YES

Problem:
 plus(s(X),plus(Y,Z)) -> plus(X,plus(s(s(Y)),Z))
 plus(s(X1),plus(X2,plus(X3,X4))) -> plus(X1,plus(X3,plus(X2,X4)))

Proof:
 KBO Processor:
  weight function:
   w0 = 1
   w(plus) = w(s) = 0
  precedence:
   s > plus
  problem:
   
  Qed