NO proof of prog.inttrs # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given IRSwT could be disproven: (0) IRSwT (1) IRSFormatTransformerProof [EQUIVALENT, 0 ms] (2) IRSwT (3) IRSwTTerminationDigraphProof [EQUIVALENT, 77 ms] (4) IRSwT (5) IntTRSCompressionProof [EQUIVALENT, 31 ms] (6) IRSwT (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (8) IRSwT (9) FilterProof [EQUIVALENT, 0 ms] (10) IntTRS (11) IntTRSNonPeriodicNontermProof [COMPLETE, 0 ms] (12) NO ---------------------------------------- (0) Obligation: Rules: l0(xHAT0, yHAT0) -> l1(xHATpost, yHATpost) :|: yHAT0 = yHATpost && xHAT0 = xHATpost && 0 <= xHAT0 l1(x, x1) -> l0(x2, x3) :|: x1 = x3 && x = x2 l2(x4, x5) -> l0(x6, x7) :|: x8 = 0 && x7 = -1 + x5 && x9 = 1 && x6 = 0 l3(x10, x11) -> l2(x12, x13) :|: x11 = x13 && x10 = x12 Start term: l3(xHAT0, yHAT0) ---------------------------------------- (1) IRSFormatTransformerProof (EQUIVALENT) Reformatted IRS to match normalized format (transformed away non-linear left-hand sides, !=, / and %). ---------------------------------------- (2) Obligation: Rules: l0(xHAT0, yHAT0) -> l1(xHATpost, yHATpost) :|: yHAT0 = yHATpost && xHAT0 = xHATpost && 0 <= xHAT0 l1(x, x1) -> l0(x2, x3) :|: x1 = x3 && x = x2 l2(x4, x5) -> l0(x6, x7) :|: x8 = 0 && x7 = -1 + x5 && x9 = 1 && x6 = 0 l3(x10, x11) -> l2(x12, x13) :|: x11 = x13 && x10 = x12 Start term: l3(xHAT0, yHAT0) ---------------------------------------- (3) IRSwTTerminationDigraphProof (EQUIVALENT) Constructed termination digraph! Nodes: (1) l0(xHAT0, yHAT0) -> l1(xHATpost, yHATpost) :|: yHAT0 = yHATpost && xHAT0 = xHATpost && 0 <= xHAT0 (2) l1(x, x1) -> l0(x2, x3) :|: x1 = x3 && x = x2 (3) l2(x4, x5) -> l0(x6, x7) :|: x8 = 0 && x7 = -1 + x5 && x9 = 1 && x6 = 0 (4) l3(x10, x11) -> l2(x12, x13) :|: x11 = x13 && x10 = x12 Arcs: (1) -> (2) (2) -> (1) (3) -> (1) (4) -> (3) This digraph is fully evaluated! ---------------------------------------- (4) Obligation: Termination digraph: Nodes: (1) l0(xHAT0, yHAT0) -> l1(xHATpost, yHATpost) :|: yHAT0 = yHATpost && xHAT0 = xHATpost && 0 <= xHAT0 (2) l1(x, x1) -> l0(x2, x3) :|: x1 = x3 && x = x2 Arcs: (1) -> (2) (2) -> (1) This digraph is fully evaluated! ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: l0(x2:0, x3:0) -> l0(x2:0, x3:0) :|: x2:0 > -1 ---------------------------------------- (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: l0(x1, x2) -> l0(x1) ---------------------------------------- (8) Obligation: Rules: l0(x2:0) -> l0(x2:0) :|: x2:0 > -1 ---------------------------------------- (9) FilterProof (EQUIVALENT) Used the following sort dictionary for filtering: l0(INTEGER) Replaced non-predefined constructor symbols by 0. ---------------------------------------- (10) Obligation: Rules: l0(x2:0) -> l0(x2:0) :|: x2:0 > -1 ---------------------------------------- (11) IntTRSNonPeriodicNontermProof (COMPLETE) Normalized system to the following form: f(pc, x2:0) -> f(1, x2:0) :|: pc = 1 && x2:0 > -1 Proved unsatisfiability of the following formula, indicating that the system is never left after entering: (((run2_0 = ((1 * 1)) and run2_1 = ((run1_1 * 1))) and (((run1_0 * 1)) = ((1 * 1)) and ((run1_1 * 1)) > ((1 * -1)))) and !(((run2_0 * 1)) = ((1 * 1)) and ((run2_1 * 1)) > ((1 * -1)))) Proved satisfiability of the following formula, indicating that the system is entered at least once: ((run2_0 = ((1 * 1)) and run2_1 = ((run1_1 * 1))) and (((run1_0 * 1)) = ((1 * 1)) and ((run1_1 * 1)) > ((1 * -1)))) ---------------------------------------- (12) NO