NO

### Pre-processing the ITS problem ###

Initial linear ITS problem
   Start location: l5
      0: l0 -> l1 : Result_4^0'=Result_4^post_1, x_5^0'=x_5^post_1, y_6^0'=y_6^post_1, [ -x_5^0+y_6^0<=0 && x_5^0-y_6^0<=0 && Result_4^post_1==Result_4^post_1 && x_5^0==x_5^post_1 && y_6^0==y_6^post_1 ], cost: 1
      1: l0 -> l2 : Result_4^0'=Result_4^post_2, x_5^0'=x_5^post_2, y_6^0'=y_6^post_2, [ -x_5^0+y_6^0<=0 && 0<=-1+x_5^0-y_6^0 && x_5^post_2==1+x_5^0 && Result_4^0==Result_4^post_2 && y_6^0==y_6^post_2 ], cost: 1
      3: l0 -> l3 : Result_4^0'=Result_4^post_4, x_5^0'=x_5^post_4, y_6^0'=y_6^post_4, [ 0<=-1-x_5^0+y_6^0 && x_5^post_4==1+x_5^0 && Result_4^0==Result_4^post_4 && y_6^0==y_6^post_4 ], cost: 1
      2: l2 -> l0 : Result_4^0'=Result_4^post_3, x_5^0'=x_5^post_3, y_6^0'=y_6^post_3, [ Result_4^0==Result_4^post_3 && x_5^0==x_5^post_3 && y_6^0==y_6^post_3 ], cost: 1
      4: l3 -> l0 : Result_4^0'=Result_4^post_5, x_5^0'=x_5^post_5, y_6^0'=y_6^post_5, [ Result_4^0==Result_4^post_5 && x_5^0==x_5^post_5 && y_6^0==y_6^post_5 ], cost: 1
      5: l4 -> l0 : Result_4^0'=Result_4^post_6, x_5^0'=x_5^post_6, y_6^0'=y_6^post_6, [ Result_4^0==Result_4^post_6 && x_5^0==x_5^post_6 && y_6^0==y_6^post_6 ], cost: 1
      6: l5 -> l4 : Result_4^0'=Result_4^post_7, x_5^0'=x_5^post_7, y_6^0'=y_6^post_7, [ Result_4^0==Result_4^post_7 && x_5^0==x_5^post_7 && y_6^0==y_6^post_7 ], cost: 1

Checking for constant complexity:
   The following rule is satisfiable with cost >= 1, yielding constant complexity:
      6: l5 -> l4 : Result_4^0'=Result_4^post_7, x_5^0'=x_5^post_7, y_6^0'=y_6^post_7, [ Result_4^0==Result_4^post_7 && x_5^0==x_5^post_7 && y_6^0==y_6^post_7 ], cost: 1

Removed unreachable and leaf rules:
   Start location: l5
      1: l0 -> l2 : Result_4^0'=Result_4^post_2, x_5^0'=x_5^post_2, y_6^0'=y_6^post_2, [ -x_5^0+y_6^0<=0 && 0<=-1+x_5^0-y_6^0 && x_5^post_2==1+x_5^0 && Result_4^0==Result_4^post_2 && y_6^0==y_6^post_2 ], cost: 1
      3: l0 -> l3 : Result_4^0'=Result_4^post_4, x_5^0'=x_5^post_4, y_6^0'=y_6^post_4, [ 0<=-1-x_5^0+y_6^0 && x_5^post_4==1+x_5^0 && Result_4^0==Result_4^post_4 && y_6^0==y_6^post_4 ], cost: 1
      2: l2 -> l0 : Result_4^0'=Result_4^post_3, x_5^0'=x_5^post_3, y_6^0'=y_6^post_3, [ Result_4^0==Result_4^post_3 && x_5^0==x_5^post_3 && y_6^0==y_6^post_3 ], cost: 1
      4: l3 -> l0 : Result_4^0'=Result_4^post_5, x_5^0'=x_5^post_5, y_6^0'=y_6^post_5, [ Result_4^0==Result_4^post_5 && x_5^0==x_5^post_5 && y_6^0==y_6^post_5 ], cost: 1
      5: l4 -> l0 : Result_4^0'=Result_4^post_6, x_5^0'=x_5^post_6, y_6^0'=y_6^post_6, [ Result_4^0==Result_4^post_6 && x_5^0==x_5^post_6 && y_6^0==y_6^post_6 ], cost: 1
      6: l5 -> l4 : Result_4^0'=Result_4^post_7, x_5^0'=x_5^post_7, y_6^0'=y_6^post_7, [ Result_4^0==Result_4^post_7 && x_5^0==x_5^post_7 && y_6^0==y_6^post_7 ], cost: 1

