NO ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, [], cost: 1 1: f2 -> f2 : arg1'=arg1P_2, [ arg1==arg1P_2 ], cost: 1 2: __init -> f1 : arg1'=arg1P_3, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 2: __init -> f1 : arg1'=arg1P_3, [], cost: 1 Simplified all rules, resulting in: Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, [], cost: 1 1: f2 -> f2 : [], cost: 1 2: __init -> f1 : arg1'=arg1P_3, [], cost: 1 ### Simplification by acceleration and chaining ### Accelerating simple loops of location 1. Accelerating the following rules: 1: f2 -> f2 : [], cost: 1 Accelerated rule 1 with non-termination, yielding the new rule 3. [accelerate] Nesting with 0 inner and 0 outer candidates Removing the simple loops: 1. Accelerated all simple loops using metering functions (where possible): Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, [], cost: 1 3: f2 -> [3] : [], cost: NONTERM 2: __init -> f1 : arg1'=arg1P_3, [], cost: 1 Chained accelerated rules (with incoming rules): Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, [], cost: 1 4: f1 -> [3] : [], cost: NONTERM 2: __init -> f1 : arg1'=arg1P_3, [], cost: 1 Removed unreachable locations (and leaf rules with constant cost): Start location: __init 4: f1 -> [3] : [], cost: NONTERM 2: __init -> f1 : arg1'=arg1P_3, [], cost: 1 Eliminated locations (on linear paths): Start location: __init 5: __init -> [3] : [], cost: NONTERM ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: __init 5: __init -> [3] : [], cost: NONTERM Computing asymptotic complexity for rule 5 Guard is satisfiable, yielding nontermination Resulting cost NONTERM has complexity: Nonterm Found new complexity Nonterm. Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Nonterm Cpx degree: Nonterm Solved cost: NONTERM Rule cost: NONTERM Rule guard: [] NO