WORST_CASE(INF,?) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: __init 0: f1_0_main_Load -> f145_0_main_EQ : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 ], cost: 1 1: f145_0_main_EQ -> f145_0_main_EQ : arg1'=arg1P_2, arg2'=arg2P_2, [ arg2>arg1 && 1+arg1==arg1P_2 && arg2==arg2P_2 ], cost: 1 2: f145_0_main_EQ -> f145_0_main_EQ : arg1'=arg1P_3, arg2'=arg2P_3, [ arg2 f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 3: __init -> f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1 Simplified all rules, resulting in: Start location: __init 0: f1_0_main_Load -> f145_0_main_EQ : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 ], cost: 1 1: f145_0_main_EQ -> f145_0_main_EQ : arg1'=1+arg1, [ arg2>arg1 ], cost: 1 2: f145_0_main_EQ -> f145_0_main_EQ : arg2'=1+arg2, [ arg2 f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1 ### Simplification by acceleration and chaining ### Accelerating simple loops of location 1. Accelerating the following rules: 1: f145_0_main_EQ -> f145_0_main_EQ : arg1'=1+arg1, [ arg2>arg1 ], cost: 1 2: f145_0_main_EQ -> f145_0_main_EQ : arg2'=1+arg2, [ arg2 f145_0_main_EQ : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 ], cost: 1 4: f145_0_main_EQ -> f145_0_main_EQ : arg1'=arg2, [ arg2>arg1 ], cost: -arg1+arg2 5: f145_0_main_EQ -> f145_0_main_EQ : arg2'=arg1, [ arg2 f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1 Chained accelerated rules (with incoming rules): Start location: __init 0: f1_0_main_Load -> f145_0_main_EQ : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 ], cost: 1 6: f1_0_main_Load -> f145_0_main_EQ : arg1'=arg2P_1, arg2'=arg2P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 && arg2P_1>arg1P_1 ], cost: 1+arg2P_1-arg1P_1 7: f1_0_main_Load -> f145_0_main_EQ : arg1'=arg1P_1, arg2'=arg1P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 && arg2P_1 f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1 Removed unreachable locations (and leaf rules with constant cost): Start location: __init 6: f1_0_main_Load -> f145_0_main_EQ : arg1'=arg2P_1, arg2'=arg2P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 && arg2P_1>arg1P_1 ], cost: 1+arg2P_1-arg1P_1 7: f1_0_main_Load -> f145_0_main_EQ : arg1'=arg1P_1, arg2'=arg1P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 && arg2P_1 f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1 Eliminated locations (on tree-shaped paths): Start location: __init 8: __init -> f145_0_main_EQ : arg1'=arg2P_1, arg2'=arg2P_1, [ arg2P_1>-1 && arg2P_4>-1 && arg1P_1>-1 && arg1P_4>0 && arg2P_1>arg1P_1 ], cost: 2+arg2P_1-arg1P_1 9: __init -> f145_0_main_EQ : arg1'=arg1P_1, arg2'=arg1P_1, [ arg2P_1>-1 && arg2P_4>-1 && arg1P_1>-1 && arg1P_4>0 && arg2P_1 f145_0_main_EQ : arg1'=arg2P_1, arg2'=arg2P_1, [ arg2P_1>-1 && arg2P_4>-1 && arg1P_1>-1 && arg1P_4>0 && arg2P_1>arg1P_1 ], cost: 2+arg2P_1-arg1P_1 9: __init -> f145_0_main_EQ : arg1'=arg1P_1, arg2'=arg1P_1, [ arg2P_1>-1 && arg2P_4>-1 && arg1P_1>-1 && arg1P_4>0 && arg2P_1 f145_0_main_EQ : arg1'=arg2P_1, arg2'=arg2P_1, [ arg2P_4>-1 && arg1P_1>-1 && arg1P_4>0 && arg2P_1>arg1P_1 ], cost: 2+arg2P_1-arg1P_1 Solved the limit problem by the following transformations: Created initial limit problem: 1+arg1P_1 (+/+!), arg2P_1-arg1P_1 (+/+!), 2+arg2P_1-arg1P_1 (+), 1+arg2P_4 (+/+!), arg1P_4 (+/+!) [not solved] removing all constraints (solved by SMT) resulting limit problem: [solved] applying transformation rule (C) using substitution {arg2P_1==2*n,arg1P_4==n,arg1P_1==n,arg2P_4==n} resulting limit problem: [solved] Solution: arg2P_1 / 2*n arg1P_4 / n arg1P_1 / n arg2P_4 / n Resulting cost 2+n has complexity: Unbounded Found new complexity Unbounded. Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Unbounded Cpx degree: Unbounded Solved cost: 2+n Rule cost: 2+arg2P_1-arg1P_1 Rule guard: [ arg2P_4>-1 && arg1P_1>-1 && arg1P_4>0 && arg2P_1>arg1P_1 ] WORST_CASE(INF,?)