WORST_CASE(Omega(1),?) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, arg4'=arg4P_1, [ arg2==arg2P_1 && arg3==arg3P_1 && arg4==arg4P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, arg4'=arg4P_2, [ arg1==arg1P_2 && arg3==arg3P_2 && arg4==arg4P_2 ], cost: 1 2: f3 -> f4 : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, arg4'=arg4P_3, [ arg1==arg1P_3 && arg2==arg2P_3 && arg4==arg4P_3 ], cost: 1 3: f4 -> f5 : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, arg4'=arg4P_4, [ arg1==arg1P_4 && arg2==arg2P_4 && arg3==arg3P_4 ], cost: 1 6: f5 -> f6 : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, arg4'=arg4P_7, [ arg1 f9 : arg1'=arg1P_9, arg2'=arg2P_9, arg3'=arg3P_9, arg4'=arg4P_9, [ arg1>=arg3 && arg1==arg1P_9 && arg2==arg2P_9 && arg3==arg3P_9 && arg4==arg4P_9 ], cost: 1 4: f6 -> f7 : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, arg4'=arg4P_5, [ arg2P_5==1+arg2 && arg1==arg1P_5 && arg3==arg3P_5 && arg4==arg4P_5 ], cost: 1 5: f7 -> f8 : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, arg4'=arg4P_6, [ arg1P_6==1+arg1 && arg2==arg2P_6 && arg3==arg3P_6 && arg4==arg4P_6 ], cost: 1 7: f8 -> f5 : arg1'=arg1P_8, arg2'=arg2P_8, arg3'=arg3P_8, arg4'=arg4P_8, [ arg1==arg1P_8 && arg2==arg2P_8 && arg3==arg3P_8 && arg4==arg4P_8 ], cost: 1 11: f9 -> f10 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, [ arg1 f13 : arg1'=arg1P_14, arg2'=arg2P_14, arg3'=arg3P_14, arg4'=arg4P_14, [ arg1>=arg4 && arg1==arg1P_14 && arg2==arg2P_14 && arg3==arg3P_14 && arg4==arg4P_14 ], cost: 1 9: f10 -> f11 : arg1'=arg1P_10, arg2'=arg2P_10, arg3'=arg3P_10, arg4'=arg4P_10, [ arg2P_10==1+arg2 && arg1==arg1P_10 && arg3==arg3P_10 && arg4==arg4P_10 ], cost: 1 10: f11 -> f12 : arg1'=arg1P_11, arg2'=arg2P_11, arg3'=arg3P_11, arg4'=arg4P_11, [ arg1P_11==1+arg1 && arg2==arg2P_11 && arg3==arg3P_11 && arg4==arg4P_11 ], cost: 1 12: f12 -> f9 : arg1'=arg1P_13, arg2'=arg2P_13, arg3'=arg3P_13, arg4'=arg4P_13, [ arg1==arg1P_13 && arg2==arg2P_13 && arg3==arg3P_13 && arg4==arg4P_13 ], cost: 1 14: __init -> f1 : arg1'=arg1P_15, arg2'=arg2P_15, arg3'=arg3P_15, arg4'=arg4P_15, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 14: __init -> f1 : arg1'=arg1P_15, arg2'=arg2P_15, arg3'=arg3P_15, arg4'=arg4P_15, [], cost: 1 Removed unreachable and leaf rules: Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, arg4'=arg4P_1, [ arg2==arg2P_1 && arg3==arg3P_1 && arg4==arg4P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, arg4'=arg4P_2, [ arg1==arg1P_2 && arg3==arg3P_2 && arg4==arg4P_2 ], cost: 