WORST_CASE(Omega(1),?) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, arg4'=arg4P_1, [ arg1==arg1P_1 && arg3==arg3P_1 && arg4==arg4P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, arg4'=arg4P_2, [ arg1==arg1P_2 && arg2==arg2P_2 && arg4==arg4P_2 ], cost: 1 2: f3 -> f4 : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, arg4'=arg4P_3, [ arg1==arg1P_3 && arg2==arg2P_3 && arg3==arg3P_3 ], cost: 1 3: f4 -> f5 : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, arg4'=arg4P_4, [ 0==arg1P_4 && arg2==arg2P_4 && arg3==arg3P_4 && arg4==arg4P_4 ], cost: 1 7: f5 -> f6 : arg1'=arg1P_8, arg2'=arg2P_8, arg3'=arg3P_8, arg4'=arg4P_8, [ arg2>arg4 && arg3>arg4 && arg1==arg1P_8 && arg2==arg2P_8 && arg3==arg3P_8 && arg4==arg4P_8 ], cost: 1 9: f5 -> f10 : arg1'=arg1P_10, arg2'=arg2P_10, arg3'=arg3P_10, arg4'=arg4P_10, [ arg2<=arg4 && arg1==arg1P_10 && arg2==arg2P_10 && arg3==arg3P_10 && arg4==arg4P_10 ], cost: 1 10: f5 -> f10 : arg1'=arg1P_11, arg2'=arg2P_11, arg3'=arg3P_11, arg4'=arg4P_11, [ arg3<=arg4 && arg1==arg1P_11 && arg2==arg2P_11 && arg3==arg3P_11 && arg4==arg4P_11 ], cost: 1 4: f6 -> f7 : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, arg4'=arg4P_5, [ arg2P_5==-1+arg2 && arg1==arg1P_5 && arg3==arg3P_5 && arg4==arg4P_5 ], cost: 1 5: f7 -> f8 : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, arg4'=arg4P_6, [ arg3P_6==-1+arg3 && arg1==arg1P_6 && arg2==arg2P_6 && arg4==arg4P_6 ], cost: 1 6: f8 -> f9 : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, arg4'=arg4P_7, [ arg1P_7==1+arg1 && arg2==arg2P_7 && arg3==arg3P_7 && arg4==arg4P_7 ], cost: 1 8: f9 -> f5 : arg1'=arg1P_9, arg2'=arg2P_9, arg3'=arg3P_9, arg4'=arg4P_9, [ arg1==arg1P_9 && arg2==arg2P_9 && arg3==arg3P_9 && arg4==arg4P_9 ], cost: 1 11: __init -> f1 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 11: __init -> f1 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, [], cost: 1 Removed unreachable and leaf rules: Start location: __init 0: f1 -> f2 : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, arg4'=arg4P_1, [ arg1==arg1P_1 && arg3==arg3P_1 && arg4==arg4P_1 ], cost: 1 1: f2 -> f3 : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, arg4'=arg4P_2, [ arg1==arg1P_2 && arg2==arg2P_2 && arg4==arg4P_2 ], cost: 1 2: f3 -> f4 : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, arg4'=arg4P_3, [ arg1==arg1P_3 && arg2==arg2P_3 && arg3==arg3P_3 ], cost: 1 3: f4 -> f5 : arg1'=arg1P_4, arg2'=arg2P_4, arg3'=arg3P_4, arg4'=arg4P_4, [ 0==arg1P_4 && arg2==arg2P_4 && arg3==arg3P_4 && arg4==arg4P_4 ], cost: 1 7: f5 -> f6 : arg1'=arg1P_8, arg2'=arg2P_8, arg3'=arg3P_8, arg4'=arg4P_8, [ arg2>arg4 && arg3>arg4 && arg1==arg1P_8 && arg2==arg2P_8 && arg3==arg3P_8 && arg4==arg4P_8 ], cost: 1 4: f6 -> f7 : arg1'=arg1P_5, arg2'=arg2P_5, arg3'=arg3P_5, arg4'=arg4P_5, [ arg2P_5==-1+arg2 && arg1==arg1P_5 && arg3==arg3P_5 && arg4==arg4P_5 ], cost: 1 5: f7 -> f8 : arg1'=arg1P_6, arg2'=arg2P_6, arg3'=arg3P_6, arg4'=arg4P_6, [ arg3P_6==-1+arg3 && arg1==arg1P_6 && arg2==arg2P_6 && arg4==arg4P_6 ], cost: 1 6: f8 -> f9 : arg1'=arg1P_7, arg2'=arg2P_7, arg3'=arg3P_7, arg4'=arg4P_7, [ arg1P_7==1+arg1 && arg2==arg2P_7 && arg3==arg3P_7 && arg4==arg4P_7 ], cost: 1 8: f9 -> f5 : arg1'=arg1P_9, arg2'=arg2P_9, arg3'=arg3P_9, arg4'=arg4P_9, [ arg1==arg1P_9 && arg2==arg2P_9 && arg3==arg3P_9 && arg4==arg4P_9 ], cost: 1 11: __init -> f1 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, [], cost: 1 Simplified