NO

### Pre-processing the ITS problem ###

Initial linear ITS problem
   Start location: l4
      0: l0 -> l1 : Result_4^0'=Result_4^post_1, x_5^0'=x_5^post_1, y_6^0'=y_6^post_1, [ Result_4^0==Result_4^post_1 && x_5^0==x_5^post_1 && y_6^0==y_6^post_1 ], cost: 1
      1: l1 -> l2 : Result_4^0'=Result_4^post_2, x_5^0'=x_5^post_2, y_6^0'=y_6^post_2, [ x_5^post_2==x_5^0+y_6^0 && -x_5^post_2<=0 && Result_4^0==Result_4^post_2 && y_6^0==y_6^post_2 ], cost: 1
      3: l1 -> l3 : Result_4^0'=Result_4^post_4, x_5^0'=x_5^post_4, y_6^0'=y_6^post_4, [ x_5^post_4==x_5^0+y_6^0 && 0<=-1-x_5^post_4 && Result_4^post_4==Result_4^post_4 && y_6^0==y_6^post_4 ], cost: 1
      2: l2 -> l1 : Result_4^0'=Result_4^post_3, x_5^0'=x_5^post_3, y_6^0'=y_6^post_3, [ Result_4^0==Result_4^post_3 && x_5^0==x_5^post_3 && y_6^0==y_6^post_3 ], cost: 1
      4: l4 -> l0 : Result_4^0'=Result_4^post_5, x_5^0'=x_5^post_5, y_6^0'=y_6^post_5, [ Result_4^0==Result_4^post_5 && x_5^0==x_5^post_5 && y_6^0==y_6^post_5 ], cost: 1

Checking for constant complexity:
   The following rule is satisfiable with cost >= 1, yielding constant complexity:
      4: l4 -> l0 : Result_4^0'=Result_4^post_5, x_5^0'=x_5^post_5, y_6^0'=y_6^post_5, [ Result_4^0==Result_4^post_5 && x_5^0==x_5^post_5 && y_6^0==y_6^post_5 ], cost: 1

Removed unreachable and leaf rules:
   Start location: l4
      0: l0 -> l1 : Result_4^0'=Result_4^post_1, x_5^0'=x_5^post_1, y_6^0'=y_6^post_1, [ Result_4^0==Result_4^post_1 && x_5^0==x_5^post_1 && y_6^0==y_6^post_1 ], cost: 1
      1: l1 -> l2 : Result_4^0'=Result_4^post_2, x_5^0'=x_5^post_2, y_6^0'=y_6^post_2, [ x_5^post_2==x_5^0+y_6^0 && -x_5^post_2<=0 && Result_4^0==Result_4^post_2 && y_6^0==y_6^post_2 ], cost: 1
      2: l2 -> l1 : Result_4^0'=Result_4^post_3, x_5^0'=x_5^post_3, y_6^0'=y_6^post_3, [ Result_4^0==Result_4^post_3 && x_5^0==x_5^post_3 && y_6^0==y_6^post_3 ], cost: 1
      4: l4 -> l0 : Result_4^0'=Result_4^post_5, x_5^0'=x_5^post_5, y_6^0'=y_6^post_5, [ Result_4^0==Result_4^post_5 && x_5^0==x_5^post_5 && y_6^0==y_6^post_5 ], cost: 1

Simplified all rules, resulting in:
   Start location: l4
      0: l0 -> l1 : [], cost: 1
      1: l1 -> l2 : x_5^0'=x_5^0+y_6^0, [ -x_5^0-y_6^0<=0 ], cost: 1
      2: l2 -> l1 : [], cost: 1
      4: l4 -> l0 : [], cost: 1

### Simplification by acceleration and chaining ###

Eliminated locations (on linear paths):
   Start location: l4
      6: l1 -> l1 : x_5^0'=x_5^0+y_6^0, [ -x_5^0-y_6^0<=0 ], cost: 2
      5: l4 -> l1 : [], cost: 2

