NO

Problem:
 a(b(a(b(x)))) -> b(a(b(a(a(b(x))))))

Proof:
 Unfolding Processor:
  loop length: 2
  terms:
   a(b(a(b(a(b(x10))))))
   b(a(b(a(a(b(a(b(x10))))))))
  context: b([])
  substitution:
   x10 -> a(a(b(x10)))
  Qed