YES

Problem:
 a(b(x)) -> b(a(x))
 a(c(x)) -> x

Proof:
 Bounds Processor:
  bound: 0
  enrichment: match
  automaton:
   final states: {2,1}
   transitions:
    a0(2) -> 3*
    f30() -> 2*
    b0(3) -> 1*
    2 -> 3*
    1 -> 3*
  problem:
   
  Qed