Accelerating simple loops of location 1.
   Accelerating the following rules:
      6: l1 -> l1 : x_5^0'=x_5^0+y_6^0, [ -x_5^0-y_6^0<=0 ], cost: 2

[test] deduced pseudo-invariant -y_6^0<=0, also trying y_6^0<=-1
   Accelerated rule 6 with non-termination, yielding the new rule 7.
   Accelerated rule 6 with non-termination, yielding the new rule 8.
   Accelerated rule 6 with backward acceleration, yielding the new rule 9.
   Accelerated rule 6 with backward acceleration, yielding the new rule 10.
[accelerate] Nesting with 1 inner and 1 outer candidates
   Also removing duplicate rules: 8.

Accelerated all simple loops using metering functions (where possible):
   Start location: l4
      6: l1 -> l1 : x_5^0'=x_5^0+y_6^0, [ -x_5^0-y_6^0<=0 ], cost: 2
      7: l1 -> [5] : [ -x_5^0-y_6^0<=0 && x_5^0==0 && y_6^0==0 ], cost: NONTERM
      9: l1 -> [5] : [ -x_5^0-y_6^0<=0 && -y_6^0<=0 ], cost: NONTERM
     10: l1 -> l1 : x_5^0'=x_5^0+y_6^0*k, [ y_6^0<=-1 && k>=0 && -x_5^0-y_6^0-(-1+k)*y_6^0<=0 ], cost: 2*k
      5: l4 -> l1 : [], cost: 2

Chained accelerated rules (with incoming rules):
   Start location: l4
      5: l4 -> l1 : [], cost: 2
     11: l4 -> l1 : x_5^0'=x_5^0+y_6^0, [ -x_5^0-y_6^0<=0 ], cost: 4
     12: l4 -> [5] : [ -x_5^0-y_6^0<=0 && x_5^0==0 && y_6^0==0 ], cost: NONTERM
     13: l4 -> [5] : [ -x_5^0-y_6^0<=0 && -y_6^0<=0 ], cost: NONTERM
     14: l4 -> l1 : x_5^0'=x_5^0+y_6^0*k, [ y_6^0<=-1 && k>=0 && -x_5^0-y_6^0-(-1+k)*y_6^0<=0 ], cost: 2+2*k

Removed unreachable locations (and leaf rules with constant cost):
   Start location: l4
     12: l4 -> [5] : [ -x_5^0-y_6^0<=0 && x_5^0==0 && y_6^0==0 ], cost: NONTERM
     13: l4 -> [5] : [ -x_5^0-y_6^0<=0 && -y_6^0<=0 ], cost: NONTERM
     14: l4 -> l1 : x_5^0'=x_5^0+y_6^0*k, [ y_6^0<=-1 && k>=0 && -x_5^0-y_6^0-(-1+k)*y_6^0<=0 ], cost: 2+2*k

### Computing asymptotic complexity ###

Fully simplified ITS problem
   Start location: l4
     12: l4 -> [5] : [ -x_5^0-y_6^0<=0 && x_5^0==0 && y_6^0==0 ], cost: NONTERM
     13: l4 -> [5] : [ -x_5^0-y_6^0<=0 && -y_6^0<=0 ], cost: NONTERM
     14: l4 -> l1 : x_5^0'=x_5^0+y_6^0*k, [ y_6^0<=-1 && k>=0 && -x_5^0-y_6^0-(-1+k)*y_6^0<=0 ], cost: 2+2*k

Computing asymptotic complexity for rule 13
   Guard is satisfiable, yielding nontermination
   Resulting cost NONTERM has complexity: Nonterm

Found new complexity Nonterm.

Obtained the following overall complexity (w.r.t. the length of the input n):
   Complexity:  Nonterm
   Cpx degree:  Nonterm
   Solved cost: NONTERM
   Rule cost:   NONTERM
   Rule guard:  [ -x_5^0-y_6^0<=0 && -y_6^0<=0 ]

NO