NO ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: __init 0: f34_0_loop_Inc -> f34_0_loop_Inc : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg1P_1<=arg1 && arg1>0 && arg1P_1>0 && 1+arg2==arg2P_1 && arg3==arg3P_1 ], cost: 1 1: f1_0_main_Load -> f34_0_loop_Inc : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, [ arg1P_2<=arg1 && arg2>-1 && arg1>0 && arg1P_2>0 && 1+arg2==arg2P_2 && arg2==arg3P_2 ], cost: 1 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 Simplified all rules, resulting in: Start location: __init 0: f34_0_loop_Inc -> f34_0_loop_Inc : arg1'=arg1P_1, arg2'=1+arg2, [ arg1P_1<=arg1 && arg1>0 && arg1P_1>0 ], cost: 1 1: f1_0_main_Load -> f34_0_loop_Inc : arg1'=arg1P_2, arg2'=1+arg2, arg3'=arg2, [ arg1P_2<=arg1 && arg2>-1 && arg1>0 && arg1P_2>0 ], cost: 1 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 ### Simplification by acceleration and chaining ### Accelerating simple loops of location 0. Accelerating the following rules: 0: f34_0_loop_Inc -> f34_0_loop_Inc : arg1'=arg1P_1, arg2'=1+arg2, [ arg1P_1<=arg1 && arg1>0 && arg1P_1>0 ], cost: 1 Accelerated rule 0 with non-termination, yielding the new rule 3. [accelerate] Nesting with 0 inner and 0 outer candidates Removing the simple loops: 0. Accelerated all simple loops using metering functions (where possible): Start location: __init 3: f34_0_loop_Inc -> [3] : [ arg1P_1<=arg1 && arg1>0 && arg1P_1>0 ], cost: NONTERM 1: f1_0_main_Load -> f34_0_loop_Inc : arg1'=arg1P_2, arg2'=1+arg2, arg3'=arg2, [ arg1P_2<=arg1 && arg2>-1 && arg1>0 && arg1P_2>0 ], cost: 1 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 Chained accelerated rules (with incoming rules): Start location: __init 1: f1_0_main_Load -> f34_0_loop_Inc : arg1'=arg1P_2, arg2'=1+arg2, arg3'=arg2, [ arg1P_2<=arg1 && arg2>-1 && arg1>0 && arg1P_2>0 ], cost: 1 4: f1_0_main_Load -> [3] : [ arg2>-1 && arg1>0 ], cost: NONTERM 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 Removed unreachable locations (and leaf rules with constant cost): Start location: __init 4: f1_0_main_Load -> [3] : [ arg2>-1 && arg1>0 ], cost: NONTERM 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 Eliminated locations (on linear paths): Start location: __init 5: __init -> [3] : [ arg2P_3>-1 && arg1P_3>0 ], cost: NONTERM ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: __init 5: __init -> [3] : [ arg2P_3>-1 && arg1P_3>0 ], cost: NONTERM Computing asymptotic complexity for rule 5 Guard is satisfiable, yielding nontermination Resulting cost NONTERM has complexity: Nonterm Found new complexity Nonterm. Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Nonterm Cpx degree: Nonterm Solved cost: NONTERM Rule cost: NONTERM Rule guard: [ arg2P_3>-1 && arg1P_3>0 ] NO