WORST_CASE(Omega(1),?)

### Pre-processing the ITS problem ###

Initial linear ITS problem
   Start location: __init
      0: f1_0_main_Load -> f157_0_log_LE : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2>-1 && arg1P_1>-1 && arg1>0 ], cost: 1
      1: f157_0_log_LE -> f157_0_log_LE\' : arg1'=arg1P_2, arg2'=arg2P_2, [ arg1>1 && arg1>x5_1 && arg1==arg1P_2 ], cost: 1
      2: f157_0_log_LE\' -> f157_0_log_LE : arg1'=arg1P_3, arg2'=arg2P_3, [ arg1>arg1P_3 && arg1>1 && arg1-2*arg1P_3<2 && arg1-2*arg1P_3>=0 ], cost: 1
      3: __init -> f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1

Checking for constant complexity:
   The following rule is satisfiable with cost >= 1, yielding constant complexity:
      3: __init -> f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1

Simplified all rules, resulting in:
   Start location: __init
      0: f1_0_main_Load -> f157_0_log_LE : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2>-1 && arg1P_1>-1 && arg1>0 ], cost: 1
      1: f157_0_log_LE -> f157_0_log_LE\' : arg2'=arg2P_2, [ arg1>1 ], cost: 1
      2: f157_0_log_LE\' -> f157_0_log_LE : arg1'=arg1P_3, arg2'=arg2P_3, [ arg1>1 && arg1-2*arg1P_3<2 && arg1-2*arg1P_3>=0 ], cost: 1
      3: __init -> f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1

### Simplification by acceleration and chaining ###

Eliminated locations (on linear paths):
   Start location: __init
      5: f157_0_log_LE -> f157_0_log_LE : arg1'=arg1P_3, arg2'=arg2P_3, [ arg1>1 && arg1-2*arg1P_3<2 && arg1-2*arg1P_3>=0 ], cost: 2
      4: __init -> f157_0_log_LE : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2P_4>-1 && arg1P_1>-1 && arg1P_4>0 ], cost: 2

Accelerating simple loops of location 1.
   Accelerating the following rules:
      5: f157_0_log_LE -> f157_0_log_LE : arg1'=arg1P_3, arg2'=arg2P_3, [ arg1>1 && arg1-2*arg1P_3<2 && arg1-2*arg1P_3>=0 ], cost: 2

   Failed to prove monotonicity of the guard of rule 5.
[accelerate] Nesting with 1 inner and 1 outer candidates

Accelerated all simple loops using metering functions (where possible):
   Start location: __init
      5: f157_0_log_LE -> f157_0_log_LE : arg1'=arg1P_3, arg2'=arg2P_3, [ arg1>1 && arg1-2*arg1P_3<2 && arg1-2*arg1P_3>=0 ], cost: 2
      4: __init -> f157_0_log_LE : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2P_4>-1 && arg1P_1>-1 && arg1P_4>0 ], cost: 2

Chained accelerated rules (with incoming rules):
   Start location: __init
      4: __init -> f157_0_log_LE : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2P_4>-1 && arg1P_1>-1 && arg1P_4>0 ], cost: 2
      6: __init -> f157_0_log_LE : arg1'=arg1P_3, arg2'=arg2P_3, [ 2<=1+2*arg1P_3 ], cost: 4

Removed unreachable locations (and leaf rules with constant cost):
   Start location: __init
     <empty>

### Computing asymptotic complexity ###

Fully simplified ITS problem
   Start location: __init
     <empty>

Obtained the following overall complexity (w.r.t. the length of the input n):
   Complexity:  Constant
   Cpx degree:  0
   Solved cost: 1
   Rule cost:   1
   Rule guard:  []

WORST_CASE(Omega(1),?)