YES proof of prog.inttrs # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given IRSwT could be proven: (0) IRSwT (1) IRSFormatTransformerProof [EQUIVALENT, 0 ms] (2) IRSwT (3) IRSwTTerminationDigraphProof [EQUIVALENT, 189 ms] (4) AND (5) IRSwT (6) IntTRSCompressionProof [EQUIVALENT, 0 ms] (7) IRSwT (8) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (9) IRSwT (10) TempFilterProof [SOUND, 16 ms] (11) IntTRS (12) RankingReductionPairProof [EQUIVALENT, 0 ms] (13) YES (14) IRSwT (15) IntTRSCompressionProof [EQUIVALENT, 0 ms] (16) IRSwT (17) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (18) IRSwT (19) TempFilterProof [SOUND, 15 ms] (20) IntTRS (21) PolynomialOrderProcessor [EQUIVALENT, 0 ms] (22) YES ---------------------------------------- (0) Obligation: Rules: l0(iHAT0, jHAT0) -> l1(iHATpost, jHATpost) :|: iHAT0 = iHATpost && jHATpost = 0 && 2 <= iHAT0 l0(x, x1) -> l2(x2, x3) :|: x1 = x3 && x2 = 1 + x && 1 + x <= 2 l2(x4, x5) -> l0(x6, x7) :|: x5 = x7 && x4 = x6 l1(x8, x9) -> l3(x10, x11) :|: x9 = x11 && x8 = x10 l4(x12, x13) -> l5(x14, x15) :|: x13 = x15 && x12 = x14 l6(x16, x17) -> l4(x18, x19) :|: x17 = x19 && x16 = x18 l3(x20, x21) -> l6(x22, x23) :|: x21 = x23 && x20 = x22 && 2 <= x21 l3(x24, x25) -> l1(x26, x27) :|: x24 = x26 && x27 = 1 + x25 && 1 + x25 <= 2 l7(x28, x29) -> l2(x30, x31) :|: x29 = x31 && x30 = 0 l8(x32, x33) -> l7(x34, x35) :|: x33 = x35 && x32 = x34 Start term: l8(iHAT0, jHAT0) ---------------------------------------- (1) IRSFormatTransformerProof (EQUIVALENT) Reformatted IRS to match normalized format (transformed away non-linear left-hand sides, !=, / and %). ---------------------------------------- (2) Obligation: Rules: l0(iHAT0, jHAT0) -> l1(iHATpost, jHATpost) :|: iHAT0 = iHATpost && jHATpost = 0 && 2 <= iHAT0 l0(x, x1) -> l2(x2, x3) :|: x1 = x3 && x2 = 1 + x && 1 + x <= 2 l2(x4, x5) -> l0(x6, x7) :|: x5 = x7 && x4 = x6 l1(x8, x9) -> l3(x10, x11) :|: x9 = x11 && x8 = x10 l4(x12, x13) -> l5(x14, x15) :|: x13 = x15 && x12 = x14 l6(x16, x17) -> l4(x18, x19) :|: x17 = x19 && x16 = x18 l3(x20, x21) -> l6(x22, x23) :|: x21 = x23 && x20 = x22 && 2 <= x21 l3(x24, x25) -> l1(x26, x27) :|: x24 = x26 && x27 = 1 + x25 && 1 + x25 <= 2 l7(x28, x29) -> l2(x30, x31) :|: x29 = x31 && x30 = 0 l8(x32, x33) -> l7(x34, x35) :|: x33 = x35 && x32 = x34 Start term: l8(iHAT0, jHAT0) ---------------------------------------- (3) IRSwTTerminationDigraphProof (EQUIVALENT) Constructed termination digraph! Nodes: (1) l0(iHAT0, jHAT0) -> l1(iHATpost, jHATpost) :|: iHAT0 = iHATpost && jHATpost = 0 && 2 <= iHAT0 (2) l0(x, x1) -> l2(x2, x3) :|: x1 = x3 && x2 = 1 + x && 1 + x <= 2 (3) l2(x4, x5) -> l0(x6, x7) :|: x5 = x7 && x4 = x6 (4) l1(x8, x9) -> l3(x10, x11) :|: x9 = x11 && x8 = x10 (5) l4(x12, x13) -> l5(x14, x15) :|: x13 = x15 && x12 = x14 (6) l6(x16, x17) -> l4(x18, x19) :|: x17 = x19 && x16 = x18 (7) l3(x20, x21) -> l6(x22, x23) :|: x21 = x23 && x20 = x22 && 2 <= x21 (8) l3(x24, x25) -> l1(x26, x27) :|: x24 = x26 && x27 = 1 + x25 && 1 + x25 <= 2 (9) l7(x28, x29) -> l2(x30, x31) :|: x29 = x31 && x30 = 0 (10) l8(x32, x33) -> l7(x34, x35) :|: x33 = x35 && x32 = x34 Arcs: (1) -> (4) (2) -> (3) (3) -> (1), (2) (4) -> (7), (8) (6) -> (5) (7) -> (6) (8) -> (4) (9) -> (3) (10) -> (9) This digraph is fully evaluated! ---------------------------------------- (4) Complex Obligation (AND) ---------------------------------------- (5) Obligation: Termination digraph: Nodes: (1) l0(x, x1) -> l2(x2, x3) :|: x1 = x3 && x2 = 1 + x && 1 + x <= 2 (2) l2(x4, x5) -> l0(x6, x7) :|: x5 = x7 && x4 = x6 Arcs: (1) -> (2) (2) -> (1) This digraph is fully evaluated! ---------------------------------------- (6) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (7) Obligation: Rules: l0(x:0, x1:0) -> l0(1 + x:0, x1:0) :|: x:0 < 2 ---------------------------------------- (8) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: l0(x1, x2) -> l0(x1) ---------------------------------------- (9) Obligation: Rules: l0(x:0) -> l0(1 + x:0) :|: x:0 < 2 ---------------------------------------- (10) TempFilterProof (SOUND) Used the following sort dictionary for filtering: l0(INTEGER) Replaced non-predefined constructor symbols by 0. ---------------------------------------- (11) Obligation: Rules: l0(x:0) -> l0(c) :|: c = 1 + x:0 && x:0 < 2 ---------------------------------------- (12) RankingReductionPairProof (EQUIVALENT) Interpretation: [ l0 ] = -1*l0_1 The following rules are decreasing: l0(x:0) -> l0(c) :|: c = 1 + x:0 && x:0 < 2 The following rules are bounded: l0(x:0) -> l0(c) :|: c = 1 + x:0 && x:0 < 2 ---------------------------------------- (13) YES ---------------------------------------- (14) Obligation: Termination digraph: Nodes: (1) l1(x8, x9) -> l3(x10, x11) :|: x9 = x11 && x8 = x10 (2) l3(x24, x25) -> l1(x26, x27) :|: x24 = x26 && x27 = 1 + x25 && 1 + x25 <= 2 Arcs: (1) -> (2) (2) -> (1) This digraph is fully evaluated! ---------------------------------------- (15) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (16) Obligation: Rules: l1(x10:0, x11:0) -> l1(x10:0, 1 + x11:0) :|: x11:0 < 2 ---------------------------------------- (17) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: l1(x1, x2) -> l1(x2) ---------------------------------------- (18) Obligation: Rules: l1(x11:0) -> l1(1 + x11:0) :|: x11:0 < 2 ---------------------------------------- (19) TempFilterProof (SOUND) Used the following sort dictionary for filtering: l1(INTEGER) Replaced non-predefined constructor symbols by 0. ---------------------------------------- (20) Obligation: Rules: l1(x11:0) -> l1(c) :|: c = 1 + x11:0 && x11:0 < 2 ---------------------------------------- (21) PolynomialOrderProcessor (EQUIVALENT) Found the following polynomial interpretation: [l1(x)] = 1 - x The following rules are decreasing: l1(x11:0) -> l1(c) :|: c = 1 + x11:0 && x11:0 < 2 The following rules are bounded: l1(x11:0) -> l1(c) :|: c = 1 + x11:0 && x11:0 < 2 ---------------------------------------- (22) YES