YES

Problem:
 +(0(),y) -> y
 +(s(x),y) -> s(+(x,y))
 -(0(),y) -> 0()
 -(x,0()) -> x
 -(s(x),s(y)) -> -(x,y)

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [+](x0, x1) = x0 + x1,
   
   [-](x0, x1) = 2x0 + 4x1 + 4,
   
   [0] = 6,
   
   [s](x0) = x0 + 3
  orientation:
   +(0(),y) = y + 6 >= y = y
   
   +(s(x),y) = x + y + 3 >= x + y + 3 = s(+(x,y))
   
   -(0(),y) = 4y + 16 >= 6 = 0()
   
   -(x,0()) = 2x + 28 >= x = x
   
   -(s(x),s(y)) = 2x + 4y + 22 >= 2x + 4y + 4 = -(x,y)
  problem:
   +(s(x),y) -> s(+(x,y))
  Matrix Interpretation Processor: dim=3
   
   interpretation:
                  [1 1 0]     [1 0 0]  
    [+](x0, x1) = [1 0 1]x0 + [0 0 0]x1
                  [0 0 1]     [0 0 0]  ,
    
                   [0]
    [s](x0) = x0 + [1]
                   [1]
   orientation:
                [1 1 0]    [1 0 0]    [1]    [1 1 0]    [1 0 0]    [0]            
    +(s(x),y) = [1 0 1]x + [0 0 0]y + [1] >= [1 0 1]x + [0 0 0]y + [1] = s(+(x,y))
                [0 0 1]    [0 0 0]    [1]    [0 0 1]    [0 0 0]    [1]            
   problem:
    
   Qed