WORST_CASE(Omega(1),?) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, arg4'=arg4P_1, [ arg1==arg1P_1 && arg2==arg2P_1 && arg3==arg3P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, arg4'=arg4P_2, [ arg1==arg1P_2 && arg2==arg2P_2 && arg4==arg4P_2 ], cost: 1 14: f3 -> f4 : arg1'=arg1P_15, arg2'=arg2P_15, arg3'=arg3P_15, arg4'=arg4P_15, [ arg3>0 && arg4>arg3 && arg1==arg1P_15 && arg2==arg2P_15 && arg3==arg3P_15 && arg4==arg4P_15 ], cost: 1 15: f3 -> f5 : arg1'=arg1P_16, arg2'=arg2P_16, arg3'=arg3P_16, arg4'=arg4P_16, [ arg3<=0 && arg1==arg1P_16 && arg2==arg2P_16 && arg3==arg3P_16 && arg4==arg4P_16 ], cost: 1 16: f3 -> f5 : arg1'=arg1P_17, arg2'=arg2P_17, arg3'=arg3P_17, arg4'=arg4P_17, [ arg4<=arg3 && arg1==arg1P_17 && arg2==arg2P_17 && arg3==arg3P_17 && arg4==arg4P_17 ], cost: 1 2: f4 -> f7 : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, arg4'=arg4P_3, [ 0==arg1P_3 && arg2==arg2P_3 && arg3==arg3P_3 && arg4==arg4P_3 ], cost: 1 3: f7 -> f8 : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, arg4'=arg4P_4, [ arg1==arg1P_4 && 0==arg2P_4 && arg3==arg3P_4 && arg4==arg4P_4 ], cost: 1 11: f8 -> f9 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, [ arg1 f16 : arg1'=arg1P_14, arg2'=arg2P_14, arg3'=arg3P_14, arg4'=arg4P_14, [ arg1>=arg4 && arg1==arg1P_14 && arg2==arg2P_14 && arg3==arg3P_14 && arg4==arg4P_14 ], cost: 1 4: f10 -> f13 : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, arg4'=arg4P_5, [ arg2P_5==1+arg2 && arg1==arg1P_5 && arg3==arg3P_5 && arg4==arg4P_5 ], cost: 1 9: f13 -> f12 : arg1'=arg1P_10, arg2'=arg2P_10, arg3'=arg3P_10, arg4'=arg4P_10, [ arg1==arg1P_10 && arg2==arg2P_10 && arg3==arg3P_10 && arg4==arg4P_10 ], cost: 1 5: f11 -> f14 : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, arg4'=arg4P_6, [ arg1==arg1P_6 && 0==arg2P_6 && arg3==arg3P_6 && arg4==arg4P_6 ], cost: 1 6: f14 -> f15 : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, arg4'=arg4P_7, [ arg1P_7==1+arg1 && arg2==arg2P_7 && arg3==arg3P_7 && arg4==arg4P_7 ], cost: 1 10: f15 -> f12 : arg1'=arg1P_11, arg2'=arg2P_11, arg3'=arg3P_11, arg4'=arg4P_11, [ arg1==arg1P_11 && arg2==arg2P_11 && arg3==arg3P_11 && arg4==arg4P_11 ], cost: 1 7: f9 -> f10 : arg1'=arg1P_8, arg2'=arg2P_8, arg3'=arg3P_8, arg4'=arg4P_8, [ arg2 f11 : arg1'=arg1P_9, arg2'=arg2P_9, arg3'=arg3P_9, arg4'=arg4P_9, [ arg2>=arg3 && arg1==arg1P_9 && arg2==arg2P_9 && arg3==arg3P_9 && arg4==arg4P_9 ], cost: 1 12: f12 -> f8 : arg1'=arg1P_13, arg2'=arg2P_13, arg3'=arg3P_13, arg4'=arg4P_13, [ arg1==arg1P_13 && arg2==arg2P_13 && arg3==arg3P_13 && arg4==arg4P_13 ], cost: 1 17: f16 -> f6 : arg1'=arg1P_18, arg2'=arg2P_18, arg3'=arg3P_18, arg4'=arg4P_18, [ arg1==arg1P_18 && arg2==arg2P_18 && arg3==arg3P_18 && arg4==arg4P_18 ], cost: 1 18: f5 -> f6 : arg1'=arg1P_19, arg2'=arg2P_19, arg3'=arg3P_19, arg4'=arg4P_19, [ arg1==arg1P_19 && arg2==arg2P_19 && arg3==arg3P_19 && arg4==arg4P_19 ], cost: 1 19: __init -> f1 : arg1'=arg1P_20, arg2'=arg2P_20, arg3'=arg3P_20, arg4'=arg4P_20, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 19: __init -> f1 : arg1'=arg1P_20, arg2'=arg2P_20, arg3'=arg3P_20, arg4'=arg4P_20, [], cost: 1 Removed unreachable and leaf rules: Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, arg4'=arg4P_1, [ arg1==arg1P_1 && arg2==arg2P_1 && arg3==arg3P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, arg4'=arg4P_2, [ arg1==arg1P_2 && arg2==arg2P_2 && arg4==arg4P_2 ], cost: 1 14: f3 -> f4 : arg1'=arg1P_15, arg2'=arg2P_15, arg3'=arg3P_15, arg4'=arg4P_15, [ arg3>0 && arg4>arg3 && arg1==arg1P_15 && arg2==arg2P_15 && arg3==arg3P_15 && arg4==arg4P_15 ], cost: 1 2: f4 -> f7 : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, arg4'=arg4P_3, [ 0==arg1P_3 && arg2==arg2P_3 && arg3==arg3P_3 && arg4==arg4P_3 ], cost: 1 3: f7 -> f8 : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, arg4'=arg4P_4, [ arg1==arg1P_4 && 0==arg2P_4 && arg3==arg3P_4 && arg4==arg4P_4 ], cost: 1 11: f8 -> f9 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, [ arg1 f13 : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, arg4'=arg4P_5, [ arg2P_5==1+arg2 && arg1==arg1P_5 && arg3==arg3P_5 && arg4==arg4P_5 ], cost: 1 9: f13 -> f12 : arg1'=arg1P_10, arg2'=arg2P_10, arg3'=arg3P_10, arg4'=arg4P_10, [ arg1==arg1P_10 && arg2==arg2P_10 && arg3==arg3P_10 && arg4==arg4P_10 ], cost: 1 5: f11 -> f14 : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, arg4'=arg4P_6, [ arg1==arg1P_6 && 0==arg2P_6 && arg3==arg3P_6 && arg4==arg4P_6 ], cost: 1 6: f14 -> f15 : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, arg4'=arg4P_7, [ arg1P_7==1+arg1 && arg2==arg2P_7 && arg3==arg3P_7 && arg4==arg4P_7 ], cost: 1 10: f15 -> f12 : arg1'=arg1P_11, arg2'=arg2P_11, arg3'=arg3P_11, arg4'=arg4P_11, [ arg1==arg1P_11 && arg2==arg2P_11 && arg3==arg3P_11 && arg4==arg4P_11 ], cost: 1 7: f9 -> f10 : arg1'=arg1P_8, arg2'=arg2P_8, arg3'=arg3P_8, arg4'=arg4P_8, [ arg2 f11 : arg1'=arg1P_9, arg2'=arg2P_9, arg3'=arg3P_9, arg4'=arg4P_9, [ arg2>=arg3 && arg1==arg1P_9 && arg2==arg2P_9 && arg3==arg3P_9 && arg4==arg4P_9 ], cost: 1 12: f12 -> f8 : arg1'=arg1P_13, arg2'=arg2P_13, arg3'=arg3P_13, arg4'=arg4P_13, [ arg1==arg1P_13 && arg2==arg2P_13 && arg3==arg3P_13 && arg4==arg4P_13 ], cost: 1 19: __init -> f1 : arg1'=arg1P_20, arg2'=arg2P_20, arg3'=arg3P_20, arg4'=arg4P_20, [], cost: 1 Simplified all rules, resulting in: Start location: __init 0: f1 -> f2 : arg4'=arg4P_1, [], cost: 1 1: f2 -> f3 : arg3'=arg3P_2, [], cost: 1 14: f3 -> f4 : [ arg3>0 && arg4>arg3 ], cost: 1 2: f4 -> f7 : arg1'=0, [], cost: 1 3: f7 -> f8 : arg2'=0, [], cost: 1 11: f8 -> f9 : [ arg1 f13 : arg2'=1+arg2, [], cost: 1 9: f13 -> f12 : [], cost: 1 5: f11 -> f14 : arg2'=0, [], cost: 1 6: f14 -> f15 : arg1'=1+arg1, [], cost: 1 10: f15 -> f12 : [], cost: 1 7: f9 -> f10 : [ arg2 f11 : [ arg2>=arg3 ], cost: 1 12: f12 -> f8 : [], cost: 1 19: __init -> f1 : arg1'=arg1P_20, arg2'=arg2P_20, arg3'=arg3P_20, arg4'=arg4P_20, [], cost: 1 ### Simplification by acceleration and chaining ### Eliminated locations (on linear paths): Start location: __init 11: f8 -> f9 : [ arg1 f12 : arg2'=1+arg2, [ arg2 f12 : arg1'=1+arg1, arg2'=0, [ arg2>=arg3 ], cost: 4 12: