WORST_CASE(INF,?)

### Pre-processing the ITS problem ###

Initial linear ITS problem
   Start location: __init
      0: f1_0_main_Load -> f213_0_main_GT : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg2>-1 && arg3P_1>-1 && arg1P_1>-1 && arg1>0 ], cost: 1
      1: f213_0_main_GT -> f252_0_main_LE : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, [ arg3<arg2 && arg1==arg1P_2 && arg2==arg2P_2 && arg3==arg3P_2 ], cost: 1
      2: f213_0_main_GT -> f252_0_main_LE : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [ arg2<=arg3 && arg1>arg3 && arg1==arg1P_3 && arg2==arg2P_3 && arg3==arg3P_3 ], cost: 1
      3: f252_0_main_LE -> f213_0_main_GT : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, [ arg3<arg2 && arg1==arg1P_4 && -1+arg2==arg2P_4 && arg3==arg3P_4 ], cost: 1
      4: f252_0_main_LE -> f213_0_main_GT : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, [ arg3>=arg2 && arg3>=arg1 && arg1==arg1P_5 && arg2==arg2P_5 && arg3==arg3P_5 ], cost: 1
      5: f252_0_main_LE -> f213_0_main_GT : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, [ arg3>=arg2 && arg3<arg1 && -1+arg1==arg1P_6 && arg2==arg2P_6 && arg3==arg3P_6 ], cost: 1
      6: __init -> f1_0_main_Load : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, [], cost: 1

Checking for constant complexity:
   The following rule is satisfiable with cost >= 1, yielding constant complexity:
      6: __init -> f1_0_main_Load : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, [], cost: 1

Simplified all rules, resulting in:
   Start location: __init
      0: f1_0_main_Load -> f213_0_main_GT : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg2>-1 && arg3P_1>-1 && arg1P_1>-1 && arg1>0 ], cost: 1
      1: f213_0_main_GT -> f252_0_main_LE : [ arg3<arg2 ], cost: 1
      2: f213_0_main_GT -> f252_0_main_LE : [ arg2<=arg3 && arg1>arg3 ], cost: 1
      3: f252_0_main_LE -> f213_0_main_GT : arg2'=-1+arg2, [ arg3<arg2 ], cost: 1
      4: f252_0_main_LE -> f213_0_main_GT : [ arg3>=arg2 && arg3>=arg1 ], cost: 1
      5: f252_0_main_LE -> f213_0_main_GT : arg1'=-1+arg1, [ arg3>=arg2 && arg3<arg1 ], cost: 1
      6: __init -> f1_0_main_Load : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, [], cost: 1

### Simplification by acceleration and chaining ###

Eliminated locations (on linear paths):
   Start location: __init
      1: f213_0_main_GT -> f252_0_main_LE : [ arg3<arg2 ], cost: 1
      2: f213_0_main_GT -> f252_0_main_LE : [ arg2<=arg3 && arg1>arg3 ], cost: 1
      3: f252_0_main_LE -> f213_0_main_GT : arg2'=-1+arg2, [ arg3<arg2 ], cost: 1
      4: f252_0_main_LE -> f213_0_main_GT : [ arg3>=arg2 && arg3>=arg1 ], cost: 1
      5: f252_0_main_LE -> f213_0_main_GT : arg1'=-1+arg1, [ arg3>=arg2 && arg3<arg1 ], cost: 1
      7: __init -> f213_0_main_GT : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg2P_7>-1 && arg3P_1>-1 && arg1P_1>-1 && arg1P_7>0 ], cost: 2

Eliminated locations (on tree-shaped paths):
   Start location: __init
      8: f213_0_main_GT -> f213_0_main_GT : arg2'=-1+arg2, [ arg3<arg2 ], cost: 2
      9: f213_0_main_GT -> f213_0_main_GT : arg1'=-1+arg1, [ arg2<=arg3 && arg1>arg3 ], cost: 2
      7: __init -> f213_0_main_GT : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg2P_7>-1 && arg3P_1>-1 && arg1P_1>-1 && arg1P_7>0 ], cost: 2

Accelerating simple loops of location 1.
   Accelerating the following rules:
      8: f213_0_main_GT -> f213_0_main_GT : arg2'=-1+arg2, [ arg3<arg2 ], cost: 2
      9: f213_0_main_GT -> f213_0_main_GT : arg1'=-1+arg1, [ arg2<=arg3 && arg1>arg3 ], cost: 2

   Accelerated rule 8 with metering function -arg3+arg2, yielding the new rule 10.
   Accelerated rule 9 with metering function -arg3+arg1, yielding the new rule 11.
   Removing the simple loops: 8 9.

