 1
      5: __init -> f1_0_main_Load : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, [], cost: 1

### Simplification by acceleration and chaining ###

Accelerating simple loops of location 2.
   Accelerating the following rules:
      3: f182_0_f_LE -> f182_0_f_LE : arg2'=-1+arg2, arg3'=-1+arg3, [ arg2>0 && arg1>0 ], cost: 1
      4: f182_0_f_LE -> f182_0_f_LE : arg2'=-1+arg2, arg3'=arg3P_5, [ arg2>0 && arg1>0 ], cost: 1

   Accelerated rule 3 with metering function arg2, yielding the new rule 6.
   Accelerated rule 4 with metering function arg2, yielding the new rule 7.
   Removing the simple loops: 3 4.

Accelerated all simple loops using metering functions (where possible):
   Start location: __init
      0: f1_0_main_Load -> f135_0_f_LE : arg1'=arg2, arg3'=arg3P_1, [ arg1>0 && arg2>-1 ], cost: 1
      1: f135_0_f_LE -> f182_0_f_LE : arg2'=2, arg3'=arg2, [ arg1>0 ], cost: 1
      2: f182_0_f_LE -> f135_0_f_LE : arg1'=arg1-arg2, arg2'=-1+arg3, arg3'=arg3P_3, [ arg2>0 && arg1>0 ], cost: 1
      6: f182_0_f_LE -> f182_0_f_LE : arg2'=0, arg3'=arg3-arg2, [ arg2>0 && arg1>0 ], cost: arg2
      7: f182_0_f_LE -> f182_0_f_LE : arg2'=0, arg3'=arg3P_5, [ arg2>0 && arg1>0 ], cost: arg2
      5: __init -> f1_0_main_Load : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, [], cost: 1

Chained accelerated rules (with incoming rules):
   Start location: __init
      0: f1_0_main_Load -> f135_0_f_LE : arg1'=arg2, arg3'=arg3P_1, [ arg1>0 && arg2>-1 ], cost: 1
      1: f135_0_f_LE -> f182_0_f_LE : arg2'=2, arg3'=arg2, [ arg1>0 ], cost: 1
      8: f135_0_f_LE -> f182_0_f_LE : arg2'=0, arg3'=-2+arg2, [ arg1>0 ], cost: 3
      9: f135_0_f_LE -> f182_0_f_LE : arg2'=0, arg3'=arg3P_5, [ arg1>0 ], cost: 3
      2: f182_0_f_LE -> f135_0_f_LE : arg1'=arg1-arg2, arg2'=-1+arg3, arg3'=arg3P_3, [ arg2>0 && arg1>0 ], cost: 1
      5: __init -> f1_0_main_Load : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, [], cost: 1

Eliminated locations (on linear paths):
   Start location: __init
      1: f135_0_f_LE -> f182_0_f_LE : arg2'=2, arg3'=arg2, [ arg1>0 ], cost: 1
      8: f135_0_f_LE -> f182_0_f_LE : arg2'=0, arg3'=-2+arg2, [ arg1>0 ], cost: 3
      9: f135_0_f_LE -> f182_0_f_LE : arg2'=0, arg3'=arg3P_5, [ arg1>0 ], cost: 3
      2: f182_0_f_LE -> f135_0_f_LE : arg1'=arg1-arg2, arg2'=-1+arg3, arg3'=arg3P_3, [ arg2>0 && arg1>0 ], cost: 1
     10: __init -> f135_0_f_LE : arg1'=arg2P_6, arg2'=arg2P_6, arg3'=arg3P_1, [ arg1P_6>0 && arg2P_6>-1 ], cost: 2

Eliminated locations (on tree-shaped paths):
   Start location: __init
     11: f135_0_f_LE -> f135_0_f_LE : arg1'=-2+arg1, arg2'=-1+arg2, arg3'=arg3P_3, [ arg1>0 ], cost: 2
     10: __init -> f135_0_f_LE : arg1'=arg2P_6, arg2'=arg2P_6, arg3'=arg3P_1, [ arg1P_6>0 && arg2P_6>-1 ], cost: 2

Accelerating simple loops of location 1.
   Accelerating the following rules:
     11: f135_0_f_LE -> f135_0_f_LE : arg1'=-2+arg1, arg2'=-1+arg2, arg3'=arg3P_3, [ arg1>0 ], cost: 2

   Accelerated rule 11 with metering function meter (where 2*meter==arg1), yielding the new rule 12.
   Removing the simple loops: 11.

Accelerated all simple loops using metering functions (where possible):
   Start location: __init
     12: f135_0_f_LE -> f135_0_f_LE : arg1'=-2*meter+arg1, arg2'=-meter+arg2, arg3'=arg3P_3, [ arg1>0 && 2*meter==arg1 && meter>=1 ], cost: 2*meter
     10: __init -> f135_0_f_LE : arg1'=arg2P_6, arg2'=arg2P_6, arg3'=arg3P_1, [ arg1P_6>0 && arg2P_6>-1 ], cost: 2

Chained accelerated rules (with incoming rules):
   Start location: __init
     10: __init -> f135_0_f_LE : arg1'=arg2P_6, arg2'=arg2P_6, arg3'=arg3P_1, [ arg1P_6>0 && arg2P_6>-1 ], cost: 2
     13: __init -> f135_0_f_LE : arg1'=0, arg2'=meter, arg3'=arg3P_3, [ 2*meter>0 && meter>=1 ], cost: 2+2*meter

Removed unreachable locations (and leaf rules with constant cost):
   Start location: __init
     13: __init -> f135_0_f_LE : arg1'=0, arg2'=meter, arg3'=arg3P_3, [ 2*meter>0 && meter>=1 ], cost: 2+2*meter

### Computing asymptotic complexity ###

Fully simplified ITS problem
   Start location: __init
     13: __init -> f135_0_f_LE : arg1'=0, arg2'=meter, arg3'=arg3P_3, [ 2*meter>0 && meter>=1 ], cost: 2+2*meter

Computing asymptotic complexity for rule 13
   Solved the limit problem by the following transformations:
      Created initial limit problem:
      2+2*meter (+), 2*meter (+/+!) [not solved]

      removing all constraints (solved by SMT)
      resulting limit problem: [solved]

      applying transformation rule (C) using substitution {meter==n}
      resulting limit problem:
      [solved]

   Solution:
      meter / n
   Resulting cost 2+2*n has complexity: Unbounded

Found new complexity Unbounded.

Obtained the following overall complexity (w.r.t. the length of the input n):
   Complexity:  Unbounded
   Cpx degree:  Unbounded
   Solved cost: 2+2*n
   Rule cost:   2+2*meter
   Rule guard:  [ 2*meter>0 ]

WORST_CASE(INF,?)