WORST_CASE(Omega(1),?) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, [ arg1P_1==-x_1_1 && arg2==arg2P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, [ arg2P_2==-x16_1 && arg1==arg1P_2 ], cost: 1 4: f3 -> f4 : arg1'=arg1P_5, arg2'=arg2P_5, [ arg1>arg2 && arg1==arg1P_5 && arg2==arg2P_5 ], cost: 1 6: f3 -> f7 : arg1'=arg1P_7, arg2'=arg2P_7, [ arg1<=arg2 && arg1==arg1P_7 && arg2==arg2P_7 ], cost: 1 2: f4 -> f5 : arg1'=arg1P_3, arg2'=arg2P_3, [ arg2P_3==arg2+arg1 && arg1==arg1P_3 ], cost: 1 3: f5 -> f6 : arg1'=arg1P_4, arg2'=arg2P_4, [ arg1P_4==1+arg1 && arg2==arg2P_4 ], cost: 1 5: f6 -> f3 : arg1'=arg1P_6, arg2'=arg2P_6, [ arg1==arg1P_6 && arg2==arg2P_6 ], cost: 1 7: __init -> f1 : arg1'=arg1P_8, arg2'=arg2P_8, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 7: __init -> f1 : arg1'=arg1P_8, arg2'=arg2P_8, [], cost: 1 Removed unreachable and leaf rules: Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, [ arg1P_1==-x_1_1 && arg2==arg2P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, [ arg2P_2==-x16_1 && arg1==arg1P_2 ], cost: 1 4: f3 -> f4 : arg1'=arg1P_5, arg2'=arg2P_5, [ arg1>arg2 && arg1==arg1P_5 && arg2==arg2P_5 ], cost: 1 2: f4 -> f5 : arg1'=arg1P_3, arg2'=arg2P_3, [ arg2P_3==arg2+arg1 && arg1==arg1P_3 ], cost: 1 3: f5 -> f6 : arg1'=arg1P_4, arg2'=arg2P_4, [ arg1P_4==1+arg1 && arg2==arg2P_4 ], cost: 1 5: f6 -> f3 : arg1'=arg1P_6, arg2'=arg2P_6, [ arg1==arg1P_6 && arg2==arg2P_6 ], cost: 1 7: __init -> f1 : arg1'=arg1P_8, arg2'=arg2P_8, [], cost: 1 Simplified all rules, resulting in: Start location: __init 0: f1 -> f2 : arg1'=-x_1_1, [], cost: 1 1: f2 -> f3 : arg2'=-x16_1, [], cost: 1 4: f3 -> f4 : [ arg1>arg2 ], cost: 1 2: f4 -> f5 : arg2'=arg2+arg1, [], cost: 1 3: f5 -> f6 : arg1'=1+arg1, [], cost: 1 5: f6 -> f3 : [], cost: 1 7: __init -> f1 : arg1'=arg1P_8, arg2'=arg2P_8, [], cost: 1 ### Simplification by acceleration and chaining ### Eliminated locations (on linear paths): Start location: __init 12: f3 -> f3 : arg1'=1+arg1, arg2'=arg2+arg1, [ arg1>arg2 ], cost: 4 9: __init -> f3 : arg1'=-x_1_1, arg2'=-x16_1, [], cost: 3 Accelerating simple loops of location 2. Accelerating the following rules: 12: f3 -> f3 : arg1'=1+arg1, arg2'=arg2+arg1, [ arg1>arg2 ], cost: 4 [test] deduced pseudo-invariant 1-arg1<=0, also trying -1+arg1<=-1 Accelerated rule 12 with backward acceleration, yielding the new rule 13. Accelerated rule 12 with backward acceleration, yielding the new rule 14. [accelerate] Nesting with 2 inner and 1 outer candidates Accelerated all simple loops using metering functions (where possible): Start location: __init 12: f3 -> f3 : arg1'=1+arg1, arg2'=arg2+arg1, [ arg1>arg2 ], cost: 4 13: f3 -> f3 : arg1'=k+arg1, arg2'=-1/2*k+arg2+1/2*k^2+k*arg1, [ 1-arg1<=0 && k>=0 && -1+k+arg1>1/2+1/2*(-1+k)^2-1/2*k+arg2+(-1+k)*arg1 ], cost: 4*k 14: f3 -> f3 : arg1'=1, arg2'=-1/2+arg2+1/2*(-1+arg1)^2+1/2*arg1-(-1+arg1)*arg1, [ arg1>arg2 && 1-arg1>=0 ], cost: 4-4*arg1 9: __init -> f3 : arg1'=-x_1_1, arg2'=-x16_1, [], cost: 3 Chained accelerated rules (with incoming rules): Start location: __init 9: __init -> f3 : arg1'=-x_1_1, arg2'=-x16_1, [], cost: 3 15: __init -> f3 : arg1'=1-x_1_1, arg2'=-x_1_1-x16_1, [ -x_1_1>-x16_1 ], cost: 7 16: __init -> f3 : arg1'=k-x_1_1, arg2'=-1/2*k+1/2*k^2-x16_1-k*x_1_1, [ 1+x_1_1<=0 && k>=0 && -1+k-x_1_1>1/2+1/2*(-1+k)^2-1/2*k-(-1+k)*x_1_1-x16_1 ], cost: 3+4*k 17: __init -> f3 : arg1'=1, arg2'=-1/2-1/2*x_1_1-(1+x_1_1)*x_1_1+1/2*(1+x_1_1)^2-x16_1, [ -x_1_1>-x16_1 && 1+x_1_1>=0 ], cost: 7+4*x_1_1 Removed unreachable locations (and leaf rules with constant cost): Start location: __init 16: __init -> f3 : arg1'=k-x_1_1, arg2'=-1/2*k+1/2*k^2-x16_1-k*x_1_1, [ 1+x_1_1<=0 && k>=0 && -1+k-x_1_1>1/2+1/2*(-1+k)^2-1/2*k-(-1+k)*x_1_1-x16_1 ], cost: 3+4*k 17: __init -> f3 : arg1'=1, arg2'=-1/2-1/2*x_1_1-(1+x_1_1)*x_1_1+1/2*(1+x_1_1)^2-x16_1, [ -x_1_1>-x16_1 && 1+x_1_1>=0 ], cost: 7+4*x_1_1 ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: __init 16: __init -> f3 : arg1'=k-x_1_1, arg2'=-1/2*k+1/2*k^2-x16_1-k*x_1_1, [ 1+x_1_1<=0 && k>=0 && -1+k-x_1_1>1/2+1/2*(-1+k)^2-1/2*k-(-1+k)*x_1_1-x16_1 ], cost: 3+4*k 17: __init -> f3 : arg1'=1, arg2'=-1/2-1/2*x_1_1-(1+x_1_1)*x_1_1+1/2*(1+x_1_1)^2-x16_1, [ -x_1_1>-x16_1 && 1+x_1_1>=0 ], cost: 7+4*x_1_1 Computing asymptotic complexity for rule 17 Resulting cost 0 has complexity: Unknown Computing asymptotic complexity for rule 16 Resulting cost 0 has complexity: Unknown Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Constant Cpx degree: 0 Solved cost: 1 Rule cost: 1 Rule guard: [] WORST_CASE(Omega(1),?)