Accelerated all simple loops using metering functions (where possible):
   Start location: __init
     10: f213_0_main_GT -> f213_0_main_GT : arg2'=arg3, [ arg3<arg2 ], cost: -2*arg3+2*arg2
     11: f213_0_main_GT -> f213_0_main_GT : arg1'=arg3, [ arg2<=arg3 && arg1>arg3 ], cost: -2*arg3+2*arg1
      7: __init -> f213_0_main_GT : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg2P_7>-1 && arg3P_1>-1 && arg1P_1>-1 && arg1P_7>0 ], cost: 2

Chained accelerated rules (with incoming rules):
   Start location: __init
      7: __init -> f213_0_main_GT : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg2P_7>-1 && arg3P_1>-1 && arg1P_1>-1 && arg1P_7>0 ], cost: 2
     12: __init -> f213_0_main_GT : arg1'=arg1P_1, arg2'=arg3P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg3P_1>-1 && arg1P_1>-1 && arg3P_1<arg2P_1 ], cost: 2-2*arg3P_1+2*arg2P_1
     13: __init -> f213_0_main_GT : arg1'=arg3P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg3P_1>-1 && arg1P_1>-1 && arg2P_1<=arg3P_1 && arg1P_1>arg3P_1 ], cost: 2-2*arg3P_1+2*arg1P_1

Removed unreachable locations (and leaf rules with constant cost):
   Start location: __init
     12: __init -> f213_0_main_GT : arg1'=arg1P_1, arg2'=arg3P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg3P_1>-1 && arg1P_1>-1 && arg3P_1<arg2P_1 ], cost: 2-2*arg3P_1+2*arg2P_1
     13: __init -> f213_0_main_GT : arg1'=arg3P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg3P_1>-1 && arg1P_1>-1 && arg2P_1<=arg3P_1 && arg1P_1>arg3P_1 ], cost: 2-2*arg3P_1+2*arg1P_1

### Computing asymptotic complexity ###

Fully simplified ITS problem
   Start location: __init
     12: __init -> f213_0_main_GT : arg1'=arg1P_1, arg2'=arg3P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg3P_1>-1 && arg1P_1>-1 && arg3P_1<arg2P_1 ], cost: 2-2*arg3P_1+2*arg2P_1
     13: __init -> f213_0_main_GT : arg1'=arg3P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg3P_1>-1 && arg1P_1>-1 && arg2P_1<=arg3P_1 && arg1P_1>arg3P_1 ], cost: 2-2*arg3P_1+2*arg1P_1

Computing asymptotic complexity for rule 12
   Simplified the guard:
     12: __init -> f213_0_main_GT : arg1'=arg1P_1, arg2'=arg3P_1, arg3'=arg3P_1, [ arg3P_1>-1 && arg1P_1>-1 && arg3P_1<arg2P_1 ], cost: 2-2*arg3P_1+2*arg2P_1
   Solved the limit problem by the following transformations:
      Created initial limit problem:
      1+arg1P_1 (+/+!), 2-2*arg3P_1+2*arg2P_1 (+), -arg3P_1+arg2P_1 (+/+!), 1+arg3P_1 (+/+!) [not solved]

      removing all constraints (solved by SMT)
      resulting limit problem: [solved]

      applying transformation rule (C) using substitution {arg3P_1==n,arg1P_1==n,arg2P_1==2*n}
      resulting limit problem:
      [solved]

   Solution:
      arg3P_1 / n
      arg1P_1 / n
      arg2P_1 / 2*n
   Resulting cost 2+2*n has complexity: Unbounded

Found new complexity Unbounded.

Obtained the following overall complexity (w.r.t. the length of the input n):
   Complexity:  Unbounded
   Cpx degree:  Unbounded
   Solved cost: 2+2*n
   Rule cost:   2-2*arg3P_1+2*arg2P_1
   Rule guard:  [ arg3P_1>-1 && arg1P_1>-1 && arg3P_1<arg2P_1 ]

WORST_CASE(INF,?)