NO ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: [0] 0: [0] -> [1] : [ x>=-1 && y>=-10 ], cost: 1 1: [1] -> [2] : [ x>=1 && y>=-10 ], cost: 1 3: [1] -> [3] : [ x<1 ], cost: 1 4: [1] -> [3] : [ y<-10 ], cost: 1 2: [2] -> [1] : x'=1+y, z'=x*y, [], cost: 1 Checking for constant complexity: The following rule is satisfiable with cost >= 1, yielding constant complexity: 0: [0] -> [1] : [ x>=-1 && y>=-10 ], cost: 1 Removed unreachable and leaf rules: Start location: [0] 0: [0] -> [1] : [ x>=-1 && y>=-10 ], cost: 1 1: [1] -> [2] : [ x>=1 && y>=-10 ], cost: 1 2: [2] -> [1] : x'=1+y, z'=x*y, [], cost: 1 ### Simplification by acceleration and chaining ### Eliminated locations (on linear paths): Start location: [0] 0: [0] -> [1] : [ x>=-1 && y>=-10 ], cost: 1 5: [1] -> [1] : x'=1+y, z'=x*y, [ x>=1 && y>=-10 ], cost: 2 Accelerating simple loops of location 1. Accelerating the following rules: 5: [1] -> [1] : x'=1+y, z'=x*y, [ x>=1 && y>=-10 ], cost: 2 [test] deduced pseudo-invariant -1+x-y<=0, also trying 1-x+y<=-1 Accelerated rule 5 with non-termination, yielding the new rule 6. Accelerated rule 5 with non-termination, yielding the new rule 7. Accelerated rule 5 with backward acceleration, yielding the new rule 8. [accelerate] Nesting with 0 inner and 1 outer candidates Also removing duplicate rules: 7. Accelerated all simple loops using metering functions (where possible): Start location: [0] 0: [0] -> [1] : [ x>=-1 && y>=-10 ], cost: 1 5: [1] -> [1] : x'=1+y, z'=x*y, [ x>=1 && y>=-10 ], cost: 2 6: [1] -> [4] : [ x>=1 && 1+y>=1 ], cost: NONTERM 8: [1] -> [4] : [ x>=1 && y>=-10 && -1+x-y<=0 ], cost: NONTERM Chained accelerated rules (with incoming rules): Start location: [0] 0: [0] -> [1] : [ x>=-1 && y>=-10 ], cost: 1 9: [0] -> [1] : x'=1+y, z'=x*y, [ x>=-1 && y>=-10 && x>=1 && y>=-10 ], cost: 3 10: [0] -> [4] : [ x>=-1 && y>=-10 && x>=1 && 1+y>=1 ], cost: NONTERM 11: [0] -> [4] : [ x>=-1 && y>=-10 && x>=1 && y>=-10 && -1+x-y<=0 ], cost: NONTERM Removed unreachable locations (and leaf rules with constant cost): Start location: [0] 10: [0] -> [4] : [ x>=-1 && y>=-10 && x>=1 && 1+y>=1 ], cost: NONTERM 11: [0] -> [4] : [ x>=-1 && y>=-10 && x>=1 && y>=-10 && -1+x-y<=0 ], cost: NONTERM ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: [0] 10: [0] -> [4] : [ x>=-1 && y>=-10 && x>=1 && 1+y>=1 ], cost: NONTERM 11: [0] -> [4] : [ x>=-1 && y>=-10 && x>=1 && y>=-10 && -1+x-y<=0 ], cost: NONTERM Computing asymptotic complexity for rule 10 Guard is satisfiable, yielding nontermination Resulting cost NONTERM has complexity: Nonterm Found new complexity Nonterm. Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Nonterm Cpx degree: Nonterm Solved cost: NONTERM Rule cost: NONTERM Rule guard: [ x>=-1 && y>=-10 && x>=1 && 1+y>=1 ] NO