YES

Problem:
 +(-(x,y),z) -> -(+(x,z),y)
 -(+(x,y),y) -> x

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [+](x0, x1) = x0 + 2x1 + 2,
   
   [-](x0, x1) = x0 + 2x1 + 1
  orientation:
   +(-(x,y),z) = x + 2y + 2z + 3 >= x + 2y + 2z + 3 = -(+(x,z),y)
   
   -(+(x,y),y) = x + 4y + 3 >= x = x
  problem:
   +(-(x,y),z) -> -(+(x,z),y)
  Matrix Interpretation Processor: dim=3
   
   interpretation:
                  [1 0 1]     [1 0 0]  
    [+](x0, x1) = [0 0 0]x0 + [0 1 0]x1
                  [0 0 1]     [1 0 0]  ,
    
                  [1 0 0]     [1 0 0]     [0]
    [-](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0]
                  [0 0 1]     [0 0 0]     [1]
   orientation:
                  [1 0 1]    [1 0 0]    [1 0 0]    [1]    [1 0 1]    [1 0 0]    [1 0 0]    [0]              
    +(-(x,y),z) = [0 0 0]x + [0 0 0]y + [0 1 0]z + [0] >= [0 0 0]x + [0 0 0]y + [0 0 0]z + [0] = -(+(x,z),y)
                  [0 0 1]    [0 0 0]    [1 0 0]    [1]    [0 0 1]    [0 0 0]    [1 0 0]    [1]              
   problem:
    
   Qed