YES Problem: not(x) -> xor(x,true()) implies(x,y) -> xor(and(x,y),xor(x,true())) or(x,y) -> xor(and(x,y),xor(x,y)) =(x,y) -> xor(x,xor(y,true())) Proof: Matrix Interpretation Processor: dim=1 interpretation: [and](x0, x1) = x0 + x1, [true] = 0, [implies](x0, x1) = 6x0 + 2x1, [or](x0, x1) = 7x0 + 6x1 + 1, [not](x0) = 2x0, [=](x0, x1) = 4x0 + 4x1, [xor](x0, x1) = 2x0 + 2x1 orientation: not(x) = 2x >= 2x = xor(x,true()) implies(x,y) = 6x + 2y >= 6x + 2y = xor(and(x,y),xor(x,true())) or(x,y) = 7x + 6y + 1 >= 6x + 6y = xor(and(x,y),xor(x,y)) =(x,y) = 4x + 4y >= 2x + 4y = xor(x,xor(y,true())) problem: not(x) -> xor(x,true()) implies(x,y) -> xor(and(x,y),xor(x,true())) =(x,y) -> xor(x,xor(y,true())) Matrix Interpretation Processor: dim=1 interpretation: [and](x0, x1) = 4x0 + 4x1, [true] = 0, [implies](x0, x1) = 5x0 + 4x1, [not](x0) = x0, [=](x0, x1) = x0 + x1 + 1, [xor](x0, x1) = x0 + x1 orientation: not(x) = x >= x = xor(x,true()) implies(x,y) = 5x + 4y >= 5x + 4y = xor(and(x,y),xor(x,true())) =(x,y) = x + y + 1 >= x + y = xor(x,xor(y,true())) problem: not(x) -> xor(x,true()) implies(x,y) -> xor(and(x,y),xor(x,true())) Matrix Interpretation Processor: dim=1 interpretation: [and](x0, x1) = 2x0 + x1, [true] = 0, [implies](x0, x1) = 6x0 + x1 + 1, [not](x0) = x0, [xor](x0, x1) = x0 + 4x1 orientation: not(x) = x >= x = xor(x,true()) implies(x,y) = 6x + y + 1 >= 6x + y = xor(and(x,y),xor(x,true())) problem: not(x) -> xor(x,true()) Matrix Interpretation Processor: dim=3 interpretation: [0] [true] = [1] [0], [1 0 0] [1] [not](x0) = [0 0 0]x0 + [0] [0 0 0] [1], [1 0 0] [1 0 0] [xor](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 1 0] orientation: [1 0 0] [1] [1 0 0] [0] not(x) = [0 0 0]x + [0] >= [0 0 0]x + [0] = xor(x,true()) [0 0 0] [1] [0 0 0] [1] problem: Qed