NO

### Pre-processing the ITS problem ###

Initial linear ITS problem
   Start location: __init
      0: f1_0_main_Load -> f32_0_loop_LE : arg1'=arg1P_1, arg2'=arg2P_1, [ arg1>0 && arg2>-1 && arg2==arg1P_1 ], cost: 1
      1: f32_0_loop_LE -> f32_0_loop_LE : arg1'=arg1P_2, arg2'=arg2P_2, [ 10==arg1 && 10==arg1P_2 ], cost: 1
      2: f32_0_loop_LE -> f32_0_loop_LE : arg1'=arg1P_3, arg2'=arg2P_3, [ arg1>5 && arg1<10 && -1+arg1==arg1P_3 ], cost: 1
      3: f32_0_loop_LE -> f32_0_loop_LE : arg1'=arg1P_4, arg2'=arg2P_4, [ arg1>10 && -1+arg1==arg1P_4 ], cost: 1
      4: __init -> f1_0_main_Load : arg1'=arg1P_5, arg2'=arg2P_5, [], cost: 1

Checking for constant complexity:
   The following rule is satisfiable with cost >= 1, yielding constant complexity:
      4: __init -> f1_0_main_Load : arg1'=arg1P_5, arg2'=arg2P_5, [], cost: 1

Simplified all rules, resulting in:
   Start location: __init
      0: f1_0_main_Load -> f32_0_loop_LE : arg1'=arg2, arg2'=arg2P_1, [ arg1>0 && arg2>-1 ], cost: 1
      1: f32_0_loop_LE -> f32_0_loop_LE : arg1'=10, arg2'=arg2P_2, [ 10==arg1 ], cost: 1
      2: f32_0_loop_LE -> f32_0_loop_LE : arg1'=-1+arg1, arg2'=arg2P_3, [ arg1>5 && arg1<10 ], cost: 1
      3: f32_0_loop_LE -> f32_0_loop_LE : arg1'=-1+arg1, arg2'=arg2P_4, [ arg1>10 ], cost: 1
      4: __init -> f1_0_main_Load : arg1'=arg1P_5, arg2'=arg2P_5, [], cost: 1

### Simplification by acceleration and chaining ###

Accelerating simple loops of location 1.
   Accelerating the following rules:
      1: f32_0_loop_LE -> f32_0_loop_LE : arg1'=10, arg2'=arg2P_2, [ 10==arg1 ], cost: 1
      2: f32_0_loop_LE -> f32_0_loop_LE : arg1'=-1+arg1, arg2'=arg2P_3, [ arg1>5 && arg1<10 ], cost: 1
      3: f32_0_loop_LE -> f32_0_loop_LE : arg1'=-1+arg1, arg2'=arg2P_4, [ arg1>10 ], cost: 1

   Accelerated rule 1 with non-termination, yielding the new rule 5.
   Accelerated rule 2 with backward acceleration, yielding the new rule 6.
   Accelerated rule 3 with backward acceleration, yielding the new rule 7.
[accelerate] Nesting with 2 inner and 2 outer candidates
   Removing the simple loops: 1 2 3.

Accelerated all simple loops using metering functions (where possible):
   Start location: __init
      0: f1_0_main_Load -> f32_0_loop_LE : arg1'=arg2, arg2'=arg2P_1, [ arg1>0 && arg2>-1 ], cost: 1
      5: f32_0_loop_LE -> [3] : [ 10==arg1 ], cost: NONTERM
      6: f32_0_loop_LE -> f32_0_loop_LE : arg1'=5, arg2'=arg2P_3, [ arg1<10 && -5+arg1>=1 ], cost: -5+arg1
      7: f32_0_loop_LE -> f32_0_loop_LE : arg1'=10, arg2'=arg2P_4, [ -10+arg1>=1 ], cost: -10+arg1
      4: __init -> f1_0_main_Load : arg1'=arg1P_5, arg2'=arg2P_5, [], cost: 1

Chained accelerated rules (with incoming rules):
   Start location: __init
      0: f1_0_main_Load -> f32_0_loop_LE : arg1'=arg2, arg2'=arg2P_1, [ arg1>0 && arg2>-1 ], cost: 1
      8: f1_0_main_Load -> [3] : [ arg1>0 && 10==arg2 ], cost: NONTERM
      9: f1_0_main_Load -> f32_0_loop_LE : arg1'=5, arg2'=arg2P_3, [ arg1>0 && arg2<10 && -5+arg2>=1 ], cost: -4+arg2
     10: f1_0_main_Load -> f32_0_loop_LE : arg1'=10, arg2'=arg2P_4, [ arg1>0 && -10+arg2>=1 ], cost: -9+arg2
      4: __init -> f1_0_main_Load : arg1'=arg1P_5, arg2'=arg2P_5, [], cost: 1

Removed unreachable locations (and leaf rules with constant cost):
   Start location: __init
      8: f1_0_main_Load -> [3] : [ arg1>0 && 10==arg2 ], cost: NONTERM
      9: f1_0_main_Load -> f32_0_loop_LE : arg1'=5, arg2'=arg2P_3, [ arg1>0 && arg2<10 && -5+arg2>=1 ], cost: -4+arg2
     10: f1_0_main_Load -> f32_0_loop_LE : arg1'=10, arg2'=arg2P_4, [ arg1>0 && -10+arg2>=1 ], cost: -9+arg2
      4: __init -> f1_0_main_Load : arg1'=arg1P_5, arg2'=arg2P_5, [], cost: 1

Eliminated locations (on tree-shaped paths):
   Start location: __init
     11: __init -> [3] : [ arg1P_5>0 && 10==arg2P_5 ], cost: NONTERM
     12: __init -> f32_0_loop_LE : arg1'=5, arg2'=arg2P_3, [ arg1P_5>0 && arg2P_5<10 && -5+arg2P_5>=1 ], cost: -3+arg2P_5
     13: __init -> f32_0_loop_LE : arg1'=10, arg2'=arg2P_4, [ arg1P_5>0 && -10+arg2P_5>=1 ], cost: -8+arg2P_5

### Computing asymptotic complexity ###

Fully simplified ITS problem
   Start location: __init
     11: __init -> [3] : [ arg1P_5>0 && 10==arg2P_5 ], cost: NONTERM
     12: __init -> f32_0_loop_LE : arg1'=5, arg2'=arg2P_3, [ arg1P_5>0 && arg2P_5<10 && -5+arg2P_5>=1 ], cost: -3+arg2P_5
     13: __init -> f32_0_loop_LE : arg1'=10, arg2'=arg2P_4, [ arg1P_5>0 && -10+arg2P_5>=1 ], cost: -8+arg2P_5

Computing asymptotic complexity for rule 11
   Guard is satisfiable, yielding nontermination
   Resulting cost NONTERM has complexity: Nonterm

Found new complexity Nonterm.

Obtained the following overall complexity (w.r.t. the length of the input n):
   Complexity:  Nonterm
   Cpx degree:  Nonterm
   Solved cost: NONTERM
   Rule cost:   NONTERM
   Rule guard:  [ arg1P_5>0 && 10==arg2P_5 ]

NO