WORST_CASE(Omega(1),?)

### Pre-processing the ITS problem ###

Initial linear ITS problem
   Start location: __init
      0: f1_0_main_Load -> f168_0_main_EQ : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2>-1 && arg1P_1>0 && arg2P_1>0 && arg1>0 ], cost: 1
      1: f168_0_main_EQ -> f168_0_main_EQ : arg1'=arg1P_2, arg2'=arg2P_2, [ arg2>0 && arg1>0 && arg2>arg1 && arg1==arg1P_2 && arg2-arg1==arg2P_2 ], cost: 1
      2: f168_0_main_EQ -> f168_0_main_EQ : arg1'=arg1P_3, arg2'=arg2P_3, [ arg1>0 && arg2>0 && arg2<arg1 && -arg2+arg1==arg1P_3 && arg2==arg2P_3 ], cost: 1
      3: __init -> f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1

Checking for constant complexity:
   The following rule is satisfiable with cost >= 1, yielding constant complexity:
      3: __init -> f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1

Simplified all rules, resulting in:
   Start location: __init
      0: f1_0_main_Load -> f168_0_main_EQ : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2>-1 && arg1P_1>0 && arg2P_1>0 && arg1>0 ], cost: 1
      1: f168_0_main_EQ -> f168_0_main_EQ : arg2'=arg2-arg1, [ arg1>0 && arg2>arg1 ], cost: 1
      2: f168_0_main_EQ -> f168_0_main_EQ : arg1'=-arg2+arg1, [ arg2>0 && arg2<arg1 ], cost: 1
      3: __init -> f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1

### Simplification by acceleration and chaining ###

Accelerating simple loops of location 1.
   Accelerating the following rules:
      1: f168_0_main_EQ -> f168_0_main_EQ : arg2'=arg2-arg1, [ arg1>0 && arg2>arg1 ], cost: 1
      2: f168_0_main_EQ -> f168_0_main_EQ : arg1'=-arg2+arg1, [ arg2>0 && arg2<arg1 ], cost: 1

   Accelerated rule 1 with backward acceleration, yielding the new rule 4.
   Accelerated rule 2 with backward acceleration, yielding the new rule 5.
[accelerate] Nesting with 2 inner and 2 outer candidates
   Removing the simple loops: 1 2.

Accelerated all simple loops using metering functions (where possible):
   Start location: __init
      0: f1_0_main_Load -> f168_0_main_EQ : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2>-1 && arg1P_1>0 && arg2P_1>0 && arg1>0 ], cost: 1
      4: f168_0_main_EQ -> f168_0_main_EQ : arg2'=arg2-k*arg1, [ arg1>0 && k>=0 && -(-1+k)*arg1+arg2>arg1 ], cost: k
      5: f168_0_main_EQ -> f168_0_main_EQ : arg1'=-arg2*k_1+arg1, [ arg2>0 && k_1>=0 && arg2<-arg2*(-1+k_1)+arg1 ], cost: k_1
      3: __init -> f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1

Chained accelerated rules (with incoming rules):
   Start location: __init
      0: f1_0_main_Load -> f168_0_main_EQ : arg1'=arg1P_1, arg2'=arg2P_1, [ arg2>-1 && arg1P_1>0 && arg2P_1>0 && arg1>0 ], cost: 1
      6: f1_0_main_Load -> f168_0_main_EQ : arg1'=arg1P_1, arg2'=-arg1P_1*k+arg2P_1, [ arg2>-1 && arg1P_1>0 && arg2P_1>0 && arg1>0 && k>=0 && arg2P_1-arg1P_1*(-1+k)>arg1P_1 ], cost: 1+k
      7: f1_0_main_Load -> f168_0_main_EQ : arg1'=arg1P_1-k_1*arg2P_1, arg2'=arg2P_1, [ arg2>-1 && arg1P_1>0 && arg2P_1>0 && arg1>0 && k_1>=0 && arg2P_1<arg1P_1-arg2P_1*(-1+k_1) ], cost: 1+k_1
      3: __init -> f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1

Removed unreachable locations (and leaf rules with constant cost):
   Start location: __init
      6: f1_0_main_Load -> f168_0_main_EQ : arg1'=arg1P_1, arg2'=-arg1P_1*k+arg2P_1, [ arg2>-1 && arg1P_1>0 && arg2P_1>0 && arg1>0 && k>=0 && arg2P_1-arg1P_1*(-1+k)>arg1P_1 ], cost: 1+k
      7: f1_0_main_Load -> f168_0_main_EQ : arg1'=arg1P_1-k_1*arg2P_1, arg2'=arg2P_1, [ arg2>-1 && arg1P_1>0 && arg2P_1>0 && arg1>0 && k_1>=0 && arg2P_1<arg1P_1-arg2P_1*(-1+k_1) ], cost: 1+k_1
      3: __init -> f1_0_main_Load : arg1'=arg1P_4, arg2'=arg2P_4, [], cost: 1

Eliminated locations (on tree-shaped paths):
   Start location: __init
      8: __init -> f168_0_main_EQ : arg1'=arg1P_1, arg2'=-arg1P_1*k+arg2P_1, [ arg2P_4>-1 && arg1P_1>0 && arg2P_1>0 && arg1P_4>0 && k>=0 && arg2P_1-arg1P_1*(-1+k)>arg1P_1 ], cost: 2+k
      9: __init -> f168_0_main_EQ : arg1'=arg1P_1-k_1*arg2P_1, arg2'=arg2P_1, [ arg2P_4>-1 && arg1P_1>0 && arg2P_1>0 && arg1P_4>0 && k_1>=0 && arg2P_1<arg1P_1-arg2P_1*(-1+k_1) ], cost: 2+k_1

### Computing asymptotic complexity ###

Fully simplified ITS problem
   Start location: __init
      8: __init -> f168_0_main_EQ : arg1'=arg1P_1, arg2'=-arg1P_1*k+arg2P_1, [ arg2P_4>-1 && arg1P_1>0 && arg2P_1>0 && arg1P_4>0 && k>=0 && arg2P_1-arg1P_1*(-1+k)>arg1P_1 ], cost: 2+k
      9: __init -> f168_0_main_EQ : arg1'=arg1P_1-k_1*arg2P_1, arg2'=arg2P_1, [ arg2P_4>-1 && arg1P_1>0 && arg2P_1>0 && arg1P_4>0 && k_1>=0 && arg2P_1<arg1P_1-arg2P_1*(-1+k_1) ], cost: 2+k_1

Computing asymptotic complexity for rule 8
   Resulting cost 0 has complexity: Unknown

Computing asymptotic complexity for rule 9
   Simplified the guard:
      9: __init -> f168_0_main_EQ : arg1'=arg1P_1-k_1*arg2P_1, arg2'=arg2P_1, [ arg2P_4>-1 && arg2P_1>0 && arg1P_4>0 && k_1>=0 && arg2P_1<arg1P_1-arg2P_1*(-1+k_1) ], cost: 2+k_1
   Resulting cost 0 has complexity: Unknown

Obtained the following overall complexity (w.r.t. the length of the input n):
   Complexity:  Constant
   Cpx degree:  0
   Solved cost: 1
   Rule cost:   1
   Rule guard:  []

WORST_CASE(Omega(1),?)