f12 -> f8 : [], cost: 1 24: __init -> f8 : arg1'=0, arg2'=0, arg3'=arg3P_2, arg4'=arg4P_1, [ arg3P_2>0 && arg4P_1>arg3P_2 ], cost: 6 Eliminated locations (on tree-shaped paths): Start location: __init 30: f8 -> f12 : arg2'=1+arg2, [ arg1 f12 : arg1'=1+arg1, arg2'=0, [ arg1=arg3 ], cost: 5 12: f12 -> f8 : [], cost: 1 24: __init -> f8 : arg1'=0, arg2'=0, arg3'=arg3P_2, arg4'=arg4P_1, [ arg3P_2>0 && arg4P_1>arg3P_2 ], cost: 6 Eliminated locations (on tree-shaped paths): Start location: __init 32: f8 -> f8 : arg2'=1+arg2, [ arg1 f8 : arg1'=1+arg1, arg2'=0, [ arg1=arg3 ], cost: 6 24: __init -> f8 : arg1'=0, arg2'=0, arg3'=arg3P_2, arg4'=arg4P_1, [ arg3P_2>0 && arg4P_1>arg3P_2 ], cost: 6 Accelerating simple loops of location 5. Accelerating the following rules: 32: f8 -> f8 : arg2'=1+arg2, [ arg1 f8 : arg1'=1+arg1, arg2'=0, [ arg1=arg3 ], cost: 6 Accelerated rule 32 with backward acceleration, yielding the new rule 34. Failed to prove monotonicity of the guard of rule 33. [accelerate] Nesting with 2 inner and 2 outer candidates Nested simple loops 33 (outer loop) and 34 (inner loop) with Rule(5 | arg2>=arg3, arg3>=0, -1+arg4-arg1>=1, -1+arg4 f8 : arg2'=arg3, [ arg1=0 ], cost: -5*arg2+5*arg3 35: f8 -> f8 : arg1'=-1+arg4, arg2'=arg3, [ arg2>=arg3 && arg3>=0 && -1+arg4-arg1>=1 ], cost: -6+5*arg3*(-1+arg4-arg1)+6*arg4-6*arg1 36: f8 -> f8 : arg1'=-1+arg4, arg2'=arg3, [ -arg2+arg3>=0 && arg3>=0 && -1+arg4-arg1>=1 ], cost: -6-5*arg2+5*arg3*(-1+arg4-arg1)+5*arg3+6*arg4-6*arg1 24: __init -> f8 : arg1'=0, arg2'=0, arg3'=arg3P_2, arg4'=arg4P_1, [ arg3P_2>0 && arg4P_1>arg3P_2 ], cost: 6 Chained accelerated rules (with incoming rules): Start location: __init 24: __init -> f8 : arg1'=0, arg2'=0, arg3'=arg3P_2, arg4'=arg4P_1, [ arg3P_2>0 && arg4P_1>arg3P_2 ], cost: 6 37: __init -> f8 : arg1'=0, arg2'=arg3P_2, arg3'=arg3P_2, arg4'=arg4P_1, [ arg3P_2>0 && arg4P_1>arg3P_2 && 0 f8 : arg1'=-1+arg4P_1, arg2'=arg3P_2, arg3'=arg3P_2, arg4'=arg4P_1, [ arg3P_2>0 && arg4P_1>arg3P_2 && -1+arg4P_1>=1 ], cost: 6*arg4P_1+5*arg3P_2+5*arg3P_2*(-1+arg4P_1) Removed unreachable locations (and leaf rules with constant cost): Start location: __init 37: __init -> f8 : arg1'=0, arg2'=arg3P_2, arg3'=arg3P_2, arg4'=arg4P_1, [ arg3P_2>0 && arg4P_1>arg3P_2 && 0 f8 : arg1'=-1+arg4P_1, arg2'=arg3P_2, arg3'=arg3P_2, arg4'=arg4P_1, [ arg3P_2>0 && arg4P_1>arg3P_2 && -1+arg4P_1>=1 ], cost: 6*arg4P_1+5*arg3P_2+5*arg3P_2*(-1+arg4P_1) ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: __init 37: __init -> f8 : arg1'=0, arg2'=arg3P_2, arg3'=arg3P_2, arg4'=arg4P_1, [ arg3P_2>0 && arg4P_1>arg3P_2 && 0 f8 : arg1'=-1+arg4P_1, arg2'=arg3P_2, arg3'=arg3P_2, arg4'=arg4P_1, [ arg3P_2>0 && arg4P_1>arg3P_2 && -1+arg4P_1>=1 ], cost: 6*arg4P_1+5*arg3P_2+5*arg3P_2*(-1+arg4P_1) Computing asymptotic complexity for rule 38 Resulting cost 0 has complexity: Unknown Computing asymptotic complexity for rule 37 Resulting cost 0 has complexity: Unknown Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Constant Cpx degree: 0 Solved cost: 1 Rule cost: 1 Rule guard: [] WORST_CASE(Omega(1),?)