YES

Problem:
 f(x,y) -> g(x,y)
 g(h(x),y) -> h(f(x,y))
 g(h(x),y) -> h(g(x,y))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [g](x0, x1) = 5x0 + x1 + 4,
   
   [f](x0, x1) = 5x0 + x1 + 4,
   
   [h](x0) = x0 + 1
  orientation:
   f(x,y) = 5x + y + 4 >= 5x + y + 4 = g(x,y)
   
   g(h(x),y) = 5x + y + 9 >= 5x + y + 5 = h(f(x,y))
   
   g(h(x),y) = 5x + y + 9 >= 5x + y + 5 = h(g(x,y))
  problem:
   f(x,y) -> g(x,y)
  Matrix Interpretation Processor: dim=3
   
   interpretation:
                  [1 0 0]     [1 0 0]  
    [g](x0, x1) = [0 0 0]x0 + [0 0 0]x1
                  [0 0 0]     [0 0 0]  ,
    
                  [1 0 0]     [1 0 0]     [1]
    [f](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0]
                  [0 0 0]     [0 0 1]     [0]
   orientation:
             [1 0 0]    [1 0 0]    [1]    [1 0 0]    [1 0 0]          
    f(x,y) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0 0 0]y = g(x,y)
             [0 0 0]    [0 0 1]    [0]    [0 0 0]    [0 0 0]          
   problem:
    
   Qed