1 2: f3 -> f4 : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, arg4'=arg4P_3, [ arg1==arg1P_3 && arg2==arg2P_3 && arg4==arg4P_3 ], cost: 1 3: f4 -> f5 : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, arg4'=arg4P_4, [ arg1==arg1P_4 && arg2==arg2P_4 && arg3==arg3P_4 ], cost: 1 6: f5 -> f6 : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, arg4'=arg4P_7, [ arg1 f9 : arg1'=arg1P_9, arg2'=arg2P_9, arg3'=arg3P_9, arg4'=arg4P_9, [ arg1>=arg3 && arg1==arg1P_9 && arg2==arg2P_9 && arg3==arg3P_9 && arg4==arg4P_9 ], cost: 1 4: f6 -> f7 : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, arg4'=arg4P_5, [ arg2P_5==1+arg2 && arg1==arg1P_5 && arg3==arg3P_5 && arg4==arg4P_5 ], cost: 1 5: f7 -> f8 : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, arg4'=arg4P_6, [ arg1P_6==1+arg1 && arg2==arg2P_6 && arg3==arg3P_6 && arg4==arg4P_6 ], cost: 1 7: f8 -> f5 : arg1'=arg1P_8, arg2'=arg2P_8, arg3'=arg3P_8, arg4'=arg4P_8, [ arg1==arg1P_8 && arg2==arg2P_8 && arg3==arg3P_8 && arg4==arg4P_8 ], cost: 1 11: f9 -> f10 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, [ arg1 f11 : arg1'=arg1P_10, arg2'=arg2P_10, arg3'=arg3P_10, arg4'=arg4P_10, [ arg2P_10==1+arg2 && arg1==arg1P_10 && arg3==arg3P_10 && arg4==arg4P_10 ], cost: 1 10: f11 -> f12 : arg1'=arg1P_11, arg2'=arg2P_11, arg3'=arg3P_11, arg4'=arg4P_11, [ arg1P_11==1+arg1 && arg2==arg2P_11 && arg3==arg3P_11 && arg4==arg4P_11 ], cost: 1 12: f12 -> f9 : arg1'=arg1P_13, arg2'=arg2P_13, arg3'=arg3P_13, arg4'=arg4P_13, [ arg1==arg1P_13 && arg2==arg2P_13 && arg3==arg3P_13 && arg4==arg4P_13 ], cost: 1 14: __init -> f1 : arg1'=arg1P_15, arg2'=arg2P_15, arg3'=arg3P_15, arg4'=arg4P_15, [], cost: 1 Simplified all rules, resulting in: Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, [], cost: 1 1: f2 -> f3 : arg2'=arg2P_2, [], cost: 1 2: f3 -> f4 : arg3'=arg3P_3, [], cost: 1 3: f4 -> f5 : arg4'=arg4P_4, [], cost: 1 6: f5 -> f6 : [ arg1 f9 : [ arg1>=arg3 ], cost: 1 4: f6 -> f7 : arg2'=1+arg2, [], cost: 1 5: f7 -> f8 : arg1'=1+arg1, [], cost: 1 7: f8 -> f5 : [], cost: 1 11: f9 -> f10 : [ arg1 f11 : arg2'=1+arg2, [], cost: 1 10: f11 -> f12 : arg1'=1+arg1, [], cost: 1 12: f12 -> f9 : [], cost: 1 14: __init -> f1 : arg1'=arg1P_15, arg2'=arg2P_15, arg3'=arg3P_15, arg4'=arg4P_15, [], cost: 1 ### Simplification by acceleration and chaining ### Eliminated locations (on linear paths): Start location: __init 8: f5 -> f9 : [ arg1>=arg3 ], cost: 1 21: f5 -> f5 : arg1'=1+arg1, arg2'=1+arg2, [ arg1 f9 : arg1'=1+arg1, arg2'=1+arg2, [ arg1 f5 : arg1'=arg1P_1, arg2'=arg2P_2, arg3'=arg3P_3, arg4'=arg4P_4, [], cost: 5 Accelerating simple loops of location 4. Accelerating the following rules: 21: f5 -> f5 : arg1'=1+arg1, arg2'=1+arg2, [ arg1 f9 : arg1'=1+arg1, arg2'=1+arg2, [ arg1 f9 : [ arg1>=arg3 ], cost: 1 25: f5 -> f5 : arg1'=arg3, arg2'=arg2+arg3-arg1, [ arg3-arg1>=0 ], cost: 4*arg3-4*arg1 26: f9 -> f9 : arg1'=arg4, arg2'=arg2+arg4-arg1, [ arg4-arg1>=0 ], cost: 4*arg4-4*arg1 18: __init -> f5 : arg1'=arg1P_1, arg2'=arg2P_2, arg3'=arg3P_3, arg4'=arg4P_4, [], cost: 5 Chained accelerated rules (with incoming rules): Start location: __init 8: f5 -> f9 : [ arg1>=arg3 ], cost: 1 28: f5 -> f9 : arg1'=arg4, arg2'=arg2+arg4-arg1, [ arg1>=arg3 && arg4-arg1>=0 ], cost: 1+4*arg4-4*arg1 18: __init -> f5 : arg1'=arg1P_1, arg2'=arg2P_2, arg3'=arg3P_3, arg4'=arg4P_4, [], cost: 5 27: __init -> f5 : arg1'=arg3P_3, arg2'=arg2P_2-arg1P_1+arg3P_3, arg3'=arg3P_3, arg4'=arg4P_4, [ -arg1P_1+arg3P_3>=0 ], cost: 5-4*arg1P_1+4*arg3P_3 Removed unreachable locations (and leaf rules with constant cost): Start location: __init 28: f5 -> f9 : arg1'=arg4, arg2'=arg2+arg4-arg1, [ arg1>=arg3 && arg4-arg1>=0 ], cost: 1+4*arg4-4*arg1 18: __init -> f5 : arg1'=arg1P_1, arg2'=arg2P_2, arg3'=arg3P_3, arg4'=arg4P_4, [], cost: 5 27: __init -> f5 : arg1'=arg3P_3, arg2'=arg2P_2-arg1P_1+arg3P_3, arg3'=arg3P_3, arg4'=arg4P_4, [ -arg1P_1+arg3P_3>=0 ], cost: 5-4*arg1P_1+4*arg3P_3 Eliminated locations (on tree-shaped paths): Start location: __init 29: __init -> f9 : arg1'=arg4P_4, arg2'=arg4P_4+arg2P_2-arg1P_1, arg3'=arg3P_3, arg4'=arg4P_4, [ arg1P_1>=arg3P_3 && arg4P_4-arg1P_1>=0 ], cost: 6+4*arg4P_4-4*arg1P_1 30: __init -> f9 : arg1'=arg4P_4, arg2'=arg4P_4+arg2P_2-arg1P_1, arg3'=arg3P_3, arg4'=arg4P_4, [ -arg1P_1+arg3P_3>=0 && arg4P_4-arg3P_3>=0 ], cost: 6+4*arg4P_4-4*arg1P_1 ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: __init 29: __init -> f9 : arg1'=arg4P_4, arg2'=arg4P_4+arg2P_2-arg1P_1, arg3'=arg3P_3, arg4'=arg4P_4, [ arg1P_1>=arg3P_3 && arg4P_4-arg1P_1>=0 ], cost: 6+4*arg4P_4-4*arg1P_1 30: __init -> f9 : arg1'=arg4P_4, arg2'=arg4P_4+arg2P_2-arg1P_1, arg3'=arg3P_3, arg4'=arg4P_4, [ -arg1P_1+arg3P_3>=0 && arg4P_4-arg3P_3>=0 ], cost: 6+4*arg4P_4-4*arg1P_1 Computing asymptotic complexity for rule 29 Resulting cost 0 has complexity: Unknown Computing asymptotic complexity for rule 30 Resulting cost 0 has complexity: Unknown Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Constant Cpx degree: 0 Solved cost: 1 Rule cost: 1 Rule guard: [] WORST_CASE(Omega(1),?)