WORST_CASE(Omega(1),?) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: l2 0: l0 -> l1 : x^0'=x^post_1, [ 1<=x^0 && x^post_1==-1+x^0 ], cost: 1 1: l1 -> l0 : x^0'=x^post_2, [ x^0==x^post_2 ], cost: 1 2: l2 -> l0 : x^0'=x^post_3, [ x^0==x^post_3 ], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 2: l2 -> l0 : x^0'=x^post_3, [ x^0==x^post_3 ], cost: 1 Simplified all rules, resulting in: Start location: l2 0: l0 -> l1 : x^0'=-1+x^0, [ 1<=x^0 ], cost: 1 1: l1 -> l0 : [], cost: 1 2: l2 -> l0 : [], cost: 1 ### Simplification by acceleration and chaining ### Eliminated locations (on linear paths): Start location: l2 3: l0 -> l0 : x^0'=-1+x^0, [ 1<=x^0 ], cost: 2 2: l2 -> l0 : [], cost: 1 Accelerating simple loops of location 0. Accelerating the following rules: 3: l0 -> l0 : x^0'=-1+x^0, [ 1<=x^0 ], cost: 2 Accelerated rule 3 with backward acceleration, yielding the new rule 4. [accelerate] Nesting with 1 inner and 1 outer candidates Removing the simple loops: 3. Accelerated all simple loops using metering functions (where possible): Start location: l2 4: l0 -> l0 : x^0'=0, [ x^0>=0 ], cost: 2*x^0 2: l2 -> l0 : [], cost: 1 Chained accelerated rules (with incoming rules): Start location: l2 2: l2 -> l0 : [], cost: 1 5: l2 -> l0 : x^0'=0, [ x^0>=0 ], cost: 1+2*x^0 Removed unreachable locations (and leaf rules with constant cost): Start location: l2 5: l2 -> l0 : x^0'=0, [ x^0>=0 ], cost: 1+2*x^0 ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: l2 5: l2 -> l0 : x^0'=0, [ x^0>=0 ], cost: 1+2*x^0 Computing asymptotic complexity for rule 5 Resulting cost 0 has complexity: Unknown Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Constant Cpx degree: 0 Solved cost: 1 Rule cost: 1 Rule guard: [ x^0==x^post_3 ] WORST_CASE(Omega(1),?)