NO

### Pre-processing the ITS problem ###

Initial linear ITS problem
   Start location: l5
      0: l0 -> l2 : __disjvr_0^0'=__disjvr_0^post_1, b^0'=b^post_1, [ 0<=b^0 && b^post_1==1 && __disjvr_0^0==__disjvr_0^post_1 ], cost: 1
      1: l2 -> l3 : __disjvr_0^0'=__disjvr_0^post_2, b^0'=b^post_2, [ __disjvr_0^post_2==__disjvr_0^0 && __disjvr_0^0==__disjvr_0^post_2 && b^0==b^post_2 ], cost: 1
      2: l3 -> l1 : __disjvr_0^0'=__disjvr_0^post_3, b^0'=b^post_3, [ b^post_3==0 && __disjvr_0^0==__disjvr_0^post_3 ], cost: 1
      3: l1 -> l0 : __disjvr_0^0'=__disjvr_0^post_4, b^0'=b^post_4, [ __disjvr_0^0==__disjvr_0^post_4 && b^0==b^post_4 ], cost: 1
      4: l4 -> l0 : __disjvr_0^0'=__disjvr_0^post_5, b^0'=b^post_5, [ __disjvr_0^0==__disjvr_0^post_5 && b^0==b^post_5 ], cost: 1
      5: l5 -> l4 : __disjvr_0^0'=__disjvr_0^post_6, b^0'=b^post_6, [ __disjvr_0^0==__disjvr_0^post_6 && b^0==b^post_6 ], cost: 1

Checking for constant complexity:
   The following rule is satisfiable with cost >= 1, yielding constant complexity:
      5: l5 -> l4 : __disjvr_0^0'=__disjvr_0^post_6, b^0'=b^post_6, [ __disjvr_0^0==__disjvr_0^post_6 && b^0==b^post_6 ], cost: 1

Simplified all rules, resulting in:
   Start location: l5
      0: l0 -> l2 : b^0'=1, [ 0<=b^0 ], cost: 1
      1: l2 -> l3 : [], cost: 1
      2: l3 -> l1 : b^0'=0, [], cost: 1
      3: l1 -> l0 : [], cost: 1
      4: l4 -> l0 : [], cost: 1
      5: l5 -> l4 : [], cost: 1

### Simplification by acceleration and chaining ###

Eliminated locations (on linear paths):
   Start location: l5
      9: l0 -> l0 : b^0'=0, [ 0<=b^0 ], cost: 4
      6: l5 -> l0 : [], cost: 2

Accelerating simple loops of location 0.
   Accelerating the following rules:
      9: l0 -> l0 : b^0'=0, [ 0<=b^0 ], cost: 4

   Accelerated rule 9 with non-termination, yielding the new rule 10.
[accelerate] Nesting with 0 inner and 0 outer candidates
   Removing the simple loops: 9.

Accelerated all simple loops using metering functions (where possible):
   Start location: l5
     10: l0 -> [6] : [ 0<=b^0 ], cost: NONTERM
      6: l5 -> l0 : [], cost: 2

Chained accelerated rules (with incoming rules):
   Start location: l5
      6: l5 -> l0 : [], cost: 2
     11: l5 -> [6] : [ 0<=b^0 ], cost: NONTERM

Removed unreachable locations (and leaf rules with constant cost):
   Start location: l5
     11: l5 -> [6] : [ 0<=b^0 ], cost: NONTERM

### Computing asymptotic complexity ###

Fully simplified ITS problem
   Start location: l5
     11: l5 -> [6] : [ 0<=b^0 ], cost: NONTERM

Computing asymptotic complexity for rule 11
   Guard is satisfiable, yielding nontermination
   Resulting cost NONTERM has complexity: Nonterm

Found new complexity Nonterm.

Obtained the following overall complexity (w.r.t. the length of the input n):
   Complexity:  Nonterm
   Cpx degree:  Nonterm
   Solved cost: NONTERM
   Rule cost:   NONTERM
   Rule guard:  [ 0<=b^0 ]

NO