all rules, resulting in: Start location: __init 0: f1 -> f2 : arg2'=arg2P_1, [], cost: 1 1: f2 -> f3 : arg3'=arg3P_2, [], cost: 1 2: f3 -> f4 : arg4'=arg4P_3, [], cost: 1 3: f4 -> f5 : arg1'=0, [], cost: 1 7: f5 -> f6 : [ arg2>arg4 && arg3>arg4 ], cost: 1 4: f6 -> f7 : arg2'=-1+arg2, [], cost: 1 5: f7 -> f8 : arg3'=-1+arg3, [], cost: 1 6: f8 -> f9 : arg1'=1+arg1, [], cost: 1 8: f9 -> f5 : [], cost: 1 11: __init -> f1 : arg1'=arg1P_12, arg2'=arg2P_12, arg3'=arg3P_12, arg4'=arg4P_12, [], cost: 1 ### Simplification by acceleration and chaining ### Eliminated locations (on linear paths): Start location: __init 19: f5 -> f5 : arg1'=1+arg1, arg2'=-1+arg2, arg3'=-1+arg3, [ arg2>arg4 && arg3>arg4 ], cost: 5 15: __init -> f5 : arg1'=0, arg2'=arg2P_1, arg3'=arg3P_2, arg4'=arg4P_3, [], cost: 5 Accelerating simple loops of location 4. Accelerating the following rules: 19: f5 -> f5 : arg1'=1+arg1, arg2'=-1+arg2, arg3'=-1+arg3, [ arg2>arg4 && arg3>arg4 ], cost: 5 Accelerated rule 19 with backward acceleration, yielding the new rule 20. Accelerated rule 19 with backward acceleration, yielding the new rule 21. [accelerate] Nesting with 2 inner and 1 outer candidates Removing the simple loops: 19. Accelerated all simple loops using metering functions (where possible): Start location: __init 20: f5 -> f5 : arg1'=arg2-arg4+arg1, arg2'=arg4, arg3'=-arg2+arg3+arg4, [ arg2-arg4>=0 && 1-arg2+arg3+arg4>arg4 ], cost: 5*arg2-5*arg4 21: f5 -> f5 : arg1'=arg3-arg4+arg1, arg2'=arg2-arg3+arg4, arg3'=arg4, [ arg3-arg4>=0 && 1+arg2-arg3+arg4>arg4 ], cost: 5*arg3-5*arg4 15: __init -> f5 : arg1'=0, arg2'=arg2P_1, arg3'=arg3P_2, arg4'=arg4P_3, [], cost: 5 Chained accelerated rules (with incoming rules): Start location: __init 15: __init -> f5 : arg1'=0, arg2'=arg2P_1, arg3'=arg3P_2, arg4'=arg4P_3, [], cost: 5 22: __init -> f5 : arg1'=-arg4P_3+arg2P_1, arg2'=arg4P_3, arg3'=arg3P_2+arg4P_3-arg2P_1, arg4'=arg4P_3, [ -arg4P_3+arg2P_1>=0 && 1+arg3P_2+arg4P_3-arg2P_1>arg4P_3 ], cost: 5-5*arg4P_3+5*arg2P_1 23: __init -> f5 : arg1'=arg3P_2-arg4P_3, arg2'=-arg3P_2+arg4P_3+arg2P_1, arg3'=arg4P_3, arg4'=arg4P_3, [ arg3P_2-arg4P_3>=0 && 1-arg3P_2+arg4P_3+arg2P_1>arg4P_3 ], cost: 5+5*arg3P_2-5*arg4P_3 Removed unreachable locations (and leaf rules with constant cost): Start location: __init 22: __init -> f5 : arg1'=-arg4P_3+arg2P_1, arg2'=arg4P_3, arg3'=arg3P_2+arg4P_3-arg2P_1, arg4'=arg4P_3, [ -arg4P_3+arg2P_1>=0 && 1+arg3P_2+arg4P_3-arg2P_1>arg4P_3 ], cost: 5-5*arg4P_3+5*arg2P_1 23: __init -> f5 : arg1'=arg3P_2-arg4P_3, arg2'=-arg3P_2+arg4P_3+arg2P_1, arg3'=arg4P_3, arg4'=arg4P_3, [ arg3P_2-arg4P_3>=0 && 1-arg3P_2+arg4P_3+arg2P_1>arg4P_3 ], cost: 5+5*arg3P_2-5*arg4P_3 ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: __init 22: __init -> f5 : arg1'=-arg4P_3+arg2P_1, arg2'=arg4P_3, arg3'=arg3P_2+arg4P_3-arg2P_1, arg4'=arg4P_3, [ -arg4P_3+arg2P_1>=0 && 1+arg3P_2+arg4P_3-arg2P_1>arg4P_3 ], cost: 5-5*arg4P_3+5*arg2P_1 23: __init -> f5 : arg1'=arg3P_2-arg4P_3, arg2'=-arg3P_2+arg4P_3+arg2P_1, arg3'=arg4P_3, arg4'=arg4P_3, [ arg3P_2-arg4P_3>=0 && 1-arg3P_2+arg4P_3+arg2P_1>arg4P_3 ], cost: 5+5*arg3P_2-5*arg4P_3 Computing asymptotic complexity for rule 22 Resulting cost 0 has complexity: Unknown Computing asymptotic complexity for rule 23 Resulting cost 0 has complexity: Unknown Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Constant Cpx degree: 0 Solved cost: 1 Rule cost: 1 Rule guard: [] WORST_CASE(Omega(1),?)