YES

Problem:
 f(s(X),Y) -> h(s(f(h(Y),X)))

Proof:
 Matrix Interpretation Processor: dim=3
  
  interpretation:
                 [1 1 0]     [1 0 0]  
   [f](x0, x1) = [0 0 0]x0 + [0 0 0]x1
                 [0 0 0]     [0 0 0]  ,
   
             [1 0 0]     [0]
   [s](x0) = [0 0 0]x0 + [1]
             [0 0 0]     [0],
   
             [1 0 0]  
   [h](x0) = [0 0 0]x0
             [0 0 0]  
  orientation:
               [1 0 0]    [1 0 0]    [1]    [1 0 0]    [1 0 0]                   
   f(s(X),Y) = [0 0 0]X + [0 0 0]Y + [0] >= [0 0 0]X + [0 0 0]Y = h(s(f(h(Y),X)))
               [0 0 0]    [0 0 0]    [0]    [0 0 0]    [0 0 0]                   
  problem:
   
  Qed