WORST_CASE(Omega(1),?)

### Pre-processing the ITS problem ###

Initial linear ITS problem
   Start location: l2
      0: l0 -> l1 : tmp3^0'=tmp3^post_1, tmp___04^0'=tmp___04^post_1, [ tmp3^post_1==tmp3^post_1 && tmp___04^post_1==tmp___04^post_1 ], cost: 1
      1: l2 -> l0 : tmp3^0'=tmp3^post_2, tmp___04^0'=tmp___04^post_2, [ tmp3^0==tmp3^post_2 && tmp___04^0==tmp___04^post_2 ], cost: 1

Checking for constant complexity:
   The following rule is satisfiable with cost >= 1, yielding constant complexity:
      1: l2 -> l0 : tmp3^0'=tmp3^post_2, tmp___04^0'=tmp___04^post_2, [ tmp3^0==tmp3^post_2 && tmp___04^0==tmp___04^post_2 ], cost: 1

Removed unreachable and leaf rules:
   Start location: l2
     <empty>

Empty problem, aborting

Obtained the following overall complexity (w.r.t. the length of the input n):
   Complexity:  Constant
   Cpx degree:  0
   Solved cost: 1
   Rule cost:   1
   Rule guard:  [ tmp3^0==tmp3^post_2 && tmp___04^0==tmp___04^post_2 ]

WORST_CASE(Omega(1),?)