YES

Problem:
 f(x,a()) -> x
 f(x,g(y)) -> f(g(x),y)

Proof:
 Matrix Interpretation Processor: dim=3
  
  interpretation:
                      [1 0 1]  
   [f](x0, x1) = x0 + [0 0 1]x1
                      [0 0 1]  ,
   
         [0]
   [a] = [0]
         [1],
   
             [1 0 0]     [0]
   [g](x0) = [0 0 0]x0 + [1]
             [0 0 1]     [1]
  orientation:
                  [1]         
   f(x,a()) = x + [1] >= x = x
                  [1]         
   
                   [1 0 1]    [1]    [1 0 0]    [1 0 1]    [0]            
   f(x,g(y)) = x + [0 0 1]y + [1] >= [0 0 0]x + [0 0 1]y + [1] = f(g(x),y)
                   [0 0 1]    [1]    [0 0 1]    [0 0 1]    [1]            
  problem:
   
  Qed