Simplified all rules, resulting in:
   Start location: l5
      1: l0 -> l2 : x_5^0'=1+x_5^0, [ 0<=-1+x_5^0-y_6^0 ], cost: 1
      3: l0 -> l3 : x_5^0'=1+x_5^0, [ 0<=-1-x_5^0+y_6^0 ], cost: 1
      2: l2 -> l0 : [], cost: 1
      4: l3 -> l0 : [], cost: 1
      5: l4 -> l0 : [], cost: 1
      6: l5 -> l4 : [], cost: 1

### Simplification by acceleration and chaining ###

Eliminated locations (on linear paths):
   Start location: l5
      8: l0 -> l0 : x_5^0'=1+x_5^0, [ 0<=-1+x_5^0-y_6^0 ], cost: 2
      9: l0 -> l0 : x_5^0'=1+x_5^0, [ 0<=-1-x_5^0+y_6^0 ], cost: 2
      7: l5 -> l0 : [], cost: 2

Accelerating simple loops of location 0.
   Accelerating the following rules:
      8: l0 -> l0 : x_5^0'=1+x_5^0, [ 0<=-1+x_5^0-y_6^0 ], cost: 2
      9: l0 -> l0 : x_5^0'=1+x_5^0, [ 0<=-1-x_5^0+y_6^0 ], cost: 2

   Accelerated rule 8 with non-termination, yielding the new rule 10.
   Accelerated rule 9 with backward acceleration, yielding the new rule 11.
[accelerate] Nesting with 1 inner and 1 outer candidates
   Removing the simple loops: 8 9.

Accelerated all simple loops using metering functions (where possible):
   Start location: l5
     10: l0 -> [6] : [ 0<=-1+x_5^0-y_6^0 ], cost: NONTERM
     11: l0 -> l0 : x_5^0'=y_6^0, [ -x_5^0+y_6^0>=0 ], cost: -2*x_5^0+2*y_6^0
      7: l5 -> l0 : [], cost: 2

Chained accelerated rules (with incoming rules):
   Start location: l5
      7: l5 -> l0 : [], cost: 2
     12: l5 -> [6] : [ 0<=-1+x_5^0-y_6^0 ], cost: NONTERM
     13: l5 -> l0 : x_5^0'=y_6^0, [ -x_5^0+y_6^0>=0 ], cost: 2-2*x_5^0+2*y_6^0

Removed unreachable locations (and leaf rules with constant cost):
   Start location: l5
     12: l5 -> [6] : [ 0<=-1+x_5^0-y_6^0 ], cost: NONTERM
     13: l5 -> l0 : x_5^0'=y_6^0, [ -x_5^0+y_6^0>=0 ], cost: 2-2*x_5^0+2*y_6^0

### Computing asymptotic complexity ###

Fully simplified ITS problem
   Start location: l5
     12: l5 -> [6] : [ 0<=-1+x_5^0-y_6^0 ], cost: NONTERM
     13: l5 -> l0 : x_5^0'=y_6^0, [ -x_5^0+y_6^0>=0 ], cost: 2-2*x_5^0+2*y_6^0

Computing asymptotic complexity for rule 12
   Guard is satisfiable, yielding nontermination
   Resulting cost NONTERM has complexity: Nonterm

Found new complexity Nonterm.

Obtained the following overall complexity (w.r.t. the length of the input n):
   Complexity:  Nonterm
   Cpx degree:  Nonterm
   Solved cost: NONTERM
   Rule cost:   NONTERM
   Rule guard:  [ 0<=-1+x_5^0-y_6^0 ]

NO