WORST_CASE(Omega(1),?) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: l6 0: l0 -> l1 : i^0'=i^post_1, [ i^0==i^post_1 ], cost: 1 1: l2 -> l0 : i^0'=i^post_2, [ 20<=i^0 && i^0==i^post_2 ], cost: 1 2: l2 -> l3 : i^0'=i^post_3, [ 1+i^0<=20 && i^post_3==1+i^0 ], cost: 1 5: l3 -> l2 : i^0'=i^post_6, [ i^0==i^post_6 ], cost: 1 3: l4 -> l0 : i^0'=i^post_4, [ i^0<=0 && i^0==i^post_4 ], cost: 1 4: l4 -> l3 : i^0'=i^post_5, [ 1<=i^0 && i^0==i^post_5 ], cost: 1 6: l5 -> l4 : i^0'=i^post_7, [ i^1_1==0 && i^post_7==i^post_7 ], cost: 1 7: l6 -> l5 : i^0'=i^post_8, [ i^0==i^post_8 ], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 7: l6 -> l5 : i^0'=i^post_8, [ i^0==i^post_8 ], cost: 1 Removed unreachable and leaf rules: Start location: l6 2: l2 -> l3 : i^0'=i^post_3, [ 1+i^0<=20 && i^post_3==1+i^0 ], cost: 1 5: l3 -> l2 : i^0'=i^post_6, [ i^0==i^post_6 ], cost: 1 4: l4 -> l3 : i^0'=i^post_5, [ 1<=i^0 && i^0==i^post_5 ], cost: 1 6: l5 -> l4 : i^0'=i^post_7, [ i^1_1==0 && i^post_7==i^post_7 ], cost: 1 7: l6 -> l5 : i^0'=i^post_8, [ i^0==i^post_8 ], cost: 1 Simplified all rules, resulting in: Start location: l6 2: l2 -> l3 : i^0'=1+i^0, [ 1+i^0<=20 ], cost: 1 5: l3 -> l2 : [], cost: 1 4: l4 -> l3 : [ 1<=i^0 ], cost: 1 6: l5 -> l4 : i^0'=i^post_7, [], cost: 1 7: l6 -> l5 : [], cost: 1 ### Simplification by acceleration and chaining ### Eliminated locations (on linear paths): Start location: l6 10: l3 -> l3 : i^0'=1+i^0, [ 1+i^0<=20 ], cost: 2 9: l6 -> l3 : i^0'=i^post_7, [ 1<=i^post_7 ], cost: 3 Accelerating simple loops of location 3. Accelerating the following rules: 10: l3 -> l3 : i^0'=1+i^0, [ 1+i^0<=20 ], cost: 2 Accelerated rule 10 with backward acceleration, yielding the new rule 11. [accelerate] Nesting with 1 inner and 1 outer candidates Removing the simple loops: 10. Accelerated all simple loops using metering functions (where possible): Start location: l6 11: l3 -> l3 : i^0'=20, [ 20-i^0>=0 ], cost: 40-2*i^0 9: l6 -> l3 : i^0'=i^post_7, [ 1<=i^post_7 ], cost: 3 Chained accelerated rules (with incoming rules): Start location: l6 9: l6 -> l3 : i^0'=i^post_7, [ 1<=i^post_7 ], cost: 3 12: l6 -> l3 : i^0'=20, [ 1<=i^post_7 && 20-i^post_7>=0 ], cost: 43-2*i^post_7 Removed unreachable locations (and leaf rules with constant cost): Start location: l6 12: l6 -> l3 : i^0'=20, [ 1<=i^post_7 && 20-i^post_7>=0 ], cost: 43-2*i^post_7 ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: l6 12: l6 -> l3 : i^0'=20, [ 1<=i^post_7 && 20-i^post_7>=0 ], cost: 43-2*i^post_7 Computing asymptotic complexity for rule 12 Resulting cost 0 has complexity: Unknown Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Constant Cpx degree: 0 Solved cost: 1 Rule cost: 1 Rule guard: [ i^0==i^post_8 ] WORST_CASE(Omega(1),?)