YES

Problem:
 a(b(x)) -> b(b(a(x)))

Proof:
 String Reversal Processor:
  b(a(x)) -> a(b(b(x)))
  KBO Processor:
   weight function:
    w0 = 1
    w(a) = 1
    w(b) = 0
   precedence:
    b > a
   problem:
    
   Qed