YES

Problem:
 f(s(x),y) -> f(x,s(x))
 f(x,s(y)) -> f(y,x)
 f(c(x),y) -> f(x,s(x))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [f](x0, x1) = 4x0 + 2x1,
   
   [s](x0) = 4x0 + 6,
   
   [c](x0) = 3x0 + 3
  orientation:
   f(s(x),y) = 16x + 2y + 24 >= 12x + 12 = f(x,s(x))
   
   f(x,s(y)) = 4x + 8y + 12 >= 2x + 4y = f(y,x)
   
   f(c(x),y) = 12x + 2y + 12 >= 12x + 12 = f(x,s(x))
  problem:
   f(c(x),y) -> f(x,s(x))
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [f](x0, x1) = 4x0 + 4x1,
    
    [s](x0) = x0,
    
    [c](x0) = 4x0 + 4
   orientation:
    f(c(x),y) = 16x + 4y + 16 >= 8x = f(x,s(x))
   problem:
    
   Qed