WORST_CASE(Omega(1),?) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, [ arg1==arg1P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, [ arg2==arg2P_2 ], cost: 1 12: f3 -> f4 : arg1'=arg1P_13, arg2'=arg2P_13, [ arg2>0 && arg1>0 && arg1 f4 : arg1'=arg1P_14, arg2'=arg2P_14, [ arg2>0 && arg1>0 && arg1>arg2 && arg1==arg1P_14 && arg2==arg2P_14 ], cost: 1 15: f3 -> f13 : arg1'=arg1P_16, arg2'=arg2P_16, [ arg1==arg2 && arg1==arg1P_16 && arg2==arg2P_16 ], cost: 1 16: f3 -> f13 : arg1'=arg1P_17, arg2'=arg2P_17, [ arg2<=0 && arg1==arg1P_17 && arg2==arg2P_17 ], cost: 1 17: f3 -> f13 : arg1'=arg1P_18, arg2'=arg2P_18, [ arg1<=0 && arg1==arg1P_18 && arg2==arg2P_18 ], cost: 1 2: f5 -> f8 : arg1'=arg1P_3, arg2'=arg2P_3, [ arg2P_3==-1+arg2 && arg1==arg1P_3 ], cost: 1 10: f8 -> f7 : arg1'=arg1P_11, arg2'=arg2P_11, [ arg1==arg1P_11 && arg2==arg2P_11 ], cost: 1 3: f9 -> f12 : arg1'=arg1P_4, arg2'=arg2P_4, [ arg1P_4==-1+arg1 && arg2==arg2P_4 ], cost: 1 6: f12 -> f11 : arg1'=arg1P_7, arg2'=arg2P_7, [ arg1==arg1P_7 && arg2==arg2P_7 ], cost: 1 4: f6 -> f9 : arg1'=arg1P_5, arg2'=arg2P_5, [ arg1 f10 : arg1'=arg1P_6, arg2'=arg2P_6, [ arg1>=arg2 && arg1==arg1P_6 && arg2==arg2P_6 ], cost: 1 7: f10 -> f11 : arg1'=arg1P_8, arg2'=arg2P_8, [ arg1==arg1P_8 && arg2==arg2P_8 ], cost: 1 11: f11 -> f7 : arg1'=arg1P_12, arg2'=arg2P_12, [ arg1==arg1P_12 && arg2==arg2P_12 ], cost: 1 8: f4 -> f5 : arg1'=arg1P_9, arg2'=arg2P_9, [ arg2 f6 : arg1'=arg1P_10, arg2'=arg2P_10, [ arg2>=arg1 && arg1==arg1P_10 && arg2==arg2P_10 ], cost: 1 14: f7 -> f3 : arg1'=arg1P_15, arg2'=arg2P_15, [ arg1==arg1P_15 && arg2==arg2P_15 ], cost: 1 18: __init -> f1 : arg1'=arg1P_19, arg2'=arg2P_19, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 18: __init -> f1 : arg1'=arg1P_19, arg2'=arg2P_19, [], cost: 1 Removed unreachable and leaf rules: Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, [ arg1==arg1P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, [ arg2==arg2P_2 ], cost: 1 12: f3 -> f4 : arg1'=arg1P_13, arg2'=arg2P_13, [ arg2>0 && arg1>0 && arg1 f4 : arg1'=arg1P_14, arg2'=arg2P_14, [ arg2>0 && arg1>0 && arg1>arg2 && arg1==arg1P_14 && arg2==arg2P_14 ], cost: 1 2: f5 -> f8 : arg1'=arg1P_3, arg2'=arg2P_3, [ arg2P_3==-1+arg2 && arg1==arg1P_3 ], cost: 1 10: f8 -> f7 : arg1'=arg1P_11, arg2'=arg2P_11, [ arg1==arg1P_11 && arg2==arg2P_11 ], cost: 1 3: f9 -> f12 : arg1'=arg1P_4, arg2'=arg2P_4, [ arg1P_4==-1+arg1 && arg2==arg2P_4 ], cost: 1 6: f12 -> f11 : arg1'=arg1P_7, arg2'=arg2P_7, [ arg1==arg1P_7 && arg2==arg2P_7 ], cost: 1 4: f6 -> f9 : arg1'=arg1P_5, arg2'=arg2P_5, [ arg1 f10 : arg1'=arg1P_6, arg2'=arg2P_6, [ arg1>=arg2 && arg1==arg1P_6 && arg2==arg2P_6 ], cost: 1 7: f10 -> f11 : arg1'=arg1P_8, arg2'=arg2P_8, [ arg1==arg1P_8 && arg2==arg2P_8 ], cost: 1 11: f11 -> f7 : arg1'=arg1P_12, arg2'=arg2P_12, [ arg1==arg1P_12 && arg2==arg2P_12 ], cost: 1 8: f4 -> f5 : arg1'=arg1P_9, arg2'=arg2P_9, [ arg2 f6 : arg1'=arg1P_10, arg2'=arg2P_10, [ arg2>=arg1 && arg1==arg1P_10 && arg2==arg2P_10 ], cost: 1 14: f7 -> f3 : arg1'=arg1P_15, arg2'=arg2P_15, [ arg1==arg1P_15 && arg2==arg2P_15 ], cost: 1 18: __init -> f1 : arg1'=arg1P_19, arg2'=arg2P_19, [], cost: 1 Simplified all rules, resulting in: Start location: __init 0: f1 -> f2 : arg2'=arg2P_1, [], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, [], cost: 1 12: f3 -> f4 : [ arg1>0 && arg1 f4 : [ arg2>0 && arg1>0 && arg1>arg2 ], cost: 1 2: f5 -> f8 : arg2'=-1+arg2, [], cost: 1 10: f8 -> f7 : [], cost: 1 3: f9 -> f12 : arg1'=-1+arg1, [], cost: 1 6: f12 -> f11 : [], cost: 1 4: f6 -> f9 : [ arg1 f10 : [ arg1>=arg2 ], cost: 1 7: f10 -> f11 : [], cost: 1 11: f11 -> f7 : [], cost: 1 8: f4 -> f5 : [ arg2 f6 : [ arg2>=arg1 ], cost: 1 14: f7 -> f3 : [], cost: 1 18: __init -> f1 : arg1'=arg1P_19, arg2'=arg2P_19, [], cost: 1 ### Simplification by acceleration and chaining ### Eliminated locations (on linear paths): Start location: __init 12: f3 -> f4 : [ arg1>0 && arg1 f4 : [ arg2>0 && arg1>0 && arg1>arg2 ], cost: 1 24: f6 -> f11 : [ arg1>=arg2 ], cost: 2 25: f6 -> f11 : arg1'=-1+arg1, [ arg1 f7 : [], cost: 1 9: f4 -> f6 : [ arg2>=arg1 ], cost: 1 22: f4 -> f7 : arg2'=-1+arg2, [ arg2 f3 : [], cost: 1 20: __init -> f3 : arg1'=arg1P_2, arg2'=arg2P_1, [], cost: 3 Eliminated locations (on tree-shaped paths): Start location: __init 26: f3 -> f6 : [ arg1>0 && arg1 f7 : arg2'=-1+arg2, [ arg2>0 && arg1>0 && arg1>arg2 ], cost: 4 28: f6 -> f7 : [ arg1>=arg2 ], cost: 3 29: f6 -> f7 : arg1'=-1+arg1, [ arg1 f3 : [], cost: 1 20: __init -> f3 : arg1'=arg1P_2, arg2'=arg2P_1, [], cost: 3 Eliminated locations (on tree-shaped paths): Start location: __init 31: f3 -> f3 : arg2'=-1+arg2, [ arg2>0 && arg1>0 && arg1>arg2 ], cost: 5 32: f3 -> f3 : arg1'=-1+arg1, [ arg1>0 && arg1 f3 : arg1'=arg1P_2, arg2'=arg2P_1, [], cost: 3 Accelerating simple loops of location 2. Accelerating the following rules: 31: f3 -> f3 : arg2'=-1+arg2, [ arg2>0 && arg1>0 && arg1>arg2 ], cost: 5 32: f3 -> f3 : arg1'=-1+arg1, [ arg1>0 && arg1 f3 : arg2'=0, [ arg1>0 && arg1>arg2 && arg2>=0 ], cost: 5*arg2 34: f3 -> f3 : arg1'=0, [ arg1=0 ], cost: 7*arg1 20: __init -> f3 : arg1'=arg1P_2, arg2'=arg2P_1, [], cost: 3 Chained accelerated rules (with incoming rules): Start location: __init 20: __init -> f3 : arg1'=arg1P_2, arg2'=arg2P_1, [], cost: 3 35: __init -> f3 : arg1'=arg1P_2, arg2'=0, [ arg1P_2>0 && arg1P_2>arg2P_1 && arg2P_1>=0 ], cost: 3+5*arg2P_1 36: __init -> f3 : arg1'=0, arg2'=arg2P_1, [ arg1P_2=0 ], cost: 3+7*arg1P_2 Removed unreachable locations (and leaf rules with constant cost): Start location: __init 35: __init -> f3 : arg1'=arg1P_2, arg2'=0, [ arg1P_2>0 && arg1P_2>arg2P_1 && arg2P_1>=0 ], cost: 3+5*arg2P_1 36: __init -> f3 : arg1'=0, arg2'=arg2P_1, [ arg1P_2=0 ], cost: 3+7*arg1P_2 ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: __init 35: __init -> f3 : arg1'=arg1P_2, arg2'=0, [ arg1P_2>0 && arg1P_2>arg2P_1 && arg2P_1>=0 ], cost: 3+5*arg2P_1 36: __init -> f3 : arg1'=0, arg2'=arg2P_1, [ arg1P_2=0 ], cost: 3+7*arg1P_2 Computing asymptotic complexity for rule 36 Resulting cost 0 has complexity: Unknown Computing asymptotic complexity for rule 35 Simplified the guard: 35: __init -> f3 : arg1'=arg1P_2, arg2'=0, [ arg1P_2>arg2P_1 && arg2P_1>=0 ], cost: 3+5*arg2P_1 Resulting cost 0 has complexity: Unknown Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Constant Cpx degree: 0 Solved cost: 1 Rule cost: 1 Rule guard: [] WORST_CASE(Omega(1),?)