NO
proof of prog.inttrs
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


Termination of the given IRSwT could be disproven:

(0) IRSwT
(1) IRSFormatTransformerProof [EQUIVALENT, 0 ms]
(2) IRSwT
(3) IRSwTTerminationDigraphProof [EQUIVALENT, 84 ms]
(4) IRSwT
(5) IntTRSCompressionProof [EQUIVALENT, 31 ms]
(6) IRSwT
(7) FilterProof [EQUIVALENT, 0 ms]
(8) IntTRS
(9) IntTRSCompressionProof [EQUIVALENT, 0 ms]
(10) IntTRS
(11) IntTRSNonPeriodicNontermProof [COMPLETE, 0 ms]
(12) NO


----------------------------------------

(0)
Obligation:
Rules:
f53_0_main_Load(arg1, arg2) -> f53_0_main_Load(arg1P, arg2P) :|: arg1 = arg2P && arg2 = arg1P && arg1 + arg2 <= 99 && 0 <= arg2 - 1 && 0 <= arg1 - 1
f1_0_main_ConstantStackPush(x, x1) -> f53_0_main_Load(x2, x3) :|: 13 = x3 && 17 = x2
__init(x4, x5) -> f1_0_main_ConstantStackPush(x6, x7) :|: 0 <= 0
Start term: __init(arg1, arg2)

----------------------------------------

(1) IRSFormatTransformerProof (EQUIVALENT)
Reformatted IRS to match normalized format (transformed away non-linear left-hand sides, !=, / and %).
----------------------------------------

(2)
Obligation:
Rules:
f53_0_main_Load(arg1, arg2) -> f53_0_main_Load(arg1P, arg2P) :|: arg1 = arg2P && arg2 = arg1P && arg1 + arg2 <= 99 && 0 <= arg2 - 1 && 0 <= arg1 - 1
f1_0_main_ConstantStackPush(x, x1) -> f53_0_main_Load(x2, x3) :|: 13 = x3 && 17 = x2
__init(x4, x5) -> f1_0_main_ConstantStackPush(x6, x7) :|: 0 <= 0
Start term: __init(arg1, arg2)

----------------------------------------

(3) IRSwTTerminationDigraphProof (EQUIVALENT)
Constructed termination digraph!
Nodes:
(1) f53_0_main_Load(arg1, arg2) -> f53_0_main_Load(arg1P, arg2P) :|: arg1 = arg2P && arg2 = arg1P && arg1 + arg2 <= 99 && 0 <= arg2 - 1 && 0 <= arg1 - 1
(2) f1_0_main_ConstantStackPush(x, x1) -> f53_0_main_Load(x2, x3) :|: 13 = x3 && 17 = x2
(3) __init(x4, x5) -> f1_0_main_ConstantStackPush(x6, x7) :|: 0 <= 0

Arcs:
(1) -> (1)
(2) -> (1)
(3) -> (2)

This digraph is fully evaluated!
----------------------------------------

(4)
Obligation:

Termination digraph:
Nodes:
(1) f53_0_main_Load(arg1, arg2) -> f53_0_main_Load(arg1P, arg2P) :|: arg1 = arg2P && arg2 = arg1P && arg1 + arg2 <= 99 && 0 <= arg2 - 1 && 0 <= arg1 - 1

Arcs:
(1) -> (1)

This digraph is fully evaluated!

----------------------------------------

(5) IntTRSCompressionProof (EQUIVALENT)
Compressed rules.
----------------------------------------

(6)
Obligation:
Rules:
f53_0_main_Load(arg1:0, arg1P:0) -> f53_0_main_Load(arg1P:0, arg1:0) :|: arg1P:0 > 0 && arg1:0 + arg1P:0 <= 99 && arg1:0 > 0

----------------------------------------

(7) FilterProof (EQUIVALENT)
Used the following sort dictionary for filtering: 
f53_0_main_Load(INTEGER, INTEGER)
Replaced non-predefined constructor symbols by 0.
----------------------------------------

(8)
Obligation:
Rules:
f53_0_main_Load(arg1:0, arg1P:0) -> f53_0_main_Load(arg1P:0, arg1:0) :|: arg1P:0 > 0 && arg1:0 + arg1P:0 <= 99 && arg1:0 > 0

----------------------------------------

(9) IntTRSCompressionProof (EQUIVALENT)
Compressed rules.
----------------------------------------

(10)
Obligation:
Rules:
f53_0_main_Load(arg1:0:0, arg1P:0:0) -> f53_0_main_Load(arg1P:0:0, arg1:0:0) :|: arg1P:0:0 > 0 && arg1:0:0 + arg1P:0:0 <= 99 && arg1:0:0 > 0

----------------------------------------

(11) IntTRSNonPeriodicNontermProof (COMPLETE)
Normalized system to the following form:
f(pc, arg1:0:0, arg1P:0:0) -> f(1, arg1P:0:0, arg1:0:0) :|: pc = 1 && (arg1P:0:0 > 0 && arg1:0:0 + arg1P:0:0 <= 99 && arg1:0:0 > 0)
Proved unsatisfiability of the following formula, indicating that the system is never left after entering:
(((run2_0 = ((1 * 1)) and run2_1 = ((run1_2 * 1)) and run2_2 = ((run1_1 * 1))) and (((run1_0 * 1)) = ((1 * 1)) and ((((run1_2 * 1)) > 0 and ((run1_1 * 1) + (run1_2 * 1)) <= ((1 * 99))) and ((run1_1 * 1)) > 0))) and !(((run2_0 * 1)) = ((1 * 1)) and ((((run2_2 * 1)) > 0 and ((run2_1 * 1) + (run2_2 * 1)) <= ((1 * 99))) and ((run2_1 * 1)) > 0)))
Proved satisfiability of the following formula, indicating that the system is entered at least once:
((run2_0 = ((1 * 1)) and run2_1 = ((run1_2 * 1)) and run2_2 = ((run1_1 * 1))) and (((run1_0 * 1)) = ((1 * 1)) and ((((run1_2 * 1)) > 0 and ((run1_1 * 1) + (run1_2 * 1)) <= ((1 * 99))) and ((run1_1 * 1)) > 0)))

----------------------------------------

(12)
NO