WORST_CASE(Omega(1),?) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, arg4'=arg4P_1, arg5'=arg5P_1, [ arg1==arg1P_1 && arg3==arg3P_1 && arg4==arg4P_1 && arg5==arg5P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, arg4'=arg4P_2, arg5'=arg5P_2, [ arg1==arg1P_2 && arg2==arg2P_2 && arg4==arg4P_2 && arg5==arg5P_2 ], cost: 1 2: f3 -> f4 : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, arg4'=arg4P_3, arg5'=arg5P_3, [ arg1==arg1P_3 && arg2==arg2P_3 && arg3==arg3P_3 && arg5==arg5P_3 ], cost: 1 3: f4 -> f5 : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, arg4'=arg4P_4, arg5'=arg5P_4, [ arg1==arg1P_4 && arg2==arg2P_4 && arg3==arg3P_4 && arg4==arg4P_4 ], cost: 1 4: f5 -> f6 : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, arg4'=arg4P_5, arg5'=arg5P_5, [ 0==arg1P_5 && arg2==arg2P_5 && arg3==arg3P_5 && arg4==arg4P_5 && arg5==arg5P_5 ], cost: 1 10: f6 -> f7 : arg1'=arg1P_11, arg2'=arg2P_11, arg3'=arg3P_11, arg4'=arg4P_11, arg5'=arg5P_11, [ arg2<=100 && arg3<=arg4 && arg1==arg1P_11 && arg2==arg2P_11 && arg3==arg3P_11 && arg4==arg4P_11 && arg5==arg5P_11 ], cost: 1 12: f6 -> f13 : arg1'=arg1P_13, arg2'=arg2P_13, arg3'=arg3P_13, arg4'=arg4P_13, arg5'=arg5P_13, [ arg2>100 && arg1==arg1P_13 && arg2==arg2P_13 && arg3==arg3P_13 && arg4==arg4P_13 && arg5==arg5P_13 ], cost: 1 13: f6 -> f13 : arg1'=arg1P_14, arg2'=arg2P_14, arg3'=arg3P_14, arg4'=arg4P_14, arg5'=arg5P_14, [ arg3>arg4 && arg1==arg1P_14 && arg2==arg2P_14 && arg3==arg3P_14 && arg4==arg4P_14 && arg5==arg5P_14 ], cost: 1 5: f7 -> f8 : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, arg4'=arg4P_6, arg5'=arg5P_6, [ arg1==arg1P_6 && arg2==arg2P_6 && arg3==arg3P_6 && arg4==arg4P_6 && arg2==arg5P_6 ], cost: 1 6: f8 -> f9 : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, arg4'=arg4P_7, arg5'=arg5P_7, [ arg1==arg1P_7 && arg3==arg2P_7 && arg3==arg3P_7 && arg4==arg4P_7 && arg5==arg5P_7 ], cost: 1 7: f9 -> f10 : arg1'=arg1P_8, arg2'=arg2P_8, arg3'=arg3P_8, arg4'=arg4P_8, arg5'=arg5P_8, [ arg3P_8==1+arg5 && arg1==arg1P_8 && arg2==arg2P_8 && arg4==arg4P_8 && arg5==arg5P_8 ], cost: 1 8: f10 -> f11 : arg1'=arg1P_9, arg2'=arg2P_9, arg3'=arg3P_9, arg4'=arg4P_9, arg5'=arg5P_9, [ arg4P_9==-1+arg4 && arg1==arg1P_9 && arg2==arg2P_9 && arg3==arg3P_9 && arg5==arg5P_9 ], cost: 1 9: f11 -> f12 : arg1'=arg1P_10, arg2'=arg2P_10, arg3'=arg3P_10, arg4'=arg4P_10, arg5'=arg5P_10, [ arg1P_10==1+arg1 && arg2==arg2P_10 && arg3==arg3P_10 && arg4==arg4P_10 && arg5==arg5P_10 ], cost: 1 11: f12 -> f6 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, arg5'=arg5P_12, [ arg1==arg1P_12 && arg2==arg2P_12 && arg3==arg3P_12 && arg4==arg4P_12 && arg5==arg5P_12 ], cost: 1 14: __init -> f1 : arg1'=arg1P_15, arg2'=arg2P_15, arg3'=arg3P_15, arg4'=arg4P_15, arg5'=arg5P_15, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 14: __init -> f1 : arg1'=arg1P_15, arg2'=arg2P_15, arg3'=arg3P_15, arg4'=arg4P_15, arg5'=arg5P_15, [], cost: 1 Removed unreachable and leaf rules: Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, arg4'=arg4P_1, arg5'=arg5P_1, [ arg1==arg1P_1 && arg3==arg3P_1 && arg4==arg4P_1 && arg5==arg5P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, arg4'=arg4P_2, arg5'=arg5P_2, [ arg1==arg1P_2 && arg2==arg2P_2 && arg4==arg4P_2 && arg5==arg5P_2 ], cost: 1 2: f3 -> f4 : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, arg4'=arg4P_3, arg5'=arg5P_3, [ arg1==arg1P_3 && arg2==arg2P_3 && arg3==arg3P_3 && arg5==arg5P_3 ], cost: 1 3: f4 -> f5 : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, arg4'=arg4P_4, arg5'=arg5P_4, [ arg1==arg1P_4 && arg2==arg2P_4 && arg3==arg3P_4 && arg4==arg4P_4 ], cost: 1 4: f5 -> f6 : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, arg4'=arg4P_5, arg5'=arg5P_5, [ 0==arg1P_5 && arg2==arg2P_5 && arg3==arg3P_5 && arg4==arg4P_5 && arg5==arg5P_5 ], cost: 1 10: f6 -> f7 : arg1'=arg1P_11, arg2'=arg2P_11, arg3'=arg3P_11, arg4'=arg4P_11, arg5'=arg5P_11, [ arg2<=100 && arg3<=arg4 && arg1==arg1P_11 && arg2==arg2P_11 && arg3==arg3P_11 && arg4==arg4P_11 && arg5==arg5P_11 ], cost: 1 5: f7 -> f8 : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, arg4'=arg4P_6, arg5'=arg5P_6, [ arg1==arg1P_6 && arg2==arg2P_6 && arg3==arg3P_6 && arg4==arg4P_6 && arg2==arg5P_6 ], cost: 1 6: f8 -> f9 : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, arg4'=arg4P_7, arg5'=arg5P_7, [ arg1==arg1P_7 && arg3==arg2P_7 && arg3==arg3P_7 && arg4==arg4P_7 && arg5==arg5P_7 ], cost: 1 7: f9 -> f10 : arg1'=arg1P_8, arg2'=arg2P_8, arg3'=arg3P_8, arg4'=arg4P_8, arg5'=arg5P_8, [ arg3P_8==1+arg5 && arg1==arg1P_8 && arg2==arg2P_8 && arg4==arg4P_8 && arg5==arg5P_8 ], cost: 1 8: f10 -> f11 : arg1'=arg1P_9, arg2'=arg2P_9, arg3'=arg3P_9, arg4'=arg4P_9, arg5'=arg5P_9, [ arg4P_9==-1+arg4 && arg1==arg1P_9 && arg2==arg2P_9 && arg3==arg3P_9 && arg5==arg5P_9 ], cost: 1 9: f11 -> f12 : arg1'=arg1P_10, arg2'=arg2P_10, arg3'=arg3P_10, arg4'=arg4P_10, arg5'=arg5P_10, [ arg1P_10==1+arg1 && arg2==arg2P_10 && arg3==arg3P_10 && arg4==arg4P_10 && arg5==arg5P_10 ], cost: 1 11: f12 -> f6 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, arg5'=arg5P_12, [ arg1==arg1P_12 && arg2==arg2P_12 && arg3==arg3P_12 && arg4==arg4P_12 && arg5==arg5P_12 ], cost: 1 14: __init -> f1 : arg1'=arg1P_15, arg2'=arg2P_15, arg3'=arg3P_15, arg4'=arg4P_15, arg5'=arg5P_15, [], cost: 1 Simplified all rules, resulting in: Start location: __init 0: f1 -> f2 : arg2'=arg2P_1, [], cost: 1 1: f2 -> f3 : arg3'=arg3P_2, [], cost: 1 2: f3 -> f4 : arg4'=arg4P_3, [], cost: 1 3: f4 -> f5 : arg5'=arg5P_4, [], cost: 1 4: f5 -> f6 : arg1'=0, [], cost: 1 10: f6 -> f7 : [ arg2<=100 && arg3<=arg4 ], cost: 1 5: f7 -> f8 : arg5'=arg2, [], cost: 1 6: f8 -> f9 : arg2'=arg3, [], cost: 1 7: f9 -> f10 : arg3'=1+arg5, [], cost: 1 8: f10 -> f11 : arg4'=-1+arg4, [], cost: 1 9: f11 -> f12 : arg1'=1+arg1, [], cost: 1 11: f12 -> f6 : [], cost: 1 14: __init -> f1 : arg1'=arg1P_15, arg2'=arg2P_15, arg3'=arg3P_15, arg4'=arg4P_15, arg5'=arg5P_15, [], cost: 1 ### Simplification by acceleration and chaining ### Eliminated locations (on linear paths): Start location: __init 25: f6 -> f6 : arg1'=1+arg1, arg2'=arg3, arg3'=1+arg2, arg4'=-1+arg4, arg5'=arg2, [ arg2<=100 && arg3<=arg4 ], cost: 7 19: __init -> f6 : arg1'=0, arg2'=arg2P_1, arg3'=arg3P_2, arg4'=arg4P_3, arg5'=arg5P_4, [], cost: 6 Accelerating simple loops of location 5. Accelerating the following rules: 25: f6 -> f6 : arg1'=1+arg1, arg2'=arg3, arg3'=1+arg2, arg4'=-1+arg4, arg5'=arg2, [ arg2<=100 && arg3<=arg4 ], cost: 7 Accelerated rule 25 with backward acceleration, yielding the new rule 26. [accelerate] Nesting with 1 inner and 1 outer candidates Removing the simple loops: 25. Accelerated all simple loops using metering functions (where possible): Start location: __init 26: f6 -> f6 : arg1'=2*k+arg1, arg2'=arg2+k, arg3'=arg3+k, arg4'=-2*k+arg4, arg5'=-1+arg3+k, [ k>=1 && -1+arg2+k<=100 && -1+arg3+k<=2-2*k+arg4 && -1+arg3+k<=100 && arg2+k<=1-2*k+arg4 ], cost: 14*k 19: __init -> f6 : arg1'=0, arg2'=arg2P_1, arg3'=arg3P_2, arg4'=arg4P_3, arg5'=arg5P_4, [], cost: 6 Chained accelerated rules (with incoming rules): Start location: __init 19: __init -> f6 : arg1'=0, arg2'=arg2P_1, arg3'=arg3P_2, arg4'=arg4P_3, arg5'=arg5P_4, [], cost: 6 27: __init -> f6 : arg1'=2*k, arg2'=arg2P_1+k, arg3'=arg3P_2+k, arg4'=arg4P_3-2*k, arg5'=-1+arg3P_2+k, [ k>=1 && -1+arg2P_1+k<=100 && -1+arg3P_2+k<=2+arg4P_3-2*k && -1+arg3P_2+k<=100 && arg2P_1+k<=1+arg4P_3-2*k ], cost: 6+14*k Removed unreachable locations (and leaf rules with constant cost): Start location: __init 27: __init -> f6 : arg1'=2*k, arg2'=arg2P_1+k, arg3'=arg3P_2+k, arg4'=arg4P_3-2*k, arg5'=-1+arg3P_2+k, [ k>=1 && -1+arg2P_1+k<=100 && -1+arg3P_2+k<=2+arg4P_3-2*k && -1+arg3P_2+k<=100 && arg2P_1+k<=1+arg4P_3-2*k ], cost: 6+14*k ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: __init 27: __init -> f6 : arg1'=2*k, arg2'=arg2P_1+k, arg3'=arg3P_2+k, arg4'=arg4P_3-2*k, arg5'=-1+arg3P_2+k, [ k>=1 && -1+arg2P_1+k<=100 && -1+arg3P_2+k<=2+arg4P_3-2*k && -1+arg3P_2+k<=100 && arg2P_1+k<=1+arg4P_3-2*k ], cost: 6+14*k Computing asymptotic complexity for rule 27 Resulting cost 0 has complexity: Unknown Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Constant Cpx degree: 0 Solved cost: 1 Rule cost: 1 Rule guard: [] WORST_CASE(Omega(1),?)