YES proof of prog.inttrs # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given IRSwT could be proven: (0) IRSwT (1) IRSFormatTransformerProof [EQUIVALENT, 0 ms] (2) IRSwT (3) IRSwTTerminationDigraphProof [EQUIVALENT, 145 ms] (4) TRUE ---------------------------------------- (0) Obligation: Rules: f1_0_main_ConstantStackPush(arg1, arg2, arg3) -> f83_0_main_ArrayAccess(arg1P, arg2P, arg3P) :|: arg2 = arg3P && arg2 + 1 = arg2P && 0 <= arg1P - 1 && 0 <= arg1 - 1 && -1 <= arg2 - 1 && arg1P <= arg1 f83_0_main_ArrayAccess(x, x1, x2) -> f83_0_main_ArrayAccess(x3, x4, x5) :|: x2 = x5 && x2 + 1 = x4 && 0 <= x3 - 1 && 0 <= x - 1 && x3 <= x && -1 <= x2 - 1 && x1 <= x2 - 1 __init(x6, x7, x8) -> f1_0_main_ConstantStackPush(x9, x10, x11) :|: 0 <= 0 Start term: __init(arg1, arg2, arg3) ---------------------------------------- (1) IRSFormatTransformerProof (EQUIVALENT) Reformatted IRS to match normalized format (transformed away non-linear left-hand sides, !=, / and %). ---------------------------------------- (2) Obligation: Rules: f1_0_main_ConstantStackPush(arg1, arg2, arg3) -> f83_0_main_ArrayAccess(arg1P, arg2P, arg3P) :|: arg2 = arg3P && arg2 + 1 = arg2P && 0 <= arg1P - 1 && 0 <= arg1 - 1 && -1 <= arg2 - 1 && arg1P <= arg1 f83_0_main_ArrayAccess(x, x1, x2) -> f83_0_main_ArrayAccess(x3, x4, x5) :|: x2 = x5 && x2 + 1 = x4 && 0 <= x3 - 1 && 0 <= x - 1 && x3 <= x && -1 <= x2 - 1 && x1 <= x2 - 1 __init(x6, x7, x8) -> f1_0_main_ConstantStackPush(x9, x10, x11) :|: 0 <= 0 Start term: __init(arg1, arg2, arg3) ---------------------------------------- (3) IRSwTTerminationDigraphProof (EQUIVALENT) Constructed termination digraph! Nodes: (1) f1_0_main_ConstantStackPush(arg1, arg2, arg3) -> f83_0_main_ArrayAccess(arg1P, arg2P, arg3P) :|: arg2 = arg3P && arg2 + 1 = arg2P && 0 <= arg1P - 1 && 0 <= arg1 - 1 && -1 <= arg2 - 1 && arg1P <= arg1 (2) f83_0_main_ArrayAccess(x, x1, x2) -> f83_0_main_ArrayAccess(x3, x4, x5) :|: x2 = x5 && x2 + 1 = x4 && 0 <= x3 - 1 && 0 <= x - 1 && x3 <= x && -1 <= x2 - 1 && x1 <= x2 - 1 (3) __init(x6, x7, x8) -> f1_0_main_ConstantStackPush(x9, x10, x11) :|: 0 <= 0 Arcs: (3) -> (1) This digraph is fully evaluated! ---------------------------------------- (4) TRUE