YES

Problem:
 i(0()) -> 0()
 +(0(),y) -> y
 +(x,0()) -> x
 i(i(x)) -> x
 +(i(x),x) -> 0()
 +(x,i(x)) -> 0()
 i(+(x,y)) -> +(i(x),i(y))
 +(x,+(y,z)) -> +(+(x,y),z)
 +(+(x,i(y)),y) -> x
 +(+(x,y),i(y)) -> x

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [i](x0) = x0,
   
   [0] = 1,
   
   [+](x0, x1) = x0 + 4x1 + 1
  orientation:
   i(0()) = 1 >= 1 = 0()
   
   +(0(),y) = 4y + 2 >= y = y
   
   +(x,0()) = x + 5 >= x = x
   
   i(i(x)) = x >= x = x
   
   +(i(x),x) = 5x + 1 >= 1 = 0()
   
   +(x,i(x)) = 5x + 1 >= 1 = 0()
   
   i(+(x,y)) = x + 4y + 1 >= x + 4y + 1 = +(i(x),i(y))
   
   +(x,+(y,z)) = x + 4y + 16z + 5 >= x + 4y + 4z + 2 = +(+(x,y),z)
   
   +(+(x,i(y)),y) = x + 8y + 2 >= x = x
   
   +(+(x,y),i(y)) = x + 8y + 2 >= x = x
  problem:
   i(0()) -> 0()
   i(i(x)) -> x
   +(i(x),x) -> 0()
   +(x,i(x)) -> 0()
   i(+(x,y)) -> +(i(x),i(y))
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [i](x0) = 4x0 + 5,
    
    [0] = 3,
    
    [+](x0, x1) = 2x0 + x1 + 5
   orientation:
    i(0()) = 17 >= 3 = 0()
    
    i(i(x)) = 16x + 25 >= x = x
    
    +(i(x),x) = 9x + 15 >= 3 = 0()
    
    +(x,i(x)) = 6x + 10 >= 3 = 0()
    
    i(+(x,y)) = 8x + 4y + 25 >= 8x + 4y + 20 = +(i(x),i(y))
   problem:
    
   Qed