YES
Input TRS:
      1: quot(0(),s(y),s(z)) -> 0()
      2: quot(s(x),s(y),z) -> quot(x,y,z)
      3: quot(x,0(),s(z)) -> s(quot(x,s(z),s(z)))
Number of strict rules: 3
Direct POLO(bPol) ... failed.
Uncurrying ... failed.
Dependency Pairs:
     #1: #quot(s(x),s(y),z) -> #quot(x,y,z)
     #2: #quot(x,0(),s(z)) -> #quot(x,s(z),s(z))
Number of SCCs: 1, DPs: 2
  SCC { #1 #2 }
POLO(Sum)... succeeded.
      s 	w: x1 + 1
      0 	w: 1
      quot	w: 0
      #quot	w: x1
    USABLE RULES: { }
    Removed DPs: #1
Number of SCCs: 0, DPs: 0