YES proof of prog.inttrs # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given IRSwT could be proven: (0) IRSwT (1) IRSFormatTransformerProof [EQUIVALENT, 0 ms] (2) IRSwT (3) IRSwTTerminationDigraphProof [EQUIVALENT, 81 ms] (4) TRUE ---------------------------------------- (0) Obligation: Rules: l0(AHAT0, NBuffersHAT0, NLocBufferHAT0, RHAT0, istempHAT0) -> l1(AHATpost, NBuffersHATpost, NLocBufferHATpost, RHATpost, istempHATpost) :|: NBuffersHATpost = NBuffersHATpost && NLocBufferHATpost = NLocBufferHATpost && istempHATpost = istempHATpost && AHATpost = RHATpost && RHATpost = 0 l2(x, x1, x2, x3, x4) -> l0(x5, x6, x7, x8, x9) :|: x4 = x9 && x3 = x8 && x2 = x7 && x1 = x6 && x = x5 Start term: l2(AHAT0, NBuffersHAT0, NLocBufferHAT0, RHAT0, istempHAT0) ---------------------------------------- (1) IRSFormatTransformerProof (EQUIVALENT) Reformatted IRS to match normalized format (transformed away non-linear left-hand sides, !=, / and %). ---------------------------------------- (2) Obligation: Rules: l0(AHAT0, NBuffersHAT0, NLocBufferHAT0, RHAT0, istempHAT0) -> l1(AHATpost, NBuffersHATpost, NLocBufferHATpost, RHATpost, istempHATpost) :|: NBuffersHATpost = NBuffersHATpost && NLocBufferHATpost = NLocBufferHATpost && istempHATpost = istempHATpost && AHATpost = RHATpost && RHATpost = 0 l2(x, x1, x2, x3, x4) -> l0(x5, x6, x7, x8, x9) :|: x4 = x9 && x3 = x8 && x2 = x7 && x1 = x6 && x = x5 Start term: l2(AHAT0, NBuffersHAT0, NLocBufferHAT0, RHAT0, istempHAT0) ---------------------------------------- (3) IRSwTTerminationDigraphProof (EQUIVALENT) Constructed termination digraph! Nodes: (1) l0(AHAT0, NBuffersHAT0, NLocBufferHAT0, RHAT0, istempHAT0) -> l1(AHATpost, NBuffersHATpost, NLocBufferHATpost, RHATpost, istempHATpost) :|: NBuffersHATpost = NBuffersHATpost && NLocBufferHATpost = NLocBufferHATpost && istempHATpost = istempHATpost && AHATpost = RHATpost && RHATpost = 0 (2) l2(x, x1, x2, x3, x4) -> l0(x5, x6, x7, x8, x9) :|: x4 = x9 && x3 = x8 && x2 = x7 && x1 = x6 && x = x5 Arcs: (2) -> (1) This digraph is fully evaluated! ---------------------------------------- (4) TRUE