YES proof of prog.inttrs # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given IRSwT could be proven: (0) IRSwT (1) IRSFormatTransformerProof [EQUIVALENT, 0 ms] (2) IRSwT (3) IRSwTTerminationDigraphProof [EQUIVALENT, 185 ms] (4) IRSwT (5) IntTRSCompressionProof [EQUIVALENT, 0 ms] (6) IRSwT (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (8) IRSwT (9) TempFilterProof [SOUND, 14 ms] (10) IntTRS (11) PolynomialOrderProcessor [EQUIVALENT, 0 ms] (12) YES ---------------------------------------- (0) Obligation: Rules: l0(pHAT0, xHAT0, yHAT0) -> l1(pHATpost, xHATpost, yHATpost) :|: yHAT0 = yHATpost && xHAT0 = xHATpost && pHATpost = 1 && xHAT0 <= 0 && yHAT0 <= 0 l0(x, x1, x2) -> l2(x3, x4, x5) :|: x1 = x4 && x = x3 && x5 = -1 + x2 && 1 <= x2 l2(x6, x7, x8) -> l0(x9, x10, x11) :|: x8 = x11 && x7 = x10 && x6 = x9 l3(x12, x13, x14) -> l2(x15, x16, x17) :|: x14 = x17 && x13 = x16 && x12 = x15 && x13 <= 0 l3(x18, x19, x20) -> l4(x21, x22, x23) :|: x20 = x23 && x19 = x22 && x21 = 1 + x18 && 1 <= x19 l5(x24, x25, x26) -> l3(x27, x28, x29) :|: x26 = x29 && x25 = x28 && x27 = 0 l6(x30, x31, x32) -> l5(x33, x34, x35) :|: x32 = x35 && x31 = x34 && x30 = x33 Start term: l6(pHAT0, xHAT0, yHAT0) ---------------------------------------- (1) IRSFormatTransformerProof (EQUIVALENT) Reformatted IRS to match normalized format (transformed away non-linear left-hand sides, !=, / and %). ---------------------------------------- (2) Obligation: Rules: l0(pHAT0, xHAT0, yHAT0) -> l1(pHATpost, xHATpost, yHATpost) :|: yHAT0 = yHATpost && xHAT0 = xHATpost && pHATpost = 1 && xHAT0 <= 0 && yHAT0 <= 0 l0(x, x1, x2) -> l2(x3, x4, x5) :|: x1 = x4 && x = x3 && x5 = -1 + x2 && 1 <= x2 l2(x6, x7, x8) -> l0(x9, x10, x11) :|: x8 = x11 && x7 = x10 && x6 = x9 l3(x12, x13, x14) -> l2(x15, x16, x17) :|: x14 = x17 && x13 = x16 && x12 = x15 && x13 <= 0 l3(x18, x19, x20) -> l4(x21, x22, x23) :|: x20 = x23 && x19 = x22 && x21 = 1 + x18 && 1 <= x19 l5(x24, x25, x26) -> l3(x27, x28, x29) :|: x26 = x29 && x25 = x28 && x27 = 0 l6(x30, x31, x32) -> l5(x33, x34, x35) :|: x32 = x35 && x31 = x34 && x30 = x33 Start term: l6(pHAT0, xHAT0, yHAT0) ---------------------------------------- (3) IRSwTTerminationDigraphProof (EQUIVALENT) Constructed termination digraph! Nodes: (1) l0(pHAT0, xHAT0, yHAT0) -> l1(pHATpost, xHATpost, yHATpost) :|: yHAT0 = yHATpost && xHAT0 = xHATpost && pHATpost = 1 && xHAT0 <= 0 && yHAT0 <= 0 (2) l0(x, x1, x2) -> l2(x3, x4, x5) :|: x1 = x4 && x = x3 && x5 = -1 + x2 && 1 <= x2 (3) l2(x6, x7, x8) -> l0(x9, x10, x11) :|: x8 = x11 && x7 = x10 && x6 = x9 (4) l3(x12, x13, x14) -> l2(x15, x16, x17) :|: x14 = x17 && x13 = x16 && x12 = x15 && x13 <= 0 (5) l3(x18, x19, x20) -> l4(x21, x22, x23) :|: x20 = x23 && x19 = x22 && x21 = 1 + x18 && 1 <= x19 (6) l5(x24, x25, x26) -> l3(x27, x28, x29) :|: x26 = x29 && x25 = x28 && x27 = 0 (7) l6(x30, x31, x32) -> l5(x33, x34, x35) :|: x32 = x35 && x31 = x34 && x30 = x33 Arcs: (2) -> (3) (3) -> (1), (2) (4) -> (3) (6) -> (4), (5) (7) -> (6) This digraph is fully evaluated! ---------------------------------------- (4) Obligation: Termination digraph: Nodes: (1) l0(x, x1, x2) -> l2(x3, x4, x5) :|: x1 = x4 && x = x3 && x5 = -1 + x2 && 1 <= x2 (2) l2(x6, x7, x8) -> l0(x9, x10, x11) :|: x8 = x11 && x7 = x10 && x6 = x9 Arcs: (1) -> (2) (2) -> (1) This digraph is fully evaluated! ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: l0(x3:0, x10:0, x2:0) -> l0(x3:0, x10:0, -1 + x2:0) :|: x2:0 > 0 ---------------------------------------- (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: l0(x1, x2, x3) -> l0(x3) ---------------------------------------- (8) Obligation: Rules: l0(x2:0) -> l0(-1 + x2:0) :|: x2:0 > 0 ---------------------------------------- (9) TempFilterProof (SOUND) Used the following sort dictionary for filtering: l0(INTEGER) Replaced non-predefined constructor symbols by 0. ---------------------------------------- (10) Obligation: Rules: l0(x2:0) -> l0(c) :|: c = -1 + x2:0 && x2:0 > 0 ---------------------------------------- (11) PolynomialOrderProcessor (EQUIVALENT) Found the following polynomial interpretation: [l0(x)] = x The following rules are decreasing: l0(x2:0) -> l0(c) :|: c = -1 + x2:0 && x2:0 > 0 The following rules are bounded: l0(x2:0) -> l0(c) :|: c = -1 + x2:0 && x2:0 > 0 ---------------------------------------- (12) YES