WORST_CASE(Omega(1),?) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: __init 0: f1_0_main_Load -> f150_0_main_LT : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=arg3P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 && 1+arg1P_1==arg3P_1 ], cost: 1 1: f150_0_main_LT -> f150_0_main_LT : arg1'=arg1P_2, arg2'=arg2P_2, arg3'=arg3P_2, [ arg3<=arg2 && arg1>-2 && 1+arg1==arg1P_2 && arg2==arg2P_2 && 2+arg1==arg3P_2 ], cost: 1 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 Simplified all rules, resulting in: Start location: __init 0: f1_0_main_Load -> f150_0_main_LT : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=1+arg1P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 ], cost: 1 1: f150_0_main_LT -> f150_0_main_LT : arg1'=1+arg1, arg3'=2+arg1, [ arg3<=arg2 && arg1>-2 ], cost: 1 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 ### Simplification by acceleration and chaining ### Accelerating simple loops of location 1. Accelerating the following rules: 1: f150_0_main_LT -> f150_0_main_LT : arg1'=1+arg1, arg3'=2+arg1, [ arg3<=arg2 && arg1>-2 ], cost: 1 [test] deduced invariant -1+arg3-arg1<=0 Accelerated rule 1 with backward acceleration, yielding the new rule 3. [accelerate] Nesting with 1 inner and 1 outer candidates Accelerated all simple loops using metering functions (where possible): Start location: __init 0: f1_0_main_Load -> f150_0_main_LT : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=1+arg1P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 ], cost: 1 1: f150_0_main_LT -> f150_0_main_LT : arg1'=1+arg1, arg3'=2+arg1, [ arg3<=arg2 && arg1>-2 ], cost: 1 3: f150_0_main_LT -> f150_0_main_LT : arg1'=arg2, arg3'=1+arg2, [ arg1>-2 && -1+arg3-arg1<=0 && arg2-arg1>=1 ], cost: arg2-arg1 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 Chained accelerated rules (with incoming rules): Start location: __init 0: f1_0_main_Load -> f150_0_main_LT : arg1'=arg1P_1, arg2'=arg2P_1, arg3'=1+arg1P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 ], cost: 1 4: f1_0_main_Load -> f150_0_main_LT : arg1'=1+arg1P_1, arg2'=arg2P_1, arg3'=2+arg1P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 && 1+arg1P_1<=arg2P_1 ], cost: 2 5: f1_0_main_Load -> f150_0_main_LT : arg1'=arg2P_1, arg2'=arg2P_1, arg3'=1+arg2P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 && -arg1P_1+arg2P_1>=1 ], cost: 1-arg1P_1+arg2P_1 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 Removed unreachable locations (and leaf rules with constant cost): Start location: __init 5: f1_0_main_Load -> f150_0_main_LT : arg1'=arg2P_1, arg2'=arg2P_1, arg3'=1+arg2P_1, [ arg2P_1>-1 && arg2>-1 && arg1P_1>-1 && arg1>0 && -arg1P_1+arg2P_1>=1 ], cost: 1-arg1P_1+arg2P_1 2: __init -> f1_0_main_Load : arg1'=arg1P_3, arg2'=arg2P_3, arg3'=arg3P_3, [], cost: 1 Eliminated locations (on linear paths): Start location: __init 6: __init -> f150_0_main_LT : arg1'=arg2P_1, arg2'=arg2P_1, arg3'=1+arg2P_1, [ arg2P_1>-1 && arg2P_3>-1 && arg1P_1>-1 && arg1P_3>0 && -arg1P_1+arg2P_1>=1 ], cost: 2-arg1P_1+arg2P_1 ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: __init 6: __init -> f150_0_main_LT : arg1'=arg2P_1, arg2'=arg2P_1, arg3'=1+arg2P_1, [ arg2P_1>-1 && arg2P_3>-1 && arg1P_1>-1 && arg1P_3>0 && -arg1P_1+arg2P_1>=1 ], cost: 2-arg1P_1+arg2P_1 Computing asymptotic complexity for rule 6 Simplified the guard: 6: __init -> f150_0_main_LT : arg1'=arg2P_1, arg2'=arg2P_1, arg3'=1+arg2P_1, [ arg2P_3>-1 && arg1P_1>-1 && arg1P_3>0 && -arg1P_1+arg2P_1>=1 ], cost: 2-arg1P_1+arg2P_1 Resulting cost 0 has complexity: Unknown Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Constant Cpx degree: 0 Solved cost: 1 Rule cost: 1 Rule guard: [] WORST_CASE(Omega(1),?)