WORST_CASE(Omega(1),?) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, arg4'=arg4P_1, [ 1==arg1P_1 && arg2==arg2P_1 && arg3==arg3P_1 && arg4==arg4P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, arg4'=arg4P_2, [ arg1==arg1P_2 && 0==arg2P_2 && arg3==arg3P_2 && arg4==arg4P_2 ], cost: 1 2: f3 -> f4 : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, arg4'=arg4P_3, [ arg1==arg1P_3 && arg2==arg2P_3 && arg4==arg4P_3 ], cost: 1 3: f4 -> f5 : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, arg4'=arg4P_4, [ arg1==arg1P_4 && arg2==arg2P_4 && arg3==arg3P_4 ], cost: 1 11: f5 -> f6 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, [ arg1<0 && arg1==arg1P_12 && arg2==arg2P_12 && arg3==arg3P_12 && arg4==arg4P_12 ], cost: 1 12: f5 -> f6 : arg1'=arg1P_13, arg2'=arg2P_13, arg3'=arg3P_13, arg4'=arg4P_13, [ arg1>0 && arg1==arg1P_13 && arg2==arg2P_13 && arg3==arg3P_13 && arg4==arg4P_13 ], cost: 1 14: f5 -> f13 : arg1'=arg1P_15, arg2'=arg2P_15, arg3'=arg3P_15, arg4'=arg4P_15, [ arg1==0 && arg1==arg1P_15 && arg2==arg2P_15 && arg3==arg3P_15 && arg4==arg4P_15 ], cost: 1 4: f7 -> f10 : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, arg4'=arg4P_5, [ 0==arg1P_5 && arg2==arg2P_5 && arg3==arg3P_5 && arg4==arg4P_5 ], cost: 1 7: f10 -> f9 : arg1'=arg1P_8, arg2'=arg2P_8, arg3'=arg3P_8, arg4'=arg4P_8, [ arg1==arg1P_8 && arg2==arg2P_8 && arg3==arg3P_8 && arg4==arg4P_8 ], cost: 1 5: f6 -> f7 : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, arg4'=arg4P_6, [ arg3>=arg4 && arg1==arg1P_6 && arg2==arg2P_6 && arg3==arg3P_6 && arg4==arg4P_6 ], cost: 1 6: f6 -> f8 : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, arg4'=arg4P_7, [ arg3 f9 : arg1'=arg1P_9, arg2'=arg2P_9, arg3'=arg3P_9, arg4'=arg4P_9, [ arg1==arg1P_9 && arg2==arg2P_9 && arg3==arg3P_9 && arg4==arg4P_9 ], cost: 1 9: f9 -> f11 : arg1'=arg1P_10, arg2'=arg2P_10, arg3'=arg3P_10, arg4'=arg4P_10, [ arg3P_10==1+arg3 && arg1==arg1P_10 && arg2==arg2P_10 && arg4==arg4P_10 ], cost: 1 10: f11 -> f12 : arg1'=arg1P_11, arg2'=arg2P_11, arg3'=arg3P_11, arg4'=arg4P_11, [ arg2P_11==1+arg2 && arg1==arg1P_11 && arg3==arg3P_11 && arg4==arg4P_11 ], cost: 1 13: f12 -> f5 : arg1'=arg1P_14, arg2'=arg2P_14, arg3'=arg3P_14, arg4'=arg4P_14, [ arg1==arg1P_14 && arg2==arg2P_14 && arg3==arg3P_14 && arg4==arg4P_14 ], cost: 1 15: __init -> f1 : arg1'=arg1P_16, arg2'=arg2P_16, arg3'=arg3P_16, arg4'=arg4P_16, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 15: __init -> f1 : arg1'=arg1P_16, arg2'=arg2P_16, arg3'=arg3P_16, arg4'=arg4P_16, [], cost: 1 Removed unreachable and leaf rules: Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, arg4'=arg4P_1, [ 1==arg1P_1 && arg2==arg2P_1 && arg3==arg3P_1 && arg4==arg4P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, arg4'=arg4P_2, [ arg1==arg1P_2 && 0==arg2P_2 && arg3==arg3P_2 && arg4==arg4P_2 ], cost: 1 2: f3 -> f4 : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, arg4'=arg4P_3, [ arg1==arg1P_3 && arg2==arg2P_3 && arg4==arg4P_3 ], cost: 1 3: f4 -> f5 : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, arg4'=arg4P_4, [ arg1==arg1P_4 && arg2==arg2P_4 && arg3==arg3P_4 ], cost: 1 11: f5 -> f6 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, [ arg1<0 && arg1==arg1P_12 && arg2==arg2P_12 && arg3==arg3P_12 && arg4==arg4P_12 ], cost: 1 12: f5 -> f6 : arg1'=arg1P_13, arg2'=arg2P_13, arg3'=arg3P_13, arg4'=arg4P_13, [ arg1>0 && arg1==arg1P_13 && arg2==arg2P_13 && arg3==arg3P_13 && arg4==arg4P_13 ], cost: 1 4: f7 -> f10 : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, arg4'=arg4P_5, [ 0==arg1P_5 && arg2==arg2P_5 && arg3==arg3P_5 && arg4==arg4P_5 ], cost: 1 7: f10 -> f9 : arg1'=arg1P_8, arg2'=arg2P_8, arg3'=arg3P_8, arg4'=arg4P_8, [ arg1==arg1P_8 && arg2==arg2P_8 && arg3==arg3P_8 && arg4==arg4P_8 ], cost: 1 5: f6 -> f7 : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, arg4'=arg4P_6, [ arg3>=arg4 && arg1==arg1P_6 && arg2==arg2P_6 && arg3==arg3P_6 && arg4==arg4P_6 ], cost: 1 6: f6 -> f8 : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, arg4'=arg4P_7, [ arg3 f9 : arg1'=arg1P_9, arg2'=arg2P_9, arg3'=arg3P_9, arg4'=arg4P_9, [ arg1==arg1P_9 && arg2==arg2P_9 && arg3==arg3P_9 && arg4==arg4P_9 ], cost: 1 9: f9 -> f11 : arg1'=arg1P_10, arg2'=arg2P_10, arg3'=arg3P_10, arg4'=arg4P_10, [ arg3P_10==1+arg3 && arg1==arg1P_10 && arg2==arg2P_10 && arg4==arg4P_10 ], cost: 1 10: f11 -> f12 : arg1'=arg1P_11, arg2'=arg2P_11, arg3'=arg3P_11, arg4'=arg4P_11, [ arg2P_11==1+arg2 && arg1==arg1P_11 && arg3==arg3P_11 && arg4==arg4P_11 ], cost: 1 13: f12 -> f5 : arg1'=arg1P_14, arg2'=arg2P_14, arg3'=arg3P_14, arg4'=arg4P_14, [ arg1==arg1P_14 && arg2==arg2P_14 && arg3==arg3P_14 && arg4==arg4P_14 ], cost: 1 15: __init -> f1 : arg1'=arg1P_16, arg2'=arg2P_16, arg3'=arg3P_16, arg4'=arg4P_16, [], cost: 1 Simplified all rules, resulting in: Start location: __init 0: f1 -> f2 : arg1'=1, [], cost: 1 1: f2 -> f3 : arg2'=0, [], cost: 1 2: f3 -> f4 : arg3'=arg3P_3, [], cost: 1 3: f4 -> f5 : arg4'=arg4P_4, [], cost: 1 11: f5 -> f6 : [ arg1<0 ], cost: 1 12: f5 -> f6 : [ arg1>0 ], cost: 1 4: f7 -> f10 : arg1'=0, [], cost: 1 7: f10 -> f9 : [], cost: 1 5: f6 -> f7 : [ arg3>=arg4 ], cost: 1 6: f6 -> f8 : [ arg3 f9 : [], cost: 1 9: f9 -> f11 : arg3'=1+arg3, [], cost: 1 10: f11 -> f12 : arg2'=1+arg2, [], cost: 1 13: f12 -> f5 : [], cost: 1 15: __init -> f1 : arg1'=arg1P_16, arg2'=arg2P_16, arg3'=arg3P_16, arg4'=arg4P_16, [], cost: 1 ### Simplification by acceleration and chaining ### Eliminated locations (on linear paths): Start location: __init 11: f5 -> f6 : [ arg1<0 ], cost: 1 12: f5 -> f6 : [ arg1>0 ], cost: 1 21: f6 -> f9 : [ arg3 f9 : arg1'=0, [ arg3>=arg4 ], cost: 3 24: f9 -> f5 : arg2'=1+arg2, arg3'=1+arg3, [], cost: 3 19: __init -> f5 : arg1'=1, arg2'=0, arg3'=arg3P_3, arg4'=arg4P_4, [], cost: 5 Eliminated locations (on tree-shaped paths): Start location: __init 25: f5 -> f9 : [ arg1<0 && arg3 f9 : arg1'=0, [ arg1<0 && arg3>=arg4 ], cost: 4 27: f5 -> f9 : [ arg1>0 && arg3 f9 : arg1'=0, [ arg1>0 && arg3>=arg4 ], cost: 4 24: f9 -> f5 : arg2'=1+arg2, arg3'=1+arg3, [], cost: 3 19: __init -> f5 : arg1'=1, arg2'=0, arg3'=arg3P_3, arg4'=arg4P_4, [], cost: 5 Eliminated locations (on tree-shaped paths): Start location: __init 29: f5 -> f5 : arg2'=1+arg2, arg3'=1+arg3, [ arg1<0 && arg3 f5 : arg1'=0, arg2'=1+arg2, arg3'=1+arg3, [ arg1<0 && arg3>=arg4 ], cost: 7 31: f5 -> f5 : arg2'=1+arg2, arg3'=1+arg3, [ arg1>0 && arg3 f5 : arg1'=0, arg2'=1+arg2, arg3'=1+arg3, [ arg1>0 && arg3>=arg4 ], cost: 7 19: __init -> f5 : arg1'=1, arg2'=0, arg3'=arg3P_3, arg4'=arg4P_4, [], cost: 5 Accelerating simple loops of location 4. Accelerating the following rules: 29: f5 -> f5 : arg2'=1+arg2, arg3'=1+arg3, [ arg1<0 && arg3 f5 : arg1'=0, arg2'=1+arg2, arg3'=1+arg3, [ arg1<0 && arg3>=arg4 ], cost: 7 31: f5 -> f5 : arg2'=1+arg2, arg3'=1+arg3, [ arg1>0 && arg3 f5 : arg1'=0, arg2'=1+arg2, arg3'=1+arg3, [ arg1>0 && arg3>=arg4 ], cost: 7 Accelerated rule 29 with backward acceleration, yielding the new rule 33. Failed to prove monotonicity of the guard of rule 30. Accelerated rule 31 with backward acceleration, yielding the new rule 34. Failed to prove monotonicity of the guard of rule 32. [accelerate] Nesting with 4 inner and 4 outer candidates Removing the simple loops: 29 31. Accelerated all simple loops using metering functions (where possible): Start location: __init 30: f5 -> f5 : arg1'=0, arg2'=1+arg2, arg3'=1+arg3, [ arg1<0 && arg3>=arg4 ], cost: 7 32: f5 -> f5 : arg1'=0, arg2'=1+arg2, arg3'=1+arg3, [ arg1>0 && arg3>=arg4 ], cost: 7 33: f5 -> f5 : arg2'=arg2-arg3+arg4, arg3'=arg4, [ arg1<0 && -arg3+arg4>=0 ], cost: -6*arg3+6*arg4 34: f5 -> f5 : arg2'=arg2-arg3+arg4, arg3'=arg4, [ arg1>0 && -arg3+arg4>=0 ], cost: -6*arg3+6*arg4 19: __init -> f5 : arg1'=1, arg2'=0, arg3'=arg3P_3, arg4'=arg4P_4, [], cost: 5 Chained accelerated rules (with incoming rules): Start location: __init 19: __init -> f5 : arg1'=1, arg2'=0, arg3'=arg3P_3, arg4'=arg4P_4, [], cost: 5 35: __init -> f5 : arg1'=0, arg2'=1, arg3'=1+arg3P_3, arg4'=arg4P_4, [ arg3P_3>=arg4P_4 ], cost: 12 36: __init -> f5 : arg1'=1, arg2'=arg4P_4-arg3P_3, arg3'=arg4P_4, arg4'=arg4P_4, [ arg4P_4-arg3P_3>=0 ], cost: 5+6*arg4P_4-6*arg3P_3 Removed unreachable locations (and leaf rules with constant cost): Start location: __init 36: __init -> f5 : arg1'=1, arg2'=arg4P_4-arg3P_3, arg3'=arg4P_4, arg4'=arg4P_4, [ arg4P_4-arg3P_3>=0 ], cost: 5+6*arg4P_4-6*arg3P_3 ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: __init 36: __init -> f5 : arg1'=1, arg2'=arg4P_4-arg3P_3, arg3'=arg4P_4, arg4'=arg4P_4, [ arg4P_4-arg3P_3>=0 ], cost: 5+6*arg4P_4-6*arg3P_3 Computing asymptotic complexity for rule 36 Resulting cost 0 has complexity: Unknown Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Constant Cpx degree: 0 Solved cost: 1 Rule cost: 1 Rule guard: [] WORST_CASE(Omega(1),?)