YES Problem 1: (VAR v_NonEmpty:S x:S) (RULES a(b(x:S)) -> a(c(b(x:S))) ) Problem 1: Innermost Equivalent Processor: -> Rules: a(b(x:S)) -> a(c(b(x:S))) -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: Empty -> Rules: a(b(x:S)) -> a(c(b(x:S))) Problem 1: SCC Processor: -> Pairs: Empty -> Rules: a(b(x:S)) -> a(c(b(x:S))) ->Strongly Connected Components: There is no strongly connected component The